OA. Each copy made has worse quality than the original data did.

B. Data are copied quickly, easily, and perfectly.

C. Only one value of the digital data is copied perfectly.

D. Data are copied quickly, but they decrease in quality.

When **data** stored digitally are copied then data are copied quickly, easily, and perfectly.

Data stored digitally are quickly, easily and perfectly copied.

There is no effect on the quality of the data.It just copies the data exactly as theData is a **collection** of quantities, photos or videos, signs or symbols, on which operations are performed by a computer, which can be stored and transmitted in the form of **electrical signals** and recorded on magnetic, optical or mechanical recording media.

Since no quality of the file is lost, copying a data is an **easy**, **quick** and a **perfect** process.

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The density of mercury is 13600 kgm-3. So, the relative density of mercury is A. 13.6 B. 1.36 C. 136

**The density of water is,**

**The density of mercury is,**

The relative density of mercury is the density of mercury concerning the density of water.

Thus, the relative density of mercury is,

[tex]\begin{gathered} \frac{d_m}{d_w}=\frac{13600}{1000}_{} \\ \frac{d_m}{d_w}=13.6 \end{gathered}[/tex]**Hence, option A is the correct answer.**

It takes a continent approximately 250,000,000 years to move half-way around Earth, a distance of about 19,200 km or 1,920,000,000 cm. The speed of the continent in what per what can be found by dividing 1,920,000,000 cm by 250,000,000 years.

The** speed **of the **continent **is found to be 7.68 centimeters per hour when 1920000000cm is divided by 250000000years.

The distance travelled by the continent is 1920000000cm.

The time taken by the continent to complete its path is 250000000.

The **speed S** of the body,

**S = D/T**

Where,

D is the** distance travelled** by the body,

T is the **time taken** by the body to cover that distance.

The** speed S** of the continent is,

S = D/T

S = 1920000000cm/250000000year

S = 7.68 cm/year

Hence, the speed of the **continent** is 7.68 centimeters per year.

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Which of the following numbers has the greatest number of significant figures?a.) 144.5b.) 0.009514 c.) 10.507d.) 6.948 ✕ 10

So, the number with the greatest number of significant figures is:

0.009514. **[Option B]**

Starting from rest, a car accelerates at 2.0 m/s2 up a hill that is inclined 5.5° above the horizontal. How far (a) horizontally and (b) vertically has the car traveled in 12 s?

**Given data:**

* The acceleration of the car is,

[tex]a=2ms^{-2}^{}[/tex]* The angle of the inclined plane is 5.5 degree.

* The time taken by the car is 12 s.

* The initial velocity of the car is 0 m/s.

**Solution:**

By the kinematics equation, the final velocity of the car on the inclined plane is,

[tex]v-u=at[/tex]where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the tiem taken,

Subsituting the known values,

[tex]\begin{gathered} v-0=2\times12 \\ v=24\text{ m/s} \end{gathered}[/tex]By the kinematics equation, the distance tarveled by the car on the inclined plane is,

[tex]v^2-u^2=2aS[/tex]where S is the distance tarveled on the inclined plane,

Substituting the known values,

[tex]\begin{gathered} 24^2-0=2\times2\times S \\ 576=4\times S \\ S=\frac{576}{4} \\ S=144\text{ m} \end{gathered}[/tex]The diagrammatic representation of the car on the inclined plane is,

The distance traveled by the car in the horizontal direction or along x-axis is,

[tex]\begin{gathered} S_x=S\cos (5.5^{\circ}) \\ S_x=144\times\cos (5.5^{\circ}) \\ S_x=143.34\text{ m} \end{gathered}[/tex]**Thus, the distance tarveled by the car in the horizontal direction is 143.34 meter.**

The distance tarveled by the car in the vertical direction or y-axis is,

[tex]\begin{gathered} S_y=S\sin (5.5^{\circ}) \\ S_y=144\times\sin (5.5^{\circ}) \\ S_y=13.8\text{ m} \end{gathered}[/tex]**Thus, the distance tarveled by the car in the vertical direction is 13.8 meter.**

A string 0.50 m long is stretched under a tension of 2.0 x 102 N and its fundamental frequency is 400 Hz. If the length if the string is shortened to 0.35 m and the tension is increased to 4.0 x 102 N, what is the new fundamental frequency?

Given,

The initial length of the string, L₁=0.50 m

The tension on the string, T₁=2.0×10² N

The initial fundamental frequency of the string, f₁=400 Hz

The length of the string after it was shortened, L₂=0.35 m

The increased tension on the string, T₂=4.0×10² N

The fundamental frequency of the string before it was shortened is given by,

[tex]f_1=\frac{\sqrt[]{\frac{T_1}{\mu}}}{2L_1}[/tex]Where μ is the mass per unit length of the string.

On rearranging the above equation,

[tex]\begin{gathered} 4L^2_1f^2_1=\frac{T_1}{\mu} \\ \Rightarrow\mu=\frac{T_1}{4L^2_1f^2_1} \end{gathered}[/tex]On substituting the known values,

[tex]\begin{gathered} \mu=\frac{2.0\times10^2}{4\times0.50^2\times400^2} \\ =1.25\times10^{-3}\text{ kg/m} \end{gathered}[/tex]The fundamental frequency after the string was shortened is given by,

[tex]f_2=\frac{\sqrt[]{\frac{T_2}{\mu}}}{2L_2}[/tex]On substituting the known values,

[tex]\begin{gathered} f_2=\frac{\sqrt[]{\frac{4\times10^2}{1.25\times10^{-3}}}}{2\times0.35} \\ =808.1\text{ Hz} \end{gathered}[/tex]**Thus the fundamental frequency after the string is shortened and the tension is increased is 808.1 Hz**

Alex tickles his brother by stroking adjacent ________ spots on his skin.

**Answer:**

adjacent flat spots on his skin

**Answer:**

You didn't provide answer choices but I'd assume it's **pressure.**

A rocket toy moves straight upward, starting from rest with an acceleration of 4 m/s2. It runs out of fuel at the end of 10 s and continues to coast upward, reaching a maximum height before falling back to earth

a. Find the rocket’s velocity and position at the end 10 s

B. Find the velocity before the rocket crashes on the ground

C. Find the time flight of rocke

I think the answer is C

A stunt performer falls off a wall that is 3.1 m high and then lands on a mat.

What is his impact velocity?

**Answer:7.8 M/s**

**Explanation:**

Which of the following statements correctly explains the relationship between FM and AM radio waves?

A.

FM radio waves carry less energy than AM radio waves. This is supported by the fact that FM radio waves have a shorter wavelength compared to AM radio waves.

B.

FM radio waves carry less energy than AM radio waves. This is supported by the fact that FM radio waves have a longer wavelength compared to AM radio waves.

C.

FM radio waves carry more energy than AM radio waves. This is supported by the fact that FM radio waves have a shorter wavelength compared to AM radio waves.

D.

FM radio waves carry more energy than AM radio waves. This is supported by the fact that FM radio waves have a longer wavelength

The relationship between the **AM **and the **FM **waves is that the wavelength of the FM waves is **longer **than that of the AM waves.

The** radio waves** are one of the waves that are part of the **electromagnetic spectrum** and they are used in the process of communication . The reason why the radio waves could be used for the process of communication is that the radio waves do have a long wavelength this they can travel for very long miles without a significant decrease in intensity of the waves.

Thus, **FM radio waves **carry less energy than** AM radio waves.** This is supported by the fact that FM radio waves have a longer wavelength compared to AM radio waves.

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On a plot of angular position versus time t for the rotation of a disk, what corresponds to the disk’s angular velocity at any given instant t1?

a. inverse of the slope at the point on the plot corresponding to t1

b. intercept on the vertical axis

c. slope at the point on the plot corresponding to t1

d. intercept on the horizontal axis

Option** **d** **i.e**;**** ****Slope **at** **the** **point** **on** **the** **plot** corresponding to t1** corresponds to disk's angular velocity at any given instant t1.

The angular velocity (w), a **vector **quantity in uniform circular motion, is determined by dividing the angular displacement (Δ), also a vector quantity, by the change in time (Δt). Speed is equal to |w|R and is calculated by dividing the arc length travelled (S) by the change in time (Δt).

Examples of angular velocity include a roulette ball on a wheel, a race car travelling in a circle, and a Ferris wheel. In addition, the object's angular** displacement** with respect to time is represented by the angular velocity of the object.

Because it is practical, angular velocity is **perpendicular**. Because all they are is a magnitude and a direction, a vector cannot be curved. In order to represent the rotational direction, we use the direction perpendicular to the plane.

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1. A sound engineer has set up his mixing equipment a distance from an outdoor band shell.She claps her hands and hears the echo 0.250 s later. If the speed of sound was 340.0m/s, how far from the wall was she?

**Given**

Hears the echo at , t=0.250 s

Speed pf sound is v=340 m/s

**To find**

The distance from the wall

**Explanation**

let her distance from the wall be d.

When she hears the echo, the sound has travelled the same distance twice

So

[tex]\begin{gathered} v=\frac{2d}{t} \\ \Rightarrow340=\frac{2d}{0.250} \\ \Rightarrow d=d=42.5\text{ m} \end{gathered}[/tex]**Conclusion**

The distance of the wall from her is** 42.5 m**

Question 11

5 pts

Gas Laws: A balloon is carefully filled with one breath of air (about 500ml) underwater at

a depth of 100ft, then tied shut. At this depth, the balloon is under 4 atmospheres of

pressure. Assuming negligible compression by the rubber of the balloon, what is the

volume of the air (in m³) once the balloon rises to the surface of the water and

experiences 1 atm of pressure? Modify the Ideal Gas Law to solve this conservation

problem.

1 Liter 0.001 Cubic Meter

1 atm = 1.01x 105 Pascals

The **volume **of the gas once it reaches the **surface **of water is 2 liters.

The **volume **of the air in balloon at depth of 100ft (30m) is 500ml.

The pressure at this point is 4 atm.

Assuming that the balloon have **no compression **by rubber of balloon the volume of air at the water surface is V.

The pressure at the surface of water is 1 atms.

As we know, from the** ideal gas equation,**

PV = nRT

Where,

P is the **Pressure **of gas,

V is the **volume **of the gas,

n is the number of **moles**,

R is the **gas constant** whose value is 0.082057 L atm mol-1 K-1,

T is the **temperature**.

Assuming that the temperature is **constant**,

We know,

PV = nRT

All quantities on the right side are constants,

So, we can write,

P₁V₁ = P₂V₂

Putting all the the values,

4(0.5) = 1V₂

V₂ = 2 Liters.

The volume of the air at the surface is 2 liters.

1 liter = 0.001 m

Hence,

2 liters = 0.002 m³

So the **volume **of air at the surface is 0.002m³.

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A block of mass M is hung by ropes as shown. The system is in

equilibrium. The point O represents the knot, the junction of the

three ropes. The angle theta is given to be 30o

. Which of the

following statements is true concerning the magnitudes of the three

forces in equilibrium?

Their **magnitude **of force must be the same for the **tensions** to equal out.

An object at **equilibrium** has zero **acceleration** so both the magnitude and direction of the object's velocity must be constant. When the body is in equilibrium the forces are balanced. Balanced is a keyword used to describe a balanced state. Therefore the net force is zero and the acceleration is 0 m/s/s. The acceleration of a body in equilibrium must be 0 m/s/s

For a body to be in **equilibrium** it must not be** accelerating**. This means that both the net force and net torque on the object must be zero. Clearly when in equilibrium, the net force on the object is zero. According to Newton's second law of motion if the net force is zero the acceleration is also zero. When the acceleration is zero the velocity and thus the velocity is constant by definition. Option d does not apply to equilibrium in this case.

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H3C- CH2-CH2-CH2-CH3name formula HC/// C-CH2-CH3name formula

1.

The number of the carbon atom is five. All the carbon atom is single-bonded.

The formula name of the above is **Pentane.**

The number of the carbon atom is four. All the carbon atom is single-bonded except one triple bond at the first place.

The formula name of the above is **1-butyne.**

When you drop a 0.38 kg apple, Earth exerts a force on it that accelerates it at 9.8 m/s2 to- ward the earth’s surface. According to New-

**Answer:**

At the surface it is defined by 9.80665 m/s2.

What voltage was needed for 2 amps to flow through a 600 lamp?

**Answer:**

I don't kno..................................................w

yo can anyone help me solve this rq i need it for tomorrow

a. 600 **meters**; b. 6 **minutes**; c. 7.5 minutes; d. 4 minutes; e. 5 minutes; f. 125m/min; g. 50m/min; h. 60m/min; i. 150m/min; j. 100m/min; k. 80m/min and l. 1m/s, 2.5m/s, 1.66m/s and 1.33m/s.

As per the** graph,**

The **motion **of Rachel and ben starts from t=0 and ends at t = 13minutes after covering **distance **of 600 meters.

a. As there motion is ending at 600 meters. They travel 600 meters to go to school.

b. Ben travels for 4 minutes first, after that he stops and then again starts from 8 minutes to 10 minutes. So, it takes 6 minutes for him to go to school.

c. Rachel travels for 5 minutes first, after that she stops and then again starts from 10 minutes to 12.5 minutes. So, it takes 7.5 minutes for her to go to school.

d. Ben stops from 4 to 8 minutes on his way to school. After that he stops only at school so it would not be counted. So he stops for 4 minutes.

e. Rachel stop from 5 minutes to 10 minutes on her way. So, she stops for 5 minutes in her way to school.

f. Ben's speed in first half,

**Speed = distance in first half/time taken in first half.**

Ben's Speed in first half = 500/4

Ben's Speed in first half = 125 m/min.

g. Ben's speed in last part,

Speed = distance in last part/time taken in last part.

Ben's Speed in last part = 100/2

Ben's Speed in last part = 50m/min.

h. Rachel's speed in first half,

Speed = distance in first half/time taken in first half.

Rachel's Speed in first half = 300/5

Rachel's Speed in first half = 60 m/min.

i. Rachel's speed in last part,

Speed = distance in last part/time taken in last part

Rachel's Speed in last part = 300/2

Rachel's Speed in last part = 150m/min.

j. Ben's average speed = total distance/total time

Total distance = 600

Total time = 6 minutes

Average speed of Ben = 600/6 = 100 m/min.

k. Rachel's average speed = total distance/total time

Total distance = 600

Total time = 7.5 minutes

Average speed of Rachel = 600/7.5 = 80m/min.

l. **Converting m/min** to **m/s **by **dividing **by 60.

Converting speed in h = 60/60 = 1m/s.

Converting speed in i = 150/60 = 2.5m/s.

Converting speed in j = 100/60 = 1.66m/s.

Converting speed in k = 80/60 = 1.33m/s.

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A spherical specimen of the mineral chalcopyrite measures 3.9 cm in diameter and has a mass of

129.67 g. What is its specific gravity?

A **spherical specimen** of the **mineral chalcopyrite** measures 3.9 cm in diameter and has a **mass **of 129.67 g, its **specific gravity **is 4.17g/cm³

The ratio of a substance's density to that of a reference substance is its **specific gravity**, also known as relative density.

Water, which has a density of 1.0 kg/litre at 4 °C (39.2 °F), serves as the standard of comparison for solids and liquids (62.4 pounds per cubic foot).

Dry air, which is frequently used as a comparison point for gases, has a density of 1.29 grams per litre (1.29 ounces per cubic foot) under what are known as "standard conditions" (a temperature of 0 °C and a pressure of 1 standard atmosphere).

As an illustration, the **specific gravity **of liquid mercury is 13.6 due to its density of 13.6 kg per litre. The density of the gas carbon dioxide, which is 1.976 grams per liter under ideal conditions, translates into a s**pecific gravity **of 1.53 (= 1.976/1.29).

The formula for **specific gravity **is given by

**specific gravity **= density of the object / density of the water

Here given that a **spherical specimen** of the mineral chalcopyrite measures 3.9 cm in diameter and has a **mass **of 129.67 g

Then its volume is

Volume of sphere = [tex]{\frac {4}{3}}\pi r^{3}[/tex]

Substituting the values we get

V = [tex]{\frac {4}{3}}\pi (\frac{3.9}{2} )^{3}[/tex]

= 31.06 cm³

Density = **Mass**/Volume

Density of mineral chalcopyrite = 129.67g / 31.06 cm³

= 4.17 g/cm³

Now, we can finally calculate **specific gravity**

**specific gravity **= 4.17 g/cm³ / 1g/cm³ (Density of water is 1m/1V)

= 4.17g/cm³

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Density of iron is 7860 Kg/m^3 what is the mass of iron sphere whose diameter is 0.5 m?

The mass of the given** iron sphere** of diameter 0.5 m is **510.9 kg**

**Density** of the iron sphere = 7890 kg/m³

**Diameter** of the iron sphere = 0.5 m

**Radius **of the iron sphere = 0.25m

The formula to find the mass of the iron sphere is

**ρ = m / v**

where ρ is the density

m is the mass

v is the volume.

So , to find the mass , we need to know the volume of the sphere

Volume of the sphere = 4/3 πr³

Let us substitute the value of r in the above equation,

V = 4/3 x 3.14 x (0.25)³

= 4/3 x 3.14 x 0.0156

= 0.196/3

** V = 0.065 m³**

So , now let us find the mass of the given sphere

ρ = m / v

m = ρv

m = 7860 x 0.065

** m = 510.9 kg**

Therefore , the **mass **of the given iron sphere is **510.9 kg**

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Hello! So I need some help with this question. I don’t quite understand it and I did have another tutor figure it out and the answer was wrong. It’s not his answer of 58.04. Can you help me?

**ANSWER:**

**58 m/s**

**STEP-BY-STEP EXPLANATION:**

Given:

Initial velocity (u) = 13 m/s

The correct answer is 58 m/sDistance (d) = 400 m

Acceleration (a) = 4 m/s²

We apply the following formula to determine the final velocity:

[tex]\begin{gathered} v^2=u^2+2as \\ \\ \text{ We replacing:} \\ \\ v^2=13^2+2(4)(400) \\ \\ v^2=169+3200 \\ \\ v=\sqrt{3369} \\ \\ v=58.04\cong58\text{ m/s} \end{gathered}[/tex]**The correct answer is 58 m/s**

A 320.-kg reindeer stands in the middle of the railroad tracks, frozen by the lights of an oncoming 10,000.-kg train that is traveling at 10.0 m/s. The engineer sees the reindeer but is unable to stop the train in time and the reindeer rides down the track sitting on the cowcatcher. What is the new combined velocity of the reindeer and train?

**Answer:**

**9.69 m/s**

**Explanation**

By the conservation of momentum, we can write the following equation:

[tex]\begin{gathered} p_i=p_f \\ m_1v_{i1}+m_2v_{i2}=(m_1+m_2)v_f \end{gathered}[/tex]Where m1 is the mass of the reindeer, m2 is the mass of the train, vi1 is the initial velocity of the reindeer, vi2 is the initial velocity of the train and vf is the final velocity of the reindeer and train.

So, replacing m1 = 320 kg, m2 = 10,000 kg, vi1 = 0 m/s and vi2 = 10 m/s, we get

[tex]\begin{gathered} 320(0)+10,000(10)=(320+10000)v_f_{} \\ 0+100,000=(10320)v_f \\ 100,000=10,320v_f \end{gathered}[/tex]Now, solving for the final velocity, we get

[tex]\begin{gathered} v_f=\frac{100,000}{10,320} \\ v_f=9.69\text{ m/s} \end{gathered}[/tex]Therefore, the new combined velocity of the reindeer and train is 9.69 m/s

Which planets in our solar system revolve the fastest? and Why?

A. The gas giant planets

B.Planets closest to the Sun

C. Planets farthest from the Sun

D. All planets revolve at the same speed

The answer is B. Planets closest to the Sun

The final stage of reduction of pressure in a regulator is to how many PSIG

The final stage of reduction of **pressure** in a **regulator** is to 500 PSIG.

A **gas** **pressure** **regulator** can be defined as a mechanical device that is designed and developed to ensure that a controlled amount of **gas** is supplied from a **gas** cylinder (source).

This ultimately implies that, a **gas** **pressure** **regulator** is required on a **gas** cylinder in order to reduce very high (unusable) **pressure** within the **gas **cylinder to a safer and usable delivery **pressure**.

In Science, a two-stage **gas** **pressure** **regulator** is designed and developed to lower very high (unusable) **pressure** in two (2) stages.

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1.The water in the plumbing in a house is at a gauge pressure of 74,000 Pa. What force does this cause on the top of the tank inside a water heater if the area of the top is 0.38 m2?

**Given:**

The pressure inside the tank, P=74000 Pa

The area of the top of the tank, A=0.38 m²

**To find:**

The force exerted on the top of the tank.

**Explanation:**

The pressure can be described as the force exerted per unit area.

Thus the pressure inside the tank is given by,

[tex]P=\frac{F}{A}[/tex]Where F is the force exerted on the top of the tank.

On substituting the known values,

[tex]\begin{gathered} 74000=\frac{F}{0.38} \\ \implies F=74000\times0.38 \\ =28120\text{ N} \end{gathered}[/tex]**Final answer:**

**Thus the force exerted on the top of the tank is 28120 N**

Lesson 3

Write a descriptive essay about the basic steps of the scientific method.

Include the following essential content:

Testable hypothesis

Data collection and analysis

Peer review

Also, include where theories fit into the process of the scientific method.

A **sample descriptive essay **about the basic steps of the scientific method is given below:

When a person is **testing a hypothesis**, it is important that he **collects data **and then makes an analysis of it, and puts it through a controlled experiment** **at the lab.

Next, he would have to **peer-review **the results of the experiments and when this is confirmed, it becomes a** theory,**

This refers to the **process **of systematic observation that is used to come to a conclusion in a **scientific **investigation**.**

Hence, we can see that the **descriptive essay **about the scientific method is given above,.

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Calculate the amount of charge that flows past a cross-sectional area of a conductor if a current of 0.2 A flows in it for 1 minute?

**Answer:**

12C

**Explanation:**

q = It

where q is the charge in coloumbs (c)

I is the current in amperes (A)

t is the time in seconds (s)

q = 0.2× 60 (1 minute is 60seconds)

q= 12C

What if you had a leak in the refrigerant line. Explain in terms of energy and pressure and temperature.

The most** frequent** HVAC crises are gas leaks, clogged drain lines, electrical problems, **refrigerant leaks**, and problems with ventilation.

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If the slope of a position versus time graph is negative, what does that imply about the motion of an object? A. The object has a negative acceleration. B. The object turned around. C. The object is moving in the negative direction. D. All of the above

**ANSWER**

A. The object has a negative velocity

**EXPLANATION**

We want to describe the slope of a position-time graph that is negative.

If the slope of a position-time graph is negative, it implies that the velocity is also negative. In other words, as time increases, the velocity also decreases.

As velocity decreases, it implies that the acceleration also decreases.

Therefore, we have that **the acceleration of the object is negative**.

**The answer is option A.**

Cory is at the park playing fetch with his dog. He throws the ball 23 m south, and his dog retrieves the ball and returns it to Cory. Cory then throws the ball 18 meters, and the dog again collects the ball and returns it to Cory. When the dog returns for the second time, what distance has the dog traveled?0 m82 m36 m23 m

In order to determine the distance traveled by the dog in the two times, consider:

In the second time the dog goes and comes back for a distance of 18 m, that is, the total distance is **18m + 18m = 36 m**

In the first time the dog goes and comes back for a distance of 23 m, that is, the total distance is **23m + 23m = 46 m**

**Hence, for the two times the distance traveled by the dog is:**

**46m + 36m = 82m**

A circular loop of wire of area 10 cm^2 carries a current of 25 A. At a particular instant, the loop lies in the xy-plane and is subjected to a magnetic field B =(2.0iˆ+6.0jˆ+8.0kˆ)×10−3T. As viewed from above the xy-plane, the current is circulating clockwise. (a) What is the magnetic dipole moment of the current loop? (b) At this instant, what is the magnetic torque on the loop?

The **magnetic dipole moment** of the current loop is 0.025 Am².

The **magnetic torque** on the loop is 2.5 x 10⁻⁴ Nm.

The **magnetic dipole moment** of an object, is the measure of the object's tendency to align with a magnetic field.

Mathematically, **magnetic dipole moment** is given as;

μ = NIA

where;

N is number of turns of the loopA is the area of the loopI is the current flowing in the loopμ = (1) x (25 A) x (0.001 m²)

μ = 0.025 Am²

The **magnetic torque** on the loop is calculated as follows;

τ = μB

where;

B is magnetic field strengthB = √(0.002² + 0.006² + 0.008²)

B = 0.01 T

τ = μB

τ = 0.025 Am² x 0.01 T

τ = 2.5 x 10⁻⁴ Nm

Thus, the **magnetic dipole moment** of the current loop is determined from the current and area of the loop while the **magnetic torque** on the loop is determined from the magnetic dipole moment.

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P=N+2/D make N the subject formula
How, when, and where did Christopher Columbus died?
According to this graph what is the pressure at 120K?
3. The density of CH4 (OH) is 1.09 g/me. How Many gram of CH4 (OH)2 Should be Mixed With 375 ml of Water to make a 7.50% by Mixture?
A body weighs (i) 900N on the surface of earth how much will it weigh on the surface ofMars whose mass is one ninth and radius is one half that of the earth take g on the surfaceof earth to be 10 m/s2
James wants to have earned $7,592 amount of interest in 16 years. Currently he finds that hisannual interest rate is 9.04%. Calculate how much money James needs to invest as his principal inorder to achieve this goal.Round answers to the nearest hundredth (two decimal places) of a year.
The unit taught you that a great way to exude professionalism as a cosmetologist is to keep detailed and stringent notes on your clients. Provide an example of notes that you might keep on two different clientsone is a longtime client who receives monthly chemical relaxer services and suffers from several scalp conditions; the other is a new client who would like to receive monthly color treatments and regular haircuts. Beyond this information provided, you will come up with any other pertinent details that you feel would be important to keep notes on (hair and scalp conditions, products used, personal details, etc.). After providing an example of the notes that you might keep, offer a brief explanation of both sets of notes.
Fill in the blank with the correct indirect object pronoun.Yo prefiero comprar______ la ropa a mi esposo.A. meB. leC. lesD. te
The sum of the angle measures of a triangle is 180 degrees angles of a triangle measure 40 and 70 degrees , so Katy concludes that the third angle measures 70inductive or Deductive ??i need help
What is the headline? Caption This.REFRES...THEATER NOTRESPONSIBLEFOR THE SAFETYOF PEOPLE WHOTEXT DURINGMOVIES
Mike is training for a race. He wants his pace to be proportional throughout the race. The table relates the number of hours he ran and the distance that he traveled. Hours 0.5 1.0 1.5 2.0 Miles 3 6 8 12 Mile then graph these points (hours, miles) to determine whether or not his pace was proportional. Mike determined his pace was proportional because the graph passes through the origin. Which statement best describes his error? Multiple choice question. cross out A) The graph passes through the point (1, 1). cross out B) The graph does not pass through the origin. cross out C) The graph both passes through the origin and is a straight line. cross out D) While the graph does pass through the origin, it is not a straight line.
PLEASE HELP ASAP ITS THE LAST QUESTION I HAVE
Which 2 expressions are equivalent to 3(x+6)?1. 3+x+3+x2. (x+6)+(x+6)+(x+6)3. 3x+64. 3x+18
1. Which category of gymnosperms are thought to have given rise to modern-day flowering plants?A. gnetophytesB. ginkgoC. conifersD. Cycads
The sum of two numbers is 6. Theirdifference is 12. Find the numbers.
GEOMETRY ITS DUE AT 2:15 PLEASE .1) Write an equation perpendicular to 2x + 3y = 18 that passes through the point (1, 5).2) Write an equation parallel to y = 2x + 6 that passes through the point (0, 7).
Did any revolutions take place in Greece in 1848-1849?
Ezra miller pleaded not guilty to burglary chargeswhich dc superhero does miller play?.
PLEASE QUICK HELP ME
here are four steps in solving ones personal financial challenges: 1. considering opportunity costs 2. assessing risks and returns 3. setting short- and long-term goals 4. assessing needs and wants Which of these is the correct order of these steps? 2, 1, 3, 4 1, 2, 3, 4 4, 1, 2, 3 4, 2, 3, 1