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Which characteristic will be affected by increasing the speed of an object from 30 mph to 40 mph?

gravitational attraction

weight

kinetic energy

mass

**Answer:**

Kinetic energy

**Explanation:**

Kinetic energy of an object is directly proportional to the square of its speed (or velocity). An increase in speed will increase the kinetic energy.

Jimmy launches his rocket straight up with an initial velocity of 25 m/s.a. What is the velocity as the rocket reaches maximum height?b. How long will it take the rocket to reach its maximum height?

Given that the initial velocity is u = 25 m/s.

We have to find the final velocity and time at its maximum height.

First, we need to find the maximum height.

[tex]h\text{ =}\frac{u}{2g}[/tex]Here, g = 9.81 m/s^2 is the acceleration due to gravity.

Substituting the values, the height will be

[tex]\begin{gathered} h=\text{ }\frac{25}{2\times9.81} \\ =1.274\text{ m} \end{gathered}[/tex](a) Let the final velocity be v.

The formula to calculate final velocity is

[tex]\begin{gathered} v^2=u^2-2gh^{} \\ v=\sqrt[]{u^2-2gh^{}} \end{gathered}[/tex]Substituting the values, the final velocity will be

[tex]\begin{gathered} v=\sqrt[]{\lbrack(25)^2-(2\times9.81\times1.274)\rbrack} \\ =\sqrt[]{600.01} \\ =24.49\text{ m/s} \end{gathered}[/tex](b) The time taken can be calculated by the formula,

[tex]\begin{gathered} t=\frac{v-u}{-g} \\ =\frac{24.49-25}{-9.81} \\ =0.051\text{ s} \end{gathered}[/tex]Thus, the final velocity is 24.49 m/s and time is 0.051 s

When you drop a 0.36 kg apple, Earth ex- erts a force on it that accelerates it at 9.8 m/s² toward the earth's surface. According to New- ton's third law, the apple must exert an equal but opposite force on Earth. If the mass of the earth 5.98 x 1024 kg, what is the magnitude of the earth's acceleration toward the apple? Answer in units of m/s². Answer in units of m/s^2

The** magnitude** of the** earth's acceleration** toward the apple is** 5.7x10^-25 m/s^2**

Given:

Mass if the apple **(m)**= **0.36**

Mass of the earth **(M)**=**5.98x10^24**

Gravitational acceleration **(g)**= **9.8**

we know that the formula is:

**Ma=mg**

So, according tot the formula

a=(m/M)g

=(0.36/5.98x10^24)9.8

=**5.7x10^-25 m/s^2**

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At room temperature, most metals are

A. Solids

B. Liquids

C. Gases

D. Plasma

**Answer:**

A. Solids

**Explanation:**

only Mercury is liquid soo .... solid

During which season does the north pole experience constant sunlight?

A. spring

B. winter

C. summer

D. autumn

During the summer **season**, the **north **pole gets constant sunlight.

In the summer **season**, the **north **pole experience constant sunlight. Because in the summer the shadows are short and the sun remains higher in the sky. In the summertime, the sun remains above the horizon at the **north **pole which circles the pole every day.

In the summer the sun's rays reach the **north **pole while in winter **season** the **north** pole is tilted away from the incoming sunshine. Mostly the regions of the **north **pole remain cold because the sunlight does not directly fall on the **north **pole. At the **north** pole, there are only two types of seasons, one is summer and the other is winter **season**. The annual average temperature of the winter **season** at the **north** pole is -40 degrees Celsius while in summer **season** the average temperature is 32 F.

So we can conclude that during the months of the summer **season **the **north **pole gets maximum sunlight.

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1) speed of bob?2)Show calculation for the speed of the bob:(write formula first, then insert value with unit, then find the result with unit)

Speed of bob:

[tex]\begin{gathered} \omega=2\pi f \\ _{\text{ }}where\colon \\ f=\frac{1}{T} \\ \omega=\frac{2\pi}{T} \end{gathered}[/tex]so:

[tex]\begin{gathered} \omega=\frac{2\pi}{1.293} \\ \omega=4.83\frac{rad}{s} \end{gathered}[/tex][tex]\begin{gathered} v=\omega\cdot r \\ so\colon \\ v=4.83\cdot0.22 \\ v=1.06\frac{m}{s} \end{gathered}[/tex]

7. Determine the resistance of a lamp that draws 3 amperes when connected to a120-volt supply

A lamp draws **3** amperes of current and is connected to a **120** volt supply.

We are asked to find the resistance of the lamp.

Recall the Ohm's law is given by

[tex]V=IR[/tex]Where **V** is the voltage, **I** is current, and **R** is the resistance.

Re-arrange the equation for resistance

[tex]R=\frac{V}{I}[/tex]Substitute the given values

[tex]\begin{gathered} R=\frac{120}{3} \\ R=40\; \Omega \end{gathered}[/tex]Therefore, the resistance of the lamp is **40** ohms.

a hydraulic lift requires a minimum effort force of 14.4N to lift a patient of a mass 82kg .How much is the effort piston area if the resistance piston has an area of 1.2m²

The output force of a hydraulic lift is given by:

[tex]F_2=\frac{A_2}{A_1}F_1[/tex]In this case we need to lift a patient of mass 82 kg, that means that the lifting force has to be equal to:

[tex]F_2=82\cdot9.8=803.6[/tex]Now that we know that we plug the values given, in this case we have:

[tex]\begin{gathered} 803.6=\frac{1.2}{A_1}(14.4) \\ A_1=\frac{1.2}{803.6}(14.4) \\ A_1=0.022 \end{gathered}[/tex]**Therefore the area of the effort piston is 0.022 squared meters (rounded to three decimal).**

Graphing is a way to represent data visually to represent the motion of a rolling ball students craft data on A-line graph which of the following would accurately label the X ax

Such an object lacks a velocity since it lacks a **slope**. Such an object must have a **variable **velocity. It's quickening.

Starting off, let's graph a few instances of motion with **constant speed**. The graph on the right shows three alternative curves, each with a zero initial point. The first thing to note is how **straight **each graph is. (On a **graph**, a curve can be any type of line that is drawn.

It is not possible to determine the velocity from a **position**-**time** **graph's **slope when the graph is curved. Only straight lines have slope as a characteristic. Such an object lacks a velocity since it lacks a **slope**. Words like "the" and "a" are highlighted in this text to emphasize that there isn't a single **velocity **for these conditions. Such an object must have a variable velocity. It's quickening.

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A water bed that is 1.5 m wide and 2.5 m long weighs 1055 N. Assuming the entire lower surface of the bed is in contact with the floor, what is the pressure the bed exerts on the floor?

a.

250 Pa

c.

270 Pa

b.

260 Pa

d.

280 Pa

D

P=F/A

A=1.5*2.5= 3.75m^2

P= 1055/3.75 = 281Pa

P=F/A

A=1.5*2.5= 3.75m^2

P= 1055/3.75 = 281Pa

The double-sided mirror would produce virtual image to which objects? A)1,2 and 4 B)1,2 and 3 C)3 and 5 D)4 and 5

**Objects 3 and 5.**

Virtual images are always formed by convex mirrors and are formed by concave mirrors when the object is placed in front of f.

Explain how this sand dune was created using the words weathering, erosion, and deposition.

PLSSS HELPP

By abrasion, the **sediment** in the wind promotes **erosion**. The wind scatters sand, **sand** **dunes** created. When **clay** and silt are deposited by the wind. The presence of **vegetation** ground helps stop **wind** erosion.

Earthen materials were worn away during **erosion**, a geological process in which they are moved by water or wind. **Weathering**, a related process that does not involve **movement**, dissolves and breaks down rock.

The process through which the Earth's surface ages is known as **erosion**. **Natural forces** like wind or glacier ice can create erosion. But when it comes to altering the Earth, nothing compares to a slow, constant movement of water, as anyone who has ever seen a picture of a Grand **Canyon **will attest.

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A= 1/2 W (R+S) for W

The change of the **subject **in the **formula **is given by; W = 2A/(R + S)

When we have a **formula**, each of the components of the formula are the **parameters **of the formula. In this case, we have a formula that says A= 1/2 W (R+S). The parameters that are in this formula are A, W, R and S.

According to the question, we have been asked to make W the **subject **of the formula.

The** first step **is to multiply both sides by 2

2A = W(R + S)

And **secondly**, we divide both sides by the sum of R and S and we have;

W = 2A/(R + S)

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A particular cookie provides 54.0 kcal of energy. An athlete does an exercise that involves repeatedly lifting (without acceleration) a 103-kilogram weight 2.45-decimeters above the ground with an energy efficiency of 25%. How many repetitions of this exercise can the athlete do with the energy supplied from one of these cookies?

The maximum quantity of **repetitions** that the athlete could complete with their current level of energy was 229 for such a workout.

**Energy efficiency** is the ratio of input power to energy output. As just a result, a cookie contains 54.0 kcal in calories. An athlete utilizes the 54.0 kcal in just this cookie for input energy.

The following formula could be employed to measure efficiency:

Energy intake minus power generated is efficiency.

Efficiency = output energy / **input energy**

After rearrangement above equation.

**output energy** = efficiency × input energy

Put the given data in above equation.

Output energy = 0.25 × 54 kcal = 13.5 kcal.

Again for **power capacity,** the lifting exercise was already carried out n times. The source of total output energy is mgh within the form of electromagnetic potential.

So, Energy per repetition = mgh

Where, m will represent mass g will represent gravity h is height.

By entering the data provided above.

**Energy per repetition **= 103 kg × 9.8 m/[tex]s^{2}[/tex] × (2.45 × 0.1m)

Energy per repetition= 247.303 J

Energy per repetition = 0.059 kcal.

So, quantity of repetitions = overall output energy / energy per repetition

quantity **of repetitions** = 13.5 kcal / 0.059 kcal

quantity of repetitions will be equal to 229 repetitions.

Therefore, the quantity of repetition would be be 229.

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The potential energy for a mass on a spring is proportional to the square of which of these quantities?

A. mass

B. frequency

C. displacement

E. period displacement velocity

**Answer:**

C. Displacement

**Explanation:**

How do I find if the dog is accelerating or not?

We will have the following:

* The dog walks at a constant speed of 1 m/s in a straight line east. **[Not accelerating]**.

* The dog speeds up from 1 m/s to 7 m/s as he runs away from a cat that scared him. **[Accelerating]**.

* The dog walks at a constant speed of 0.5 m/s in a circle around a bowl of food. **[Not accelerating]**.

* The dog stand in one spot on his bed. **[Not accelerating]**.

* The dog slows down to a stop as he approaches the fence at the edge of the yard. **[Accelerating]**.

what happens to the temperature of the car brake when a driver brake decelerate quickly

**Answer:**

This reduces the kinetic energy of the vehicle, slowing it down and causing the temperature of the brakes to increase. Decelerating from very high speeds too quickly can cause a number of problems: The brakes could overheat and the material they are made from could shatter.

A cell of a constant e. m.f is connected in series with a parallel arrangement of 8ohms coil and a uniform wire of length (Lcm). The total external resistance in the circuit is found to be 6ohms. calculate the resistance of the wire and its length. Resistivity of the wire material = 6.0×10^-5 ohm/meter, cross-sectional area of the wire = 6.0×10^-3cm².

The resistance of the wire will be **24ohm** and the length of the wire will be** 24×10⁴cm.**

As given in the question,

**Rₜₒₜₐₗ **= 6ohm

**Resistivity **= 6×10⁻⁵ohm/m = 6×10⁻⁵/100ohm/cm

Area(A)= 6×10⁻³cm²

Let R = resistance of the wire, therefore;

Rₜₒₜₐₗ = R×8 / R+8

6 = R×8 / R+8

6R + 48 = 8R

48 = 2R

R = **24ohm**

R = 24ohm

we know that **resistance **(R)=rho×l/A

Therefore,

rho×l/A = 24

6×10⁻⁵/100 × l/6×10⁻³ = 24

10⁻⁴ × l = 24

l = **24×10⁴cm**

So, the resistance of the wire will be R=24ohm and the length of the **wire **will be 24×10⁴cm.

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A helium balloon has a volume of 8.89 liters, or 0.00889 cubic meters. Air has a density of 1.29 kilograms per cubic meter, and helium has a density of 0.177 kilograms per cubic meter.a. What is the weight of the helium inside the balloon?b. What is the buoyant force exerted on the balloon?c. What is the net force on the balloon? Neglect the weight of the rubbery material that comprises the actual balloon. . How many identical balloons would be needed to lift a child of mass 24.9 kilograms?

**Given:**

The volume of a helium balloon: 8.89 liters or 0.00889 cubic meters

The density of helium: 0.177 kilograms per cubic meters

The density of the air: 1.29 kilograms per cubic meters

**To find:**

a) weight of the helium inside the balloon.

b) the buoyant force exerted on the balloon.

c) the net force on the balloon.

d) number of identical balloons needed to lift a child of mass 24.9 kilograms.

**Explanation:**

**a)**

The expression for the density of the balloon is:

[tex]Density\text{ of helium=}\frac{Mass\text{ of helium}}{Volume\text{ of helium}}[/tex]Rearrange the above expression to find the mass of the helium.

[tex]Mass\text{ of helium=Density of helium}\times Volume\text{ of helium}[/tex]Substitute the values from the given data, we get:

[tex]\begin{gathered} Mass\text{ of helium=0.177}\frac{kg}{m^3}\times0.00889\text{ m}^3 \\ Mass\text{ of helium=0.001573 kg} \end{gathered}[/tex]Thus, the mass of the helium is 0.001573 kg.

The weight of an object is the product of its mass and gravitational acceleration. Thus, the weight of helium is

[tex]\begin{gathered} Weight\text{ of helium=mass of helium}\times g \\ \end{gathered}[/tex]here, g is the acceleration due to gravity.

Substitute the values, and we get:

[tex]\begin{gathered} Weight\text{ of helium=0.001573 kg }\times9.8\text{ }\frac{m}{s^2} \\ Weight\text{ of helium=0.01542 N} \end{gathered}[/tex]The weight of helium is 0.001542 Newtons.

**b)**

The expression for buoyant force is:

[tex]F=\rho gV[/tex]here, ρ is the density, g is the acceleration due to gravity and V is the volume.

To find the buoyant force exerted by helium on the balloon, substitute the values for helium in the above equation.

[tex]\begin{gathered} F=0.177\text{ }\frac{kg}{m^3}\times9.8\text{ }\frac{m}{s^2}\times0.00889\text{ m}^3 \\ F=0.01542\text{ }\frac{kg\cdot m}{s^2} \\ F=0.01542\text{ N} \end{gathered}[/tex]The buoyant force exerted on the baloon is 0.01542 Newtons.

**c) **

The buoyant force exerted by the balloon is 0.01542 N and it acts in an upward direction. Whereas, the other force acting on the balloon is the force due to gravity, the weight of the balloon. The weight of the balloon is 0.01542 N and is always acts in the downwards direction.

Since the magnitude of buoyant force exerted on a balloon is equal to the weight of the balloon. Both these forces are acting in opposite directions. Thus the net effect will be zero.

[tex]\begin{gathered} F_{net}=F-W \\ F_{net}=0.01542\text{ N -0.01542 N} \\ F_{net}=0\text{ N} \end{gathered}[/tex]Thus, the net force acting on the balloon is 0 Newtons.

**d)**

For a helium balloon, 1 liter of helium can lift 1 gram of mass.

The mass of the child is 24.9 kg = 24900 grams.

Thus, to lift a child of mass 24900 grams, 24900 liters of helium is required.

Now, one balloon contains 8.89 liters of helium, thus for 24900 liters of helium volume, the number of ballons required will be,

[tex]\frac{1\text{ balloon}}{n\text{ balloons}}=\frac{8.89\text{ liters}}{24900\text{ liters}}[/tex]Rearranging above equation to find n, we get

[tex]\begin{gathered} n\text{ balloons = }\frac{24900}{8.89} \\ n\text{ balloons = 2800.89} \end{gathered}[/tex]Thus, approximately 2801 helium balloons are required to lift a child of mass 24.9 kg.

**Final answer**:

**a) The weight of helium is 0.001542 Newtons.**

**b) The weight of helium is 0.001542 Newtons.**

**c) The net force acting on the balloon is 0 Newtons.**

**d) Approximately 2801 helium balloons are required to lift a child of mass 24.9 kg.**

How do we meet the needs of humanity in a sustainable way

We can fulfill the need of **humanity **by providing them jobs, resources, clean water, good energy, and electricity and by providing many facilities.

We can sustain our need for **humanity **in many ways which are given below.

First of all, we need to decrease the rate of poverty and hunger to make **humanity **prosperous. We should provide jobs for those people who are free. We should provide good hospitals and a well-planned health system. We should provide a good and quality education system for the improvement of **humanity**. Provide clean water and make ways for sanitation. We should provide affordable and clean energy to **humanity **which should be cheap but not expensive. We should work decently together and provide resources for economic growth. We should sustainably develop our countries because developing involves satisfying the needs of the present population without endangering the capability of the future population to satisfy its own needs.

So we can conclude that providing jobs, resources, clean water, good energy, and electricity, and many facilities to **humans **is the help of **humanity**.

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Can anyone tell me the final displacement of the puck

The final **displacement **of the puck is 4.14i + 14.14j

**Displacement** is the change in position of an object.

Since for the first **displacement **of the puck from the goal is 20 m at 45°, we have that its** displacement **vector is d = (20cos 45°)i + (20sin45°)j.

= (20 × 0.7071)i + (20 × 0.7071)j.

= 14.14i + 14.14j

Also, for the second **displacemen**t is 10 m to the left. Its displacement vector is d' = -10i

So, we see that the total **displacement** is D = d + d'

So, adding the displacements, we have D = d + d'

= 14.14i + 14.14j + (-10i)

= 14.14i - 10i + 14.14j

= 4.14i + 14.14j

So, we see that the final **displacement **of the puck is 4.14i + 14.14j

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I don't know what I'm doing wrong I just can't seem to get the answers right. Help please.

The **current **and **potential difference **in the lumped element model of **electrical circuits** are dealt with by **Kirchhoff's circuit laws**, which are two equalities. German scientist Gustav Kirchhoff published the first account of them in 1845. This was done before James Clerk Maxwell and generalized Georg Ohm's work.

Because the sum of the currents entering and leaving the junction is equal, **Kirchhoff's first law** is based on the **conservation of charge**. The algebraic sum of potential drops in a closed circuit must equal zero, according to **Kirchhoff's second law**. Therefore, it is based on **energy conservation.**

A stream of charged particles—such as **electrons **or ions—moving through a **conductor **for electricity or into empty space is known as an **electric current**. It is determined by measuring the net rate of **electric charge **flow through a surface or into a control volume.

The amount of **resistance **in an electrical circuit represents the resistance to current flow. The Greek letter **omega **(**Ω**), which stands for **resistance**, represents **ohms**.

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Many scientists believe the solar system formed _______________ago

**Answer:**

4.6/4.5 billion years ago

**Explanation:**

What is the equation for the X axis of this fbd? Remember the sign of convention discussed in the module

Answer:

F - f = ma

Explanation:The** sum of forces on the x-axis** = ma (since it is not stated that the forces are in equilibrium)

**By resolving the Free Body**

Simplifying the equation above, we have:

**F - f = ma**

A ball is thrown downwards from a height of 25m with an initial velocity of 10 m/s.

Find the velocity of the ball just before it hits the ground.

•V₁=10mls

h=25m

The **velocity **of the ball just before it hits the ground is 24.29m/s.

**What is acceleration due to gravity?**

The acceleration an object experiences as a result of gravitational force is known as **acceleration due to gravity**. M/s2 is its SI unit. Its vector nature—which includes both magnitude and direction—makes it a quantity. The unit g stands for gravitational acceleration. At sea level, the standard value of g on earth's surface is 9.8 m/s2.

Given:

Initial velocity u = 10m/s

height h = 25m

we know that the **acceleration due to gravity** g is : 9.8m/s

Therefore using the formula,

v² - u² = 2gs where s is the height in this case and v is the final velocity.

v² - 10² = 2 x 9.8 x 25

=> v² = 490 + 100

=> v = √590

=> v = 24.29m/s

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7 The distance-time graph for a motorcyclist riding off from rest is shown in Figure 1.2.18.

a Describe the motion.

b Calculate how far the motorbike moves in 30 seconds.

c Calculate the speed.

The **distance **travelled by the motorbike is** 600 m** and the **speed **of the motorbike is **20 m/s.**

The **motion **of the motorbike can be described as **linear **type of **motion **since the distance travelled by the motorbike increases with increase in the time of motion.

There is directly **linear **relationship between the distance travelled by the motorbike and the time of motion of the motorbike.

The **distance **travelled by the motorbike is calculated as follows;

from the given graph, at time 30 seconds, the corresponding the **distance **of the motorbike on the vertical axis is 600 m.

distance = 600 m

The **speed **of the motorbike is calculated as follows;

v = d/t

v = 600 m / 30 s

v = 20 m/s

Thus, the **motion **of the motorbike is a **linear **type of motion, the **distance **travelled by the motorbike increases with increase in the time of motion and the **speed **of the motorbike depends on the **distance **and time of motion.

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What is the range of motion(far,medium,or short) in these state of matters:

Neon:

Argon:

Oxygen:

Water:

thank you!

Water is your answer

The question is in the attached image:)

No count number what time of the 12 months it's far, the **northern and the southern hemisphere **will usually revel in a season** contrary to the other. **

Therefore, if the **northern hemisphere** has the **summer time**, then the southern hemisphere will revel in the **wintry weather season**. When we are saying contrary we additionally suggest that once it's far sp**ring season** in the northern hemisphere, then it's far **autumn season** in the southern hemisphere.

The most **important motive** for this phenomenon is the lean of the **earth on its axis**. Since the earth is tilted slightly, one of the hemispheres will usually get hold of greater and direct rays from the solar. It approach that once the **earth is tilted** in the direction of the solar, then the northern hemisphere gets direct solar rays that are skilled through us because the **summer time.**

During this time the southern hemisphere stories the **wintry weather **season. This** phenomenon maintains **alternating because the planet **revolves across the sun**. This summer time lasts for 1/2 of a 12 months, or instead 1/2 of a revolution.

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In (Figure 1) a 6.00-m-long, uniform beam is hanging from a point 1.00 m to the right of its center. The beam weighs 155 N and makes an angle of 30.0∘ with the vertical. At the right-hand end of the beam a 100.0 N weight is hung; an unknown weight w hangs at the left end.If the system is in equilibrium, what is w ? You can ignore the thickness of the beam.

Given::

Length = 6.00 m

Weight of beam = 155 N

Angle = 30.0 degrees

Weight added at the right-end = 100 N

If the system is in equilibrium, let's find the weight, w, at the left-end.

Since the system is in equilibrium, the net torque of the system will be zero.

Now, we have the equation:

[tex](100)(2.00sin30)-w(4.00sin30)-(155)(1.0sin30)=0[/tex]Where w is the weight at the left end.

Let's solve for w.

We have:

[tex]\begin{gathered} (100)(1)-w(2)-(155)(0.5)=0 \\ \\ 100-2w-77.5=0 \\ \\ 100-77.5-2w=0 \end{gathered}[/tex]Solving further:

[tex]\begin{gathered} 22.5-2w=0 \\ \\ 2w=22.5 \end{gathered}[/tex]Divide both sides by 2:

[tex]\begin{gathered} \frac{2w}{2}=\frac{22.5}{2} \\ \\ w=11.25\text{ N} \end{gathered}[/tex]**Therefore, the weight hung at the left end is 11.25 N**

**ANSWER:**

**11.25 N**

A 100 kg man and 50 kg woman on ice

skates stand facing each other. If the

woman pushes the man backwards so that

his final speed is 1 m/s, at what speed

does she recoil?

**Answer:**

First you must find the kinetic energy that aman use to push her;So you can find the speed that she recoil

Find the length of the third side. If necessary, round to the nearest tenth.914
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Reading the data from the given table of crimes per 1,000 residents, in which year did crime increase at all three levels of government?2005200320042008
How many more electrons can fit in the 2nd electron shell compared to the 1st?62810
HELP ASAP ASAPRead the following passage from Anne of Green Gables by Lucy Maud Montgomery. Answer the question that follows the text."Oh, you can talk as much as you like. I don't mind.""Oh, I'm so glad. I know you and I are going to get along together fine. It's such a relief to talk when one wants to and not be told that children should be seen and not heard. I've had that said to me a million times if I have once. And people laugh at me because I use big words. But if you have big ideas you have to use big words to express them, haven't you?""Well now, that seems reasonable," said Matthew."Mrs. Spencer said that my tongue must be hung in the middle. But it isn'tit's firmly fastened at one end. Mrs. Spencer said your place was named Green Gables. I asked her all about it. And she said there were trees all around it. I was gladder than ever. I just love trees. And there weren't any at all about the asylum, only a few poor weeny-teeny things out in front with little whitewashed cagey things about them. They just looked like orphans themselves, those trees did. It used to make me want to cry to look at them. I used to say to them, 'Oh, you POOR little things! If you were out in a great big woods with other trees all around you and little mosses and Junebells growing over your roots and a brook not far away and birds singing in you branches, you could grow, couldn't you? But you can't where you are. I know just exactly how you feel, little trees.' I felt sorry to leave them behind this morning. You do get so attached to things like that, don't you? Is there a brook anywhere near Green Gables? I forgot to ask Mrs. Spencer that.""Well now, yes, there's one right below the house.""Fancy. It's always been one of my dreams to live near a brook. I never expected I would, though. Dreams don't often come true, do they? Wouldn't it be nice if they did? But just now I feel pretty nearly perfectly happy. I can't feel exactly perfectly happy becausewell, what color would you call this?"She twitched one of her long glossy braids over her thin shoulder and held it up before Matthew's eyes. Matthew was not used to deciding on the tints of ladies' tresses, but in this case there couldn't be much doubt."It's red, ain't it?" he said.The girl let the braid drop back with a sigh that seemed to come from her very toes and to exhale forth all the sorrows of the ages."Yes, it's red," she said resignedly. "Now you see why I can't be perfectly happy. Nobody could who has red hair. I don't mind the other things so muchthe freckles and the green eyes and my skinniness. I can imagine them away. I can imagine that I have a beautiful rose-leaf complexion and lovely starry violet eyes. But I CANNOT imagine that red hair away. I do my best. I think to myself, 'Now my hair is a glorious black, black as the raven's wing.' But all the time I KNOW it is just plain red and it breaks my heart. It will be my lifelong sorrow. I read of a girl once in a novel who had a lifelong sorrow but it wasn't red hair. Her hair was pure gold rippling back from her alabaster brow. What is an alabaster brow? I never could find out. Can you tell me?""Well now, I'm afraid I can't," said Matthew, who was getting a little dizzy. He felt as he had once felt in his rash youth when another boy had enticed him on the merry-go-round at a picnic."Well, whatever it was it must have been something nice because she was divinely beautiful. Have you ever imagined what it must feel like to be divinely beautiful?""Well now, no, I haven't," confessed Matthew ingenuously."I have, often. Which would you rather be if you had the choice-divinely beautiful or dazzlingly clever or angelically good?""Well now, I-I don't know exactly.""Neither do I. I can never decide. But it doesn't make much real difference for it isn't likely I'll ever be either."In a minimum of one paragraph, explain what you learn about these characters from this interaction. Use details from the passage to support your response.
Following the invasion of Algeria in 1830, what did France bring to their African colonies?
How did US pilots contribute to the Allied war effort in Europe during World War II?0 They carried out countless bombing raids on targets in Germany.O They sank ships carrying supplies to Britain and the Soviet Union.They trained British pilots in effectiveair support techniques.They ferried retreating troops between Europe and Great Britain.
The manager of a new restaurant plans on ordering place-mats for the maximum number of diners, which is 279. Suppose the place-mats come in boxes of 24. Write a division expression that could be used to determine the number of boxes he needs to order.\
.question 9a data analyst is using statistical measures to get a better understanding of their data. what function can they use to determine how strongly related are two of the variables?
PLEASE HELP !! When a right triangle with a hypotenuse of 1 is placed in the unit circle, which sides of the triangle correspond to the x- and y-coordinates?
Tricia buys 18 apples for $27. The total cost, c, of the apples is proportional to the number of apples, a, that she buys. How much does one apple cost? Create an equation using c and a to represent the proportional relationship.