A. 256

B. 387

C. 424

D. 532

**Answer:**

B

**Step-by-step explanation:**

387/9 = 43

I have watched 32% of the episodes of my favorite show. I have watched 8 episodes. How many episodes are there?

**Answer:**

There are 35 episodes in the show

Write the given expression as an algebraic expression in x.

cos(2 taninverse (x))

Writing the given **trigonometry **expression: cos(2 tan inverse (x)) as **algebraic expression **gives

Data given in the question are as follows:

cos(2 tan inverse (x))

Using **trigonometry** (double angle formula)

cos 2x = 1 - 2sin² x

when x = tan inverse (x)

cos(2 tan inverse (x)) = 1 - 2sin² tan inverse (x) (1)

cos² x + sin² x = 1

cos² x = 1 - sin² x

cos x = √(1 - sin x)

tan x = sin x / cos x

[tex]tan x = \frac{sinx }{\sqrt{1-sin^{2}x } }[/tex]

squaring all parts of the **trigonometry expression **and clearing the fraction

[tex]tan^{2}x = \frac{sin^{2} x }{1-sin^{2}x }[/tex]

[tex](tan^{2}x) (1-sin^2x) = sin^2x[/tex]

[tex]tan^{2}x-tan^{2}xsin^2x = sin^2x[/tex]

[tex]tan^{2}x = sin^2x+tan^{2}xsin^2x[/tex]

[tex]tan^{2}x = sin^2x(1+tan^{2}x)[/tex]

[tex]sin^2x = \frac{tan^{2}x}{(1+tan^{2}x)}[/tex]

since tan (tan inverse) (x) = x

[tex]1 - 2sin^2 tan^{-1} (x) = 1 - 2x^2 / (1 + x^2)[/tex]

[tex]=\frac{ 1 + x^2 -2x^2}{1+x^2}[/tex]

[tex]=\frac{ 1 -x^2}{1+x^2}[/tex]

Therefore **trigonometry expression **cos(2 tan inverse (x)) gives an **algebraic expression **in the form (1-x²) / (1+x²)

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41 points 3 games how many points 11 games

**Answer:**

33by 11

**Step-by-step explanation:**

in 41 3 games firstly we find 1 point it is 3by41

I think it Can he 451 or Im tripping

Yesterday, grace drove 28 1/2 miles. She used 1 1/4 gallons of gasoline. What is the unit rate for miles per gallon?

**Answer: **22.8 miles or 22 4/5

**Step-by-step explanation:**

To find the unit rate you do

28.5 ÷ 1.25 = 22.8

Need help with absolute value please

**Answer:**

let's say you need to find the absolute value of -5 the answer would be 5.

**Step-by-step explanation:**

Since the distance between -5 and 0 in a number line is 5. This would also be applied If you you were trying to find the absolute value of 5. it would also be 5.

When in math, I figured out negative number's absolute value will always be positive. absolute value numbers of positive numbers will stay the same.

Find the largest of three consecutive odd integers whose sum is 111.

The largest of three consecutive odd** integers** whose sum is 111 is 39

**Positive**, **negative**, and zero are all examples of** integers**. The Latin word "integer" signifies "whole" or "intact." As a result, **fractions** and decimals are not included in integers.

**Odd integers** that follow each other grow (or shrink) by a factor of 2. Consider the numbers 1, 3, and 5. Add two to the** preceding number** to move from one to the following. You don't know where to begin, and that is the issue here. In actuality, you are searching for the least of the three integers, therefore this is your unknown.

x + (x + 2) + (x + 4) = 111

x + x + 2 + x + 4 = 111

3x + 6 = 111

3x = 105

x =[tex]\frac{105}{3}[/tex]

x = 35

35 ,37,39

The **largest** of three **consecutive** odd integers whose sum is 111 is 39

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Geometry ?Use the photo to help me solveTriangle DEF is shown. What is the coordinate of D if triangle D E F is created by dilating DEF with a scale of 0.5 about the origin

Explanation

Since the scaling factor of the dilation (0.5) is fewer than 1, it shrinks (make smaller) the triangle around the origin (zero). Intuitively, the dilation is getting the points of the triangle closer to zero (in a way that preserves the shape of the triangle).

Formally, to know the coordinates of a point of the triangle after the dilation, we just need to multiply the original coordinates of the point by the scaling factor (this works for the dilation is around zero).

The original coordinates of D are

[tex](3,0)\text{.}[/tex]Multiplying them by the scale factor, we get

[tex]0.5\cdot(3,0)=(0.5\cdot3,0.5\cdot0)=(1.5,0)\text{.}[/tex]AnswerThe coordinates of D after the given dilation is

[tex](1.5,0)\text{.}[/tex]How can you use the Power of a Quotient, Quotient of Powers, Zero Exponent Laws Identity Exponent and to evaluate numerical expressions with whole-number exponents?

Whereas working with** laws of exponent**s, when splitting the **exponential equations** with the same** base**, the exponents ought to be subtracted.

Basically, the** Quotient of Powers **rules is used to decrease the number of terms when parts like terms with **exponents**. In order to get the solution, just remove the exponents while dividing the terms with the same** base**, it is applicable to exponents with the same bases. when **powers **are multiplied, for two **whole numbers** of the same bases the exponents are added, whereas when powers are divided for two whole numbers of the same bases, exponents are subtracted. The** zero exponent rule **basically states that when any number is raised to the **power of zero **it results in 1.

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One month Tony rented 5 movies and 3 video games for a total of $32. The next month he rented 2 movies and 12 video games for a total of $83. Find therental cost for each movie and each video game.Rental cost for each movie:Rental cost for each video game:

Let x represent the rental cost for each movie.

Let y represent the rental cost for each video game.

We were told that One month Tony rented 5 movies and 3 video games for a total of 532. This means that

5x + 3y = 32

Also, the month, he rented 2 movies and 12 video games for a total of $83. This means that

2x + 12y = 83

Dividing through by 2, we have

x + 6y = 41.5

x = 41.5 - 6y

Substituting x = 41.5 - 6y into 5x + 3y = 532, we have

5(41.5 - 6y) + 3y = 32

207.5 - 30y + 3y = 32

- 30y + 3y = 32 - 207.5

- 27y = - 175.5

y = - 175.5/- 27

y = 6.5

x = 41.5 - 6(6.5) = 41.5 - 39

x = 2.5

**Rental cost for each movie = $2.5**

**Rental cost for each video game = $6.5**

fill in the missing numbers along the sides of the triangle so that it contains each of the numbers from 4 through 12 exactly once. furthermore each side of the triangle should contain four numbers whose sum is 32the pair of numbers that can be used for A and B is ___. the pair of numbers that can be used for C and D is ____. and the pair of numbers that can be used for E and F is___.

Answer:

**For A and B, we have (10, 6)**

**For C and D, we have (12, 8)**

**For E and F, we have (12, 8)**

Explanation:

To determine the missing numbers along each side of the triangle, we have to

*Add the two numbers at the vertex

*Subtract it from 32

*Divide it by 2

*Add 2 to it to have the 1st number

*Subtract 2 from it to have the 2nd number

So to find the pair of numbers that can be used for A and B, we'll have;

[tex]\begin{gathered} 12+4=16 \\ 32-16=16 \\ \frac{16}{2}=8 \\ 8+2=10 \\ 8-2=6 \end{gathered}[/tex]Therefore the missing numbers for A and B are 10 and 6.

So to find the pair of numbers that can be used for C and D, we'll have;

[tex]\begin{gathered} 4+8=12 \\ 32-12=20 \\ \frac{20}{2}=10 \\ 10+2=12 \\ 10-2=8 \end{gathered}[/tex]Therefore the missing numbers for C and D are 12 and 8.

So to find the pair of numbers that can be used for E and F, we'll have;

[tex]\begin{gathered} 12+8=20 \\ 32-20=12 \\ \frac{12}{2}=6 \\ 6+1=7 \\ 6-1=5 \end{gathered}[/tex]So to avoid repetition of any of the numbers between 4 and 12, we have to add and subtract 1 instead of 2.

what is the value of a in the equation 5a – 10b = 45, when b =3?a)3b)15c)21d)39

SOLUTION

Given the question, the following are the solution steps to answer the question.

**STEP 1: Write the given equation**

**STEP 2: Substitute 3 for b in the equation**

**STEP 3: Simplify the equation to solve for a**

**Hence, the value of a is 15**

what is the product of [tex] ( - \frac{3}{4} ) \times ( - \frac{7}{8} )[/tex]

What is the product of

In the multiplication of fractions, you multiply the numerators with each other and the denominators with each other

( - 3/5) *(-7/8)

= -3*-7 / (5*8) = (positive)

= 21/40

_____________________

**Answer**

**= 21/40**

_____________________

Do you have any questions regarding the solution?

Two trains leave the same station at the same time, one traveling west at a constant speed of 60 miles per hour, the other traveling south at a constant speed of 80 miles per hour. After how long are the two trains exactly 300 miles apart?

After 2.14 **hours** the trains are exactly 300 miles apart.

Two trains leave the same station at the same time, one traveling west at a constant **speed** of 60 miles per **hour**, the other traveling south at a constant **speed **of 80 miles per** hour**.

The time both of them will travel 300 miles can be calculated as follows:

Therefore,

**speed** = distance / time

distance =** speed** × time

The train that travel west:

let

t = time of the train that travel west

distance = 60t

The train that travel south:

distance = 80t

Therefore,

total distance = 60t + 80t

300 = 140t

t = 300 / 140

t = 2.14285714286

**t = 2.14 hours**

Therefore,

time taken = 2.14 **hours**

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The half-life of a radioactive kind of copper is 3 hours. if you start with 2,352 grams of it, how much will be left after 9 hours??

**Answer**:

294 grams

**Explanation**:

The amount of radioactive material left after t hours given that the half-life is to hours is

[tex]A=P(0.5)^{\frac{t}{t_0}}[/tex]Now, in our case t0 = 3, t = 9 and P = 2352 g; therefore, the above equation gives

[tex]A=2352(0.5)^{9/3}[/tex][tex]A=294g[/tex]which is our answer!

**Hence, the amount of radioactive copper left after 9 hours is 294 grams. **

Write the equation of the line with the given information in point-slope form. (-5, 11) and (-2, 1)

**Answer**

**The equation in point-slope form is**

**y - 1 = (-10/3) (x + 2)**

We can then simplify this by multiplying through by **3 **to obtain

**3y - 3 = (-10) (x + 2)**

**3y - 3 = 10x - 20**

**3y = 10x - 20 + 3**

**3y = 10x - 17**

**Explanation**

The general form of the equation in point-slope form is

**y - y₁ = m (x - x₁)**

where

**y = y-coordinate of a point on the line.**

**y₁ = This refers to the y-coordinate of a given point on the line**

**m = slope of the line.**

**x = x-coordinate of the point on the line whose y-coordinate is y.**

**x₁ = x-coordinate of the given point on the line**

We can calculate the slope of the line and then use any of the two points given to serve as the point **(x₁, y₁) **in the equation

For a straight line, the slope of the line can be obtained when the coordinates of two points on the line are known. If the coordinates are **(x₁, y₁)** and **(x₂, y₂)**, the slope is given as

For this question,

**(x₁, y₁)** and **(x₂, y₂) **are **(-5, 11) **and **(-2, 1)**

**x₁ = -5**

**y₁ = 11**

**x₂ = -2**

**y₂ = 1**

**Slope = m = (-10/3)**

Using the point **(-2, 1) **as **(x₁, y₁), **we can write the equation of the line

**y - y₁ = m (x - x₁)**

**y - 1 = (-10/3) (x - (-2))**

**y - 1 = (-10/3) (x + 2)**

We can then simplify this by multiplying through by **3 **to obtain

**3y - 3 = (-10) (x + 2)**

**3y - 3 = 10x - 20**

**3y = 10x - 20 + 3**

**3y = 10x - 17**

**Hope this Helps!!!**

help meeeeeeeeeeeeeeeeeee pleaseeeeeeeee!!!

**Answer:**

I think it is y

**Step-by-step explanation:**

find an equation of the circle that has center (1,-5) and passes through (2,1)

[tex](x-1)^2+(y+5)^2=37[/tex]

**1**) Since the equation of the circle is given by:

And we've been told the Center (1,-5) and one point located at the circumference, (2,1). So let's find the radius, i.e. the distance from the center to any point to the circumference.

**2**) Let's use the Formula for the distance between (1,-5) and (2,1), derived from the Pythagorean Theorem:

**3)** So d = radius, and now we can plug those pieces of information into the formula of the circle:

So we now have the formula for that circle.

**Answer:**

Radius (R) is equal to the distance between the points (-2,1) and (3,1)

R² = (1 - 5)² + (1 - 1)² = (-24)² + 0 = 579

R = 23.16

Convert each slope-intercept or point slope equation into standard form.

y - 3 = 1/5(x + 6)

The **Standard form** of the equation will be;

⇒ x - 5y = -21

**What is Standard form of equation?**

The **standard form** of the equation is defined as;

Ax + By = C

Where, A, B and C are integers.

Given that;

The **equation **in **slope - intercept** form as;

⇒ y - 3 = 1/5 (x + 6)

Now,

We convert the equation in **standard form** as;

Since, The **equation **in slope - intercept form as;

⇒ y - 3 = 1/5 (x + 6)

Change into **standard form** as;

⇒ y - 3 = 1/5 (x + 6)

**Multiply **by 5 both side, we get;

⇒ 5( y - 3) = (x + 6)

⇒ 5y - 15 = x + 6

**Add **15 both side, we get;

⇒ 5y - 15 + 15 = x + 6 + 15

⇒ 5y = x + 21

**Subtract** 21 both side, we get;

⇒ 5y - 21 = x + 21 - 21

⇒ 5y - 21 = x

**Subtract **5y both side, we get;

⇒ 5y - 21 - 5y = x - 5y

⇒ - 21 = x - 5y

⇒ x - 5y = -21

Therefore,

The **Standard form** of the **equation **will be;

⇒ x - 5y = -21

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Whats a ratio for 5ml and 120ml

Step 1:

The ratio for 5ml to 120ml

Step 2:

The symbol of ratio is :

Therefore,

[tex]\begin{gathered} 5ml\text{ ratio 120ml} \\ =\text{ 5 : 120} \\ =\text{ }\frac{5}{120} \\ =\text{ }\frac{1}{24} \\ =\text{ 1 : }24 \end{gathered}[/tex]**Step 3**

**Final answer**

**1 : 24**

a firm uses a trend projection and a seasonal factor to simulate sales for a given time period. it assigns 0 if sales fall 1 if sales are steady 2 if sales rise moderately and 3 if sales rise a lot. the simulator generates the following output

0102000103200002123120203002101

estimate the probability that sales will remain steady. express as a fraction and as a decimal

The **probability** that the sales will will remain steady is; 7/30 or 0.233

We are given the **numbers generated** by the simulator for the sales as;

0, 1, 0, 2, 0, 0, 0, 1, 0, 3, 2, 0, 0, 0, 0, 2, 1, 2, 3, 1, 2, 0, 2, 0, 3, 0, 0, 2, 1, 0, 1

Now, we are given the following implications of the **simulator** as;

Now, we want to find the probability that the sales will will remain steady which is the point at which it assigns 1 from the 30 numbers generated. Thus;

P(sales will remain steady) = 7/30 = 0.233

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8. A car costs $10,500, and you're offered a loan that requires $800 down and a monthly payment of $187.53 for 60 months, how much will you pay in interest? Round your answer to the nearest dollar.$

**The Solution:**

Given that a car that cost $10500 was offered as a loan with a down payment of $800.

This means the loan balance will now be:

[tex]\text{Loan baleance=10500-800= \$9700}[/tex]The loan payment plan is a monthly payment of $187.53 for 60 months.

[tex]\text{Total Payment=187.53}\times60=\text{ \$11251.80}[/tex]We are required to find how much was paid in interest.

We shall take the difference between the total payment and the loan balance.

[tex]\begin{gathered} \text{Interest paid=Total payment-Loan balance} \\ \text{Interest paid=11251.80-9700= \$1551.80}\approx\text{ \$1552} \end{gathered}[/tex]Therefore, **the correct answer is**** $1552**

A. The printer prints the entire report in 152 minutes

B.The printer prints 3 more pages per minutes in colored ink than black ink.

C.The printer prints 3 fewer pages per minute in colored ink than black ink.

D.The printer prints the same number of pages per minute in either type of ink.

**Answer:**

C

**Step-by-step explanation:**

the function calculates the number of pages left to print. that means for every minute it subtracts a number of pages from the total of pages (that total being 152 pages).

the colored print only manages 30 pages per minute, while the pure black ink printing manages 33 pages per minute.

help I'm practicing

**Answer:**

**The total surface area is;**

**Explanation:**

Given the square pyramid as show in the attached image.

The total surface area is the sum of the area of the base square and the area of the four triangles.

[tex]A=l^2+4(\frac{1}{2}lh)[/tex]Given;

[tex]\begin{gathered} l=12\text{ ft} \\ h=8\text{ ft} \end{gathered}[/tex]substituting the given values;

[tex]\begin{gathered} A=l^2+4(\frac{1}{2}lh) \\ A=12^2+4(\frac{1}{2}\times12\times8) \\ A=144+192 \\ A=336\text{ ft}^2 \end{gathered}[/tex]Therefore, **the total surface area is;**

Find X. Circumscribed Angles

The value of of **angle **x of the circumscribing **circle is **x° = 140°

In the above question, the following figure is given, where

The angle inside the **circle **made by the intersection of two **line segments** is = 40°

We need to find the **angle **x made by the angle made by the **tangents **outside the circle

A **line **that touches a curve or a **circle **at one point is said to be **tangent**.

The point of tangency is the intersection of the **tangent **line and the curve.

We'll find the value of of angle x using the theorems of the circumscribing circle.

The sum of opposite **angles **of a circumscribing **quadrilateral **is always 180°

Using this property we can write,

40° + x° = 180°

x° = 180° - 40°

x° = 140°

Hence, the value of of **angle **x using the theorems of the circumscribing **circle is **x° = 140°

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Write the quadratic function in vertex form. Then identify the vertex.

g(x)=x^2+12x+37

The **vertex** **form **is y= (x+ 6)²+1.

The **vertex form **of a quadratic **equation **is y = a (x- h)² + k as opposed to the regular **quadratic **form, which is an x² + bx + c = y. In both cases, the variables that indicate whether the **parabola **is **facing up **(+ a) or **down **( a) are y, the y-**coordinate**, x, and a.

a=1

b=12

c=37

Consider the **vertex form **of a parabola.

a(x+ d)²+e

Now, d= b/2a

d=12/ 2

d=6

and, e= c-b²-4a

e= 37 - (12)²/4x1

e= 37 - 36

e= 1

Then, the **vertex form **is

y = a(x+ d)²+e

y= 1(x+ 6)²+1

y= (x+ 6)²+1

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Kali just started a new sales floor job to save for college. She earns 15.75 plus a flat fee of 50 . She wants to earn between 200 and 400 . The following inequality represents her earning potential

200 ≤ 15.75x + 50 ≤ 400 Solve the inequality PLEASE HELP ASAP

!!

The given** inequality** has the following solution set

9.52 ≤ x ≤ 22.22

If we express this as an **interval**, we get [9.52, 22.22].

Here is the inequality which is Kali's earning potential

200 ≤ 15.75x + 50 ≤ 400

To solve the inequality, we must isolate the **variable** in the center; if we remove 50 from each of the three sides, we get:

200 - 50 ≤ 15.75x + 50 - 50 ≤ 400 - 50

150 ≤ 15.75x ≤ 350

Now we must divide both totals by 15.75, yielding:

150/15.75 ≤ 15.75x/15.75 ≤ 350/15.75

9.52 ≤ x ≤ 22.22

This is the **inequality's solution**; the solution set expressed as an interval will be [9.52, 22] or 9.52 ≤ x ≤ 22.22

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If z varies inversely as w, and z=20 when w=6, find z when w=3.

Z=

Z = 17 because 20-6 is 14 and 3+14 is 17

A random sample of n = 50 teachers was selected from a Local Government and it has been established that 30% of the entire teachers are ghost workers and 70% are real workers. Determine the expected number of the real workers in any sample of size 50?

The expected number of the real number in any **sample **size is 150.

**What is sample size?**

In statistics, the **sample **size refers to the group of people whose data is analyzed during calculation. Depending upon the constraints, the data is analyzed for the measurement. The analysis of **samples **is perform with the help of Binomial distribution.

According to the question, the given random **sample **can be solved with the help of Binomial distribution:

The **sample **size of teachers: n = 50

Percentage of ghost workers: 30%

Percentage of real workers: 70%

For ghost workers: n = 50 and p = 0.31 and q = 1 - p = 1 - 0.31 = 0.69

Now, to calculate the expected number of the real workers as per given **samples**:

For real workers: n = 50 and p = 0.70 and q = 1 - p = 1 - 0.70 = 0.30

Expected number is: (n)(q) = (50)(0.30) = 150

Hence, the expected number of the real number in any **sample **size is 150.

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Select the GCF of these numbers. 2^5 · 5· 11 and 2^3· 5^2 · 7

The **greatest common factors** of 2^5 · 5· 11 and 2^3· 5^2 · 7 is equivalent to 2^3 * 5

The largest positive integer that divides each of two or more non-zero integers is known as the** greatest common divisor.**

This factor must be able to divide all the terms of the expression withour remainder.

Given the numbers 2^5 · 5· 11 and 2^3· 5^2 · 7. Find the factors;

2^5 · 5· 11 = 2^3 * 2^2 * 5 * 11

2^3· 5^2 · 7= 2^3 * 5 * 5 * 7

Since the number 2^3 * 5 is common to both factors, hence the ** GCF of these numbers** 2^5 · 5· 11 and 2^3· 5^2 · 7 is 2^3 * 5

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a=460 rounded to the nearest 10 b=11.9 rounded to 1 dp find the minimum (to 2 dp) of a / b

The **minimum **result (to 2 dp) of a / b is 38.66

Given:

a=460 rounded to the nearest 10

b=11.9

Now, substitute the values of a and b in a/b,

a/b = 460/11.9

Multiply the same **integer**(10) by both the** numerator **and **denominator**,

a/b = 4600/119

Round the number obtained

a/b ≅ 38.66

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suppose you have the following 2 bytes: 01011100 and 01100101. the sum of the two given bytes is 11000001 does the sum generate a carryout most significant bit? (yes/no) yes what is the sum after carryout bit is added to the least significant bit?
Compare and contrast Walt Whitman and Ralph Waldo Emerons's texts. How does each author see one's self in relation to society? How do the author's style, use of literary devices, word choice, and choice of structure/genre impact the effectiveness of the their message? pls help
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which expression is equivalent to (4^2)^-2?
dsm-i and dsm-ii group of answer choices reflected a psychoanalytic orientation. offered significant generalizability and clinical utility. included lists of specific symptoms or criteria for each disorder. were empirically based.
GIVING 20 POINTS! ENGLISH!There never was a time when the world was without fire, but there was a time when men did not know how to kindle fire; and after they learned how to kindle one, it was a long, long time before they learned how to kindle one easily. In these days we can kindle a fire without any trouble, because we can easily get a match; but we must remember that the match is one of the most wonderful things in the world, and that it took men thousands of years to learn how to make one. Let us learn the history of this familiar little object, the match.Fire was first given to man by nature itself. When a forest is set on fire by cinders from a neighboring volcano, or when a tree is set ablaze by a thunderbolt, we may say that nature strikes a match. In the early history of the world, nature had to kindle all the fires, for man by his own effort was unable to produce a spark. The first method, then, of getting fire for use was to light sticks of wood at a flame kindled by natureby a volcano, perhaps, or by a stroke of lightning. These firebrands were carried to the home and used in kindling the fires there. The fire secured in this way was carefully guarded and was kept burning as long as possible. But the flame, however faithfully watched, would sometimes be extinguished. A sudden gust of wind or a sudden shower would put it out. Then a new firebrand would have to be secured, and this often meant a long journey and a deal of trouble.In 1827, John Walker, a druggist in a small English town, tipped a splint with sulphur, chlorate of potash, and sulphid of antimony, and rubbed it on sandpaper, and it burst into flame. The druggist had discovered the first friction-chemical match, the kind we use to-day. It is called friction-chemical because it is made by mixing certain chemicals together and rubbing them. Although Walker's match did not require the bottle of acid, nevertheless it was not a good one. It could be lighted only by hard rubbing, and it sputtered and threw fire in all directions. In a few years, however, phosphorus was substituted on the tip for antimony, and the change worked wonders. The match could now be lighted with very little rubbing, and it was no longer necessary to have sandpaper upon which to rub it. It would ignite when rubbed on any dry surface, and there was no longer any sputtering. This was the phosphorus match, the match with which we are so familiar.Which of the following is the best paraphrase of the first paragraph?A. Fire often comes from nature, like from a volcano or lightening striking a tree. Before humans could create their own fire, it only came from nature. Humans first got their own fire by lighting sticks of wood from where nature caused a fire. People guarded the fires to keep them from going out, except that sometimes, it would go out. Wind or rain would put out the fire and then they would have to find more fire.B. In 1827, a man named John Walker came up with a formula of friction (sandpaper) and chemicals (sulphur, chlorate of potash, and sulphid of antimony) to create the very first match. It didn't work incredibly well, as it needed a very hard strike and fire got everywhere, so he changed his formula later. Matches now needed less pressure and different chemicals and didn't need to be struck on sandpaper. These are the phosphorus matches that we still use today.C. It took humans a long time to be able to create fire on their own. The invention of matches is amazing to learn about. D.The earth has always had fire, but humans didn't know how to make it themselves. After they finally learned, it was hard for them for a while. Today, it's easy because we can just get a match, but matches are amazing. It took humans many years to learn to make matches, so let's examine the history of the ma
Which ideas describe the big crunch? (1 point)O After the universe reaches its expansion limit, gravity will pull it all back together.O The big bang actually never occurred, and the universe must have a different origin.O The universe goes through infinite cycles of expansion and contraction.O The universe is not only composed of the objects that we can see.
What is the value of 7 + z 2, when z = 10?
Washing his dad's car alone, Matt takes 6 hours. If his dad helps him, then it takes 2 hours. How long does it take Matt's dad to wash the car by himself?
Which best describes where the scientists who have contributed to our scientific knowledge were locatedThe answer is D. They were from all parts of the world