By solving the** system of equations**, we can see that the **solutions **are:

(A, B) = (4, 9)

(C, D) = (1, -6).

How to solve the system of equations?Here we have the following **system of equations:**

x^2 - y = 7

y - 5x = -11

If we isolate the **variable **y in both equations, we get:

y = x^2 - 7

y = -11 + 5x

Now we can equate these two to get:

x^2 - 7 = -11 + 5x

now we have a **quadratic equation**, this can be rewritten as:

x^2 - 7 + 11 - 5x = 0

x^2 - 5x + 4 = 0

Using the **quadratic formula**, we will see that the solutions are:

[tex]x = \frac{5 \pm \sqrt{(-5)^2 - 4*1*(4)} }{2*1}[/tex]

Solving that we get:

[tex]x = \frac{5 \pm \sqrt{(9} }{2} \\\\x = \frac{5 \pm 3}{2}[/tex]

So the two solutions for x are:

x = (5 + 3)/2 = 4

x = (5 - 3)/2 = 1

Evaluating the second equation in these x-values we get:

y = -11 + 5*4 = -11 + 20 = 9

y = -11 + 5*1 = -6

Then we have the coordinate pairs: (4, 9) (on the first quadrant) and (1, -6) on the fourth quadrant.

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PLEASE HELP ASAP!! THANK YOU

The mathematical procedure for **splitting big numbers** into more manageable groups or sections is known as **long division**. A difficulty can be solved by breaking it down into manageable parts. Dividends, divisors, quotients, and remainders all exist in long divisions.

Then, **add or subtract 50%** from the **first total** and then, I believe, add (or it might be the other way around) to get your actual total. We would want it because it shouldn't affect the **cost of the first machine.** I'm sorry, but I haven't done any math in a long. use a calculator if necessary

Calculate the total cost of all the items you bought. To calculate the cost price, divide the total cost by the quantity of units purchased. To determine the ultimate price, use the selling price formula: **Cost price + profit margin = selling price.**

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Determine which answer in the solution set will make the equation true.

2p + 9 = 4p − 13

S: {−11, 0, 11, 22}

**Answer:**

11

**Step-by-step explanation:**

If you input the number and then solve, you should get that #=#

2(11)+9=4(11)-13

22+9=44-13

31=31

**Answer: 11**

**Step-by-step explanation: 2(11)+9=4(11)-13, 22+9=44-13, 31=31**

Evaluate the quantity of x cubed minus 2x squared plus 3x minus 7 end quantity divided by the quantity of x minus 1 end quantity period. x squared minus x plus 2 minus 5 divided by the quantity x minus 1 end quantity x squared minus 2x plus 2 minus 9 divided by the quantity x minus 1 end quantity x squared minus x plus 4 minus 9 divided by the quantity x minus 1 end quantity x cubed minus 2x plus 2 minus 5 divided by the quantity x minus 1 end quantity

**Answer:**

**(x^3 + 3x^2 - 2x + 7)/x- 2**

**Expand the numerator in the above expression**

**(x^3 + 5x^2 - 2x^2 + 8x - 10x - 16 + 23)/(x - 2)**

**Rearrange the terms of the numerator in the above expression**

**(x^3 + 5x^2 + 8x - 2x^2 - 10x - 16 + 23)/(x- 2)**

**Factorize the numerator in the above expression**

**[x(x^2 + 5x + 8) - 2(x^2 + 5x + 8) + 23]/(x - 2)**

**Factor out x^2 + 5x + 8**

**[(x -2)(x^2 + 5x + 8) + 23]/(x - 2)**

**Split the fractions**

**(x -2)(x^2 + 5x + 8)/(x - 2) + 23/(x - 2)**

**Divide the common factors**

**(x^2 + 5x + 8) + 23/(x - 2) hope this help btw your welcome**

**Answer:**

The answer is really option A. x^2 - x +2-5/x-1

**Step-by-step explanation:**

I just took the test and got it right :)

find the measure of each angle only need numbers 22, 24, and 26

**22) 68**

**24) 90 **

**26) 158**

The mean birth weights of infants born at an area hospital in the month of Aprill is 128 oz. with a standard deviation of 10.2 oz. Given an interpretation of

this situation.

The distance between each infant's weight when they were bonded in April is the proper interpretation of the **standard deviation** in this situation. And the average weight was 10.20 pounds.

The **variance's** positive **square root** is the** standard deviation**. One of the foundational strategies in statistical analysis is standard deviation. The term "standard deviation," often shortened as "SD," tells us how far a value deviates from the **mean **value. It is represented by the symbol "."

Given that : The mean birth weights of infants born at an area hospital in the month of April is 128 oz. with a standard deviation of 10.2 oz.

So let's look at this and see what the correct interpretation of a standard deviation is, which is the distance between each person's actual way of being born and a braille and the main way it was, which is typically about 10 points two oh. From this, we can deduce what the question Act is. The distance between each infant's weight when they were bonded in April is the proper interpretation of the standard deviation in this situation. And the average weight was 10.20 pounds.

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What is the equation in slope-intercept form of a line that passes through the point (−2, −6) and has a slope of 12?

**Answer:**

y = 12x + 18

**Step-by-step explanation:**

**Equation of line in slope-intercept form: y =mx +b**

Here, m is the slope and b is the y-intercept.

m = 12

Substitute m =12 in the above equation,

y = 12x + b

This line passes through (-2,-6). So, plugin the point in the above equation.

-6 = 12*(-2) + b

-6 = -24 + b

-6 + 24 = b

b = 18

Equation of the line:

[tex]\sf \boxed{\bf y = 12x + 18}[/tex]

Look at question 23 please help! I'm giving out the brainliest!!!!!!

The **expressions **8x²+3(x²+y) and 7x²+7y+4x²-4y are **equivalent** .

In the question ,

two **expressions** are given as

8x²+3(x²+y) and 7x²+7y+4x²-4y .

Simplifying the **first expression **

we get ,

= 8x²+3(x²+y)

= 8x² + 3x² + 3y

adding the like terms , we get

= 11x² + 3y

Simplifying the **second expression**

we get ,

= 7x²+7y+4x²-4y

adding and subtracting the like terms ,

we get

= 11x² + 3y

We can see that both the **expressions** are giving the final answer as 11x² + 3y .

hence , both the expressions are equivalent .

Therefore , the **expressions** 8x²+3(x²+y) and 7x²+7y+4x²-4y are **equivalent **.

The given question is incomplete , the complete question is

Are the** **expressions 8x²+3(x²+y) and 7x²+7y+4x²-4y equivalent ? Explain your reasoning .

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John's commute to work is 20kmhr while Sheri's commute is 500mmin.

Who has the fastest commute to work in mihrif 1.61km=1mi?

By 6.2 miles per hour, Sheri commutes more quickly.

We are given that,

John travels to work = 20km/hr

Sheri travels to work = 500m/min converting this into km/hr we get ,

1.61km/hr or 1 mile

John travels to work at the following rate:

[tex]\frac{20 km}{1 hr} * \frac{1 mile}{1.61km} = 12.42 miles/hr[/tex]

Sheri travels work at the following rate:

[tex]\frac{500m}{1min} *\frac{1km}{1000 m}*\frac{1mile}{1.61km}*\frac{60min}{1hr}=18.63 miles/hr[/tex]

Computing the difference between the two,

18.63 miles/hr - 12.42 miles/hr = 6.21 miles/ hr ≈ 6.2 miles/ hr

thus, by 6.2 miles per hour, Sheri commutes more quickly.

What are **conversions **in maths?

An amount that is multiplied or divided between one set of units and another is known as a **conversion **factor. In the event that a **conversion **is necessary, it must be carried out with the proper **conversion **factor to produce an equivalent value. For instance, when translating between inches and feet, 12 inches equals one foot.

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Jesse recorded a temperature of 75 degrees Fahrenheit this morning for science class. The temperature increased by 4 1/2 degrees Fahrenheit in the afternoon, before decreasing 2.6 degrees Fahrenheit in the evening. What was the temperature in the evening?

The **temperature** in the evening is 79.5 degrees **Fahrenheit.**

The area of mathematics known as **algebra **aids in the representation of issues or circumstances into mathematical statements. Creating a meaningful mathematical expression, it requires variables like x, y, and z as well as mathematical operations like **addition**,** subtraction**, **multiplication**, and **division**. Algebra is used in all areas of mathematics, including **coordinate geometry**,** calculus**, and **trigonometry**. 2x + 4 = 8 is a basic algebraic expression.When operations like addition, subtraction, multiplication, division, etc. are performed on variables and constants, we obtain algebraic expressions as the mathematical statement.

Jesse recorded a temperature in the morning of 75 degrees Fahrenheit

The temperature increased by [tex]4\frac{1}{2}[/tex] degrees Fahrenheit in the afternoon

75 + [tex]4\frac{1}{2}[/tex] =[tex]\frac{159}{2}[/tex]

=79.5 degrees Fahrenheit

Before decreasing by 2.6 degrees Fahrenheit in the evening. The temperature in the evening is 79.5 degrees Fahrenheit.

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Jamie is 5 years older than her sister amy. If the sum of their ages is 19. how old is Jamie?

Considering the age of Amy and sum of their ages, Jamie is **12 years old. **

Let the age of Amy be x years. Thus, the age of Jamie be (x + 5) years. Forming equation as per the age -

x + x + 5 = 19

Performing **addition** on Left Hand Side of the equation

2x + 5 = 19

Shifting 5 to Right Hand Side of the equation

2x = 19 - 5

Performing **subtraction** on Right Hand Side of the equation

2x = 14

Shifting 2 to Right Hand Side of the equation

x = 14 ÷ 2

Performing **division** to Right Hand Side of the equation

x = 7

The age of Amy = 7 years

The age of Jamie = 7 + 5

Performing **addition**

The age of Jamie = 12 years

Thus, the age of Jamie is **1****2**** ****years ****old.**

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(X) 1.10.PS-7

Simplify the expression. Write the answer in scientific notation.

(7×10¯²) (9×10¯²)

(7×10¯²) (9×10¯²) = ¯

(Simplify your answer. Use scientific notation. Use the multiplication symbol in the r

Enter you

The **scientific notation **is** 6.3 × **[tex]10^{-3}[/tex]

The expression is ( 7 ×[tex]10^{-2}[/tex] )( 9 × [tex]10^{-2}[/tex])

Calculate the product or quotient

=63 × ([tex]10^{-2}[/tex] ×[tex]10^{-2}[/tex])

Simplify using the** exponent rule **with the same base [tex]a^{n} . a^{m}[/tex]** = **[tex]a^{n + m}[/tex]

=63 × [tex]10^{-2-2}[/tex]

=63 ×[tex]10^{-4}[/tex]

= 6.3 × [tex]10^{-3}[/tex]

Therefore the scientific notation is 6.3 ×[tex]10^{-3}[/tex].

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F(x)=3x^2-4x+8G(x)=2x-5 use the functions above to find the value of g(f(-2)) I don’t understand how to do this

**Given,**

To find **g(f(-2)). **we first find the value of **f(-2).**

The value of **f(-2) **is,

So now to find the value of **g(f(-2)),**

So the value of **g(28) **is,

So the value of **g(f(-2)) **is **51.**

A straight road makes an angle of 15 degrees with the horizontal. When the angle of elevation of the sun is 57 degrees, a vertical pole at the side of the road casts a shadow 75 feet long directly down the road, as shown in the figure. Approximate the length of the pole. Round to the nearest hundredth.

The **length **of the pole is 19.15 **feet.**

The **angle of elevation** is the **angle **created when an observer looks at an object placed above its height in relation to the eye level or the horizontal line. An angle of elevation is, for example, the angle created between the **line of sight **and the horizontal line when a man on **Earth **observes the** Sun**.

Given:

Angle made by straight road = 15°

Angle of elevation of the sun = 57°

Length of the shadow = 75 feet

∠ACB = 90° - 57° = 33°

∠CAB = 57° - 15° = 42°

Using** Sine Law** to find BC i.e.**length** of the pole.

[tex]\frac{BC}{sin A} = \frac{AB}{sin C}[/tex]

[tex]\frac{BC}{sin 42} = \frac{75}{sin 33}[/tex]

[tex]BC= \frac{75sin 42}{sin 33}[/tex]

BC ≅ 19.15 feet (to the nearest hundredth.)

Hence, the approximate length of the pole is 19.15 **feet.**

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a binomial experiment with probability of success and trials is conducted. what is the probability that the experiment results in exactly successes? do not round your intermediate computations, and round your answer to three decimal places. (if necessary, consult a list of formulas.)

The **probability **that the **experiment **results in exactly **successes **is; [tex]P(X =x) = \: ^nC_xp^x(1-p)^{n-x}[/tex]

Binomial **distributions **consist of n **independent **Bernoulli trials.

Bernoulli **trials **are those trials that end up randomly either on success (with probability p) or on failures( with **probability **1- p = q (say))

Consider that we have **random variable **X about **binomial **distribution with **parameters **n and p, then it can be written as;

[tex]X \sim B(n,p)[/tex]

The **probability **that out of n **trials**, there be x **successes **is given as;

[tex]P(X =x) = \: ^nC_xp^x(1-p)^{n-x}[/tex]

The **expected value **and **variance **of X are given as:

[tex]E(X) = np\\Var(X) = np(1-p)[/tex]

Hence, the **probability **that the **experiment **results in exact **success **are;

[tex]P(X =x) = \: ^nC_xp^x(1-p)^{n-x}[/tex]

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If the height of a cone is three

times of the radius of the base and its volume is

343 cm³, then find the radius of the base of the cone

As a result, the **cone's volume** is equal to three times its **radius** √343/π .

The word "mensuration" literally means "to measure." It is typically employed when dealing with **geometric** **shapes** when it is necessary to calculate different physical values like **perimeter**, **area**, volume, or length. Mensuration is the term for measuring these amounts.

So with respect to the information provided to us :

Height of a cone =3* **radius** of the base

let height be h and radius be r

h=3r

The Formula for volume of cone is:

V=1/3hπr²

Putting the value we get:

343=1/3*π*r²*3r:

r= √343/π

Therefore ,

the volume of the cone whose height is three times its radius is:

√343/π

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Please look at the image below. This is my homework by the way.The figure shown are congruent. Find a sequence of transformations for the indicated mapping. Give coordinate notation for the transformations you use.

Coordinates of PQRSTU

P = (-2, -6)

Q = (-4, -6)

R = ((-4, -2)

S = (2, -4)

T = (2, -8)

U = (0, -10)

They changed to ABCDEF

A = (4, 4)

B = (2, 4)

C = (2, 8)

D = (8, 6)

E = (8, 2)

F = (6, 0)

**Transformations used = (x + 6, y + 10)**

24. mrs. piatt, the math teacher, has six black, nine yellow and two blue calculators. what is the probability that she will hand out a blue calculator to the first student, then hand out a yellow calculator second?

The likelihood or **probability** that she will give the first student a blue calculator and the second student a yellow calculator is 6.6%.

The math teacher Mrs. Piatt has **six** **black**, **nine** **yellow**, and **two** **blue** calculators.

Therefore, the total number of calculators is 17.

The probability that she hands out a blue calculator to the first student is:

P₁ = Number of blue calculators/ Total number of calculator

P₁ = 2/17

Now, as a calculator is handed out to a student. Then the remaining number of calculators is 16.

Therefore, the **probability** that the second student gets a yellow calculator will:

P₂ = Number of yellow calculators/ Total number of calculators.

P₂ = 9/16

Therefore, the **probability** that she will hand out a blue calculator to the first student, then hand out a yellow calculator second will be:

P = P₁ × P₂

P = 2/17 × 9/16

P = 18/272

P = 0.06617647058

P = 6.6%

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3.if the m∠1 is 57° , find the measure of ∠6.

Show your work

123°

180°-57°=<6=123°

If f(x) = kx^3+ x^2 − kx + 2, find a number k such that the graph of f contains the point (2, 12).

**Answer:**

k = 1

**Step-by-step explanation:**

since the graph contains the point (2, 12 ) then the coordinates of the point make the equation true.

substitute x = 2 and f(x) = 12 into the equation and solve for k

12 = k(2)³ + 2² - k(2) + 2 , that is

12 = 8k + 4 - 2k + 2

12 = 6k + 6 ( subtract 6 from both sides )

6 = 6k ( divide both sides by 6 )

1 = k

A car journey is m

miles long.

One kilometre is equivalent to x

miles.

The car uses one litre of fuel to travel a distance of f

kilometres.

Fuel for the car costs p

pence per litre.

Which of the following expressions gives the cost of fuel for this journey, in pounds?

The expression gives the **cost of fuel** for this journey is option H mp / 100 fx

Given,

The **total distance** of a car journey = m miles

One kilometer = x miles

The amount of petrol needed to travel a distance of f kilometers = 1 liter

**Cost of the fuel** = p pence/ liter

Now we have to find the expression which gives the cost of fuel for this journey in pounds.

1 **pound** = 100 pence

So,

The distance in miles we can travel with 1 liter of petrol = fx

Total liter of petrol needed for the journey = m/fx

Total cost of petrol for the journey = mp / fx100

That is,

The expression gives the **cost of fuel **for this journey is option H mp / 100 fx

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The question is incomplete. Completed question is given below:

A car journey is m miles long.

One kilometre is equivalent to x miles.

The car uses one litre of fuel to travel a distance of f kilometres.

Fuel for the car costs p pence per litre.

Which of the following expressions gives the cost of fuel for this journey, in pounds?

(There are 100 pence in one pound.)

A. 100fmpx

B. 100fmp/x

C. 100mpx/f

D. 100mp/fx

E. fmpx/100

F. fmp/100x

G. mpx/100f

H. mp/100fx

Given mn, find the value of x.

Answer:

(2x+5)° (8x+5)°

Submit Answer

m

00

**Step-by-step explanation:**

2x+(-8x) +5-5

-5=0. u Wii collect like terms and if u do that that's the answer if am wrong let me know

Would the image be categorized as a function or as a relation? Use at least one sentence to explain your answer.

**Answer:**

**Step-by-step explanation:**

The attached graph is **NOT a function**, since it doesn't pass the **vertical line test**.

If a vertical line cuts the graph more than once, then this relation is not a function.

If f(x) = (x-4)(x+3), determine the x-intercepts of each function.

a) y=f(x)

b) y=-2f(x)

c) y=f(-1/2x)

d) y=f(-(x+1))

a) The **x-intercepts **of y=f(x) is (-3,0) (4,0)

b) The x-intercepts of y=-2f(x) is (-3,0) (4,0)

c) The x-intercepts of y=f(-1/2x) is (-1/8,0) (1/6,0)

d) The x-intercepts of y=f(-(x+1)) is (-5,0) (2,0)

A line's x-intercept is the distance in** x coordinates **from the line's **intersection** with the x-axis at its **origin**. A location on the graph where y is 0 is known as the x-intercept. The** x-intercept** of a line that is perpendicular** **to the y-axis is undefined.

Here to determine the x-intercept put y=0,

Given f(x)=(x-4) (x+3)

a) y=(x-4) (x+3)

Replacing y by 0 we get,

(x-4) (x+3) =0

x=-3, 4

Therefore, **x-intercepts **of y=f(x) is (-3,0) (4,0)

b) y = -2(x-4) (x+3)

Replacing y by 0 we get,

-2(x-4) (x+3) =0

x=-3, 4

Therefore, x-intercepts** **of y=-2f(x) is (-3,0) (4,0)

c) y= (-[tex]\frac{1}{2x}[/tex]-4) (-[tex]\frac{1}{2x}[/tex]+3)

Replacing y by 0 we get,

(-[tex]\frac{1}{2x}[/tex]-4) (-[tex]\frac{1}{2x}[/tex]+3) =0

By solving the above equation

(-[tex]\frac{1}{2x}[/tex]-4) =0 and (-[tex]\frac{1}{2x}[/tex]+3) =0

-1/2x=4 and -1/2x=-3

x=-1/8 and x=1/6

Therefore, x-intercepts of y=f(-1/2x) is (-1/8,0) (1/6,0)

d) y=(-(x+1)-4) (-(x+1) +3)

Replacing y by 0 we get,

(-(x+1)-4) (-(x+1) +3) =0

By solving the above **equation**

(-(x+1)-4) =0 and (-(x+1) +3) =0

-(x+1) =4 and -(x+1) =-3

x=-5, 2

Therefore, x-intercepts of y=f(-(x+1)) is (-5,0) (2,0)

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all the students in an algebra class took a 100-point test. five students scored 100, each student scored at least 60, and the mean score was 76. what is the smallest possible number of students in the class?

The** smallest** possible number of students in the algebra class is 13.

Let n≥5 be the number of students.

The sum of their** scores **must be at least 5×100 + (n - 5).

Simultaneously, we must achieve the mean 76, which is equivalent to achieving the** **mean sum** **76n.

As a result, we have a sufficient precondition on n: we should have 5×100 + (n - 5) ≤ 76n.

This can be reduced to 200 ≤ 16n. This is true for the smallest integer n = 13.

To complete our solution, we must now determine how 13 students might have scored just on test.

We have 13×76 = 988 points to distribute to them. Because five 100s equal 500, we must distribute the remaining 488 points as among remaining eight** students. **

This can be accomplished, for example, by awarding each of them 61 points.

Thus, the** **smallest possible number of students in the class is 13.

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Given A-

2 2

1 3

what is A-¹?

The **inverse** of** matrix A** = [tex]\left[\begin{array}{cc}2&2&1&3\\\end{array}\right][/tex] is [tex]A^{-1} = \frac{1}{4}[/tex] [tex]\left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|[/tex]

The given **matrix** is A = [tex]\left[\begin{array}{cc}2&2&1&3\\\end{array}\right][/tex]

The inverse of a matrix is given by

[tex]A^{-1} = \frac{1}{|A|} adjA[/tex] ...(1)

Now, **determinant** of matrix A is

|A| = [tex]\left|\begin{array}{cc}2&2&1&3\\\end{array}\right|[/tex]

= (3)(2) - (2)(1)

= 6 - 2

= 4

Now,** adjoint A** will be

[tex]A_{11}[/tex] = 3

[tex]A_{12}[/tex] = -1

[tex]A_{21}[/tex] = -2

[tex]A_{22}[/tex] = 2

AdjA = [tex]\left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|[/tex]

Now, substituting the values of** |A| **and **AdjA** in equation** (1),** we get

[tex]A^{-1} = \frac{1}{4}[/tex] [tex]\left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|[/tex]

Therefore, [tex]A^{-1} = \frac{1}{4}[/tex] [tex]\left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|[/tex]

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A robot can complete 5 tasks in 3/4 hour. each task is the same. how long does it take the robot to complete one task

The **robot** will take 0.15 **hours** to complete **one task**.

What is the **unitary method** of **problem solving**?

A single unit's value can be determined from the values of multiple units, and multiple units' values can be determined from the values of single units using the **unitary technique**. The **unitary technique** involves first determining the value of a single unit, followed by the value of the necessary number of units. In the **unitary method**, the value of a unit quantity is determined before the values of other units are determined. Direct variation and inverse variation are its two different forms of variations. When there is a direct variation, an increase or decrease in one quantity will result in an equivalent rise or fall in the other. If we increase one quantity in inverse variation, the value of another quantity will drop.

Given, **time** taken by** robot** to **complete five tasks** = 0.75 hours

Thus, **time** taken by **robot** to **complete one task** = (0.75/5) = 0.15 hours

Therefore, the **robot **will take** 0.15 hours** to complete **one task**.

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The population of a city increases by 3.1% per year. If this year's population is

290,000, what will next year's population be, to the nearest individual?

**Answer:**

** the next year population is 122,689 **

**Step-by-step explanation:**

The computation of the next year population is as follows:

= This year population × increase percentage

= 119,000 × (1 + 0.031)

= 119,000 × 1.031

= 122,689

Hence, the next year population is 122,689

The above formula is applied so that the correct value of the population could come

and the same is relevant

PLEASE HURRYYYY

The segment contains points S(a, b) and T(c, d). Which formula should be used to find the midpoint of the segment?

In this case, the formula you would use is (a+c)/2 , (b+d)/2.

In reality, you’re using the midpoint formula. The midpoint formula is as follows:

(x1+x2)/2 , (y1+y2)/2

For example,

If you had point (2,4) and (4,8) you would plug in the equation as follows.

(2,4) = x1,y1

(4,8) = x2,y2

(2+4)/2 , (4+8)/2

6/2 , 12/2

(3,6)

So the midpoint of the two points (2,4) and (4,8) would be (3,6).

In reality, you’re using the midpoint formula. The midpoint formula is as follows:

(x1+x2)/2 , (y1+y2)/2

For example,

If you had point (2,4) and (4,8) you would plug in the equation as follows.

(2,4) = x1,y1

(4,8) = x2,y2

(2+4)/2 , (4+8)/2

6/2 , 12/2

(3,6)

So the midpoint of the two points (2,4) and (4,8) would be (3,6).

The Smith twins, Joe and John, have a car collection.

The number of cars is represented by x.

The number of cars in Joe's collection is 2 times the number in John's collection.

The total number in both is 78. What is x, the number in John's collection?

A. 26 Cars

B. 54 Cars

C. 39 Cars

D. 78 Cars

B. 54 cars because basically I’m right

**Answer:**

**Step-by-step explanation:**

x = 39

C. 39 Cars

If g(x) = -x, for what value of x does

g(x) = -9?

**Answer:**

x = 9

**Step-by-step explanation:**

given g(x) = - x and g(x) = - 9 , the equate right sides

- x = - 9 ( multiply both sides by - 1 )

x = 9

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