Answers
Answer:
2.1 × 10^-8 J/°c
Explanation:
Is this the answer if yes I would explain if not , that's all I know .
When a 58.8-g piece of hot alloy is placed in 125 g of cold water in a calorimeter, the temperature of the alloy decreases by 106.1°C, while the temperature of the water increases by 10.5°C. The specific heat of the alloy is 0.087 J/(g °C).
Step 1: We know that the heat gained by the water is equal to the heat lost by the alloy. This is based on the law of conservation of energy, which states that energy cannot be created or destroyed, only transferred.
Step 2: We can calculate the heat gained by the water using the formula:
q = mcΔT
where:
q = heat energy
m = mass
c = specific heat
ΔT = change in temperature
For water, the specific heat (c) is 4.18 J/(g °C). So, the heat gained by the water is:
q = (125 g)(4.18 J/(g °C))(10.5 °C) = 5497.5 J
Step 3: The heat lost by the alloy is equal to the heat gained by the water. So, the heat lost by the alloy is also 5497.5 J.
Step 4: We can calculate the specific heat of the alloy using the formula:
c = q/(mΔT)
where:
c = specific heat
q = heat energy
m = mass
ΔT = change in temperature
So, the specific heat of the alloy is:
c = 5497.5 J / (58.8 g)(106.1 °C) = 0.087 J/(g °C)
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Related Questions
how many moles of ammonia can be formed from 4.0 mol H2
how many moles of hydrogen are required to form 8.0 mol NH3
how many moles of nitrogen are required to react with 6.0 mol H2
Answers
Answer: 1. 2.7 moles of ammonia are formed
2. 12.0 moles of hydrogen are required
3. 2.0 moles of nitrogen are required
Explanation:
The balanced chemical equation is:
[tex]N_2+3H_2\rightarrow 2NH_3[/tex]
According to stoichiometry:
3 moles of hydrogen form = 2 moles of ammonia
Thus 4.0 moles of hydrogen form =[tex]\frac{2}{3}\times 4.0=2.7moles[/tex] of ammonia
According to stoichiometry:
2 moles of ammonia are formed by = 3 moles of hydrogen
Thus 8.0 moles of ammonia are formed by =[tex]\frac{3}{2}\times 8.0=12.0moles[/tex] of hydrogen
According to stoichiometry:
3 moles of hydrogen react with = 1 mole of nitrogen
Thus 6.0 moles of hydrogen react with =[tex]\frac{1}{3}\times 6.0=2.0moles[/tex] of nitrogen
Tam a highly reactive alkali metal in period 3 with only one valence electron
O Sodium (Na)
Beryllium (Be)
Magnesium (Mg)
Answers
Answer:
Sodium (Na)
Helium
Magnesium (Mg).
Explanation:
From the periodic table, we will understand that the group 1 metals are the alkali metal. However, the period runs from left to right on the periodic table while the group runs from up to down in the periodic table. In period 3, the alkali metal present there with one valence electron in its outermost shell is sodium (Na).
The only noble gas exists in the last group, group zero of the periodic table. However, the only noble gas with two electrons in its outermost shell is called Helium
The ALkaline earth metals are group 2 metals. They are usually shiny metals and the ability to lose 2 electrons in their outermost electron shell. The alkaline earth metal located in period 3 is Magnesium (Mg).
What type of energy is being represented in the image
Answers
Answer:
Its Kinetic energy
Explanation:
You are giving the bow potential energy. "When you let the bow go, it returns to its original shape. The energy is transformed to kinetic energy and transferred to the arrow"
Answer:
potential
Explanation:
the energy is potential lol
Calculate the pH of each solution:
0.030 M HBr
3.0 M HF
0.50 M HNO3
O.0010 M NaOH
0.150 M KOH
Answers
The reaction for the formation of ammonia is given a
N2(g) + 3H2(g) = 21H3(g)
write the vate reaction for :
a) the formation of NH₃.
6) the disappearance of N and H₂
Answers
Answer:
a.
[tex]rate_{NH_3}=\frac{2d[NH_3]}{dt}[/tex]
b.
[tex]rate_{N_2}=\frac{-1d[N_2]}{dt} \\\\rate_{H_2}=\frac{-3d[H_2]}{dt}[/tex]
Explanation:
Hello there!
In this case, according to the law of rate proportions, it is possible to write the the rates of reaction for the formation of NH3 and the disappearance of the N2 and H2, by considering that the coefficient in the reaction for NH3 is +2 and those of N2 and H2, -1 and -3 respectively. Moreover, we set up these equations as derivatives as shown below:
a.
[tex]rate_{NH_3}=\frac{2d[NH_3]}{dt}[/tex]
b.
[tex]rate_{N_2}=\frac{-1d[N_2]}{dt} \\\\rate_{H_2}=\frac{-3d[H_2]}{dt}[/tex]
Best regards!
Of the following waves, which kind of wave does NOT require a medium?
a. light
b. water
с. ultrasound
d. sound
Answers
If the colour of a solution turns pink on adding few drops of phenolphthalein indicator, it means solution is acidic. Select one :
True
False
Answers
Answer:
False, it becomes colourless in acidic solutions and turns pink in basic solutions
1.Why do you think the agricultural revolution led to more population growth?
Answers
Answer:
The agricultural revolution increased agricultural production and technological advancements. I think this led to population growth because the increase in labor and the increase in technologies increased human deveolpment. The revolution also allowed farmers to grow and produce more food and transport it to where it was needed.
Explanation:
How many moles are in 272 grams of hydrogen peroxide (H2O2) ?
Answers
Answer:
8 moles
Explanation:
When we are asked to convert from grams of a substance into moles, we have to use the substance's molar mass.
Meaning that for this problem, we'll use the molar mass of hydrogen peroxide (H₂O₂), as follows:
272 g ÷ 34 g/mol = 8 molThere are 8 moles in 272 grams of hydrogen peroxide.
What is another name for heat?
A
light energy
B.
infrared energy
C
Thermal energy
D
electromagnetic energy
Answers
Answer:
C
Explanation:
thermal energy is the another name for heat
Please help me l don’t understand please !!!!!!
Answers
Answer: C
Explanation:
he never had evidence in the first place that was nearly enough.
1. What do producers do, and what is another name for them?
Answers
Producers are the foundation of every food web in every ecosystem—they occupy what is called the first tropic level of the food web. The second trophic level consists of primary consumers—the herbivores, or animals that eat plants. At the top level are secondary consumers—the carnivores and omnivores who eat the primary consumers. Ultimately, decomposers break down dead organisms, returning vital nutrients to the soil, and restarting the cycle. Another name for producers is autotrophs, which means “self-nourishers.” There are two kinds of autotrophs. The most common are photoautotrophs—producers that carry out photosynthesis. Trees, grasses, and shrubs are the most important terrestrial photoautotrophs. In most aquatic ecosystems, including lakes and oceans, algae are the most important photoautotrophs.
Which statement describes a homogeneous catalyst?
do
It is in a gaseous phase only. It is in the same phase as the reactants.
It is completely consumed by reactants.
It forms different products than the uncatalyzed reaction forms.
Answers
The statement which is given below describe a homogeneous catalyst.
"It is in the same phase as the reactants"
What is homogeneous catalyst?The catalyst which have similar phase to the reactant of the reaction is called homogeneous catalyst.
Mostly in homogeneous catalyst, catalyst present in liquid form.
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Which has more mass, 1 mole of magnesium or 1 mole of calcium?
Answers
Answer:
calcium has more mass
Explanation:
1 mole calcium mass= 40.078 g
1 mole magnesium mass= 24.305 g
Paul swam 7 5/8 miles. His sister swam five times as many miles. How many miles did Paul's sister swim?
Answers
Answer:
Distance cover by Paul's sister by swim = 38.125 miles
Explanation:
Given:
Distance cover by Paul by swim = [tex]7\frac{5}{8}[/tex] = 61/8 miles
Distance cover by Paul's sister by swim = 5 times Distance cover by Paul
Find:
Distance cover by Paul's sister by swim
Computation:
Distance cover by Paul's sister by swim = 5 times Distance cover by Paul
Distance cover by Paul's sister by swim = 5 x [61 / 8 miles]
Distance cover by Paul's sister by swim = 305 / 8 miles
Distance cover by Paul's sister by swim = 38.125 miles
A low pitch sound is associated with which of the following?
а. high frequency
b. low frequency
с. fundamental tone
d. low intensity
No links plz
Answers
Approximately 1 mL of two clear, colorless solutions, 0.1 M Ba(NO3)2 and 0.1 M Na2SO4, were combined. Upon mixing, a thick milky white precipitate formed. After centrifugation, the solution above the precipitate was found to be clear and colorless. Based on the these observations, determine if a reaction occurred. If so, what is the net ionic equation for the reaction.
Answers
Answer:
Ba²⁺(aq) + SO₄²⁻(aq) ⇒ BaSO₄(s)
Explanation:
Let's consider the molecular equation for the reaction between Ba(NO₃)₂ and Na₂SO₄. This is a double displacement reaction in which BaSO₄ forms a white precipitate.
Ba(NO₃)₂(aq) + Na₂SO₄(aq) ⇒ BaSO₄(s) + 2 NaNO₃(aq)
The complete ionic equation includes all the ions and insoluble species.
Ba²⁺(aq) + 2 NO₃⁻(aq) + 2 Na⁺(aq) + SO₄²⁻(aq) ⇒ BaSO₄(s) + 2 Na⁺(aq) + 2 NO₃⁻(aq)
The net ionic equation includes only the ions that participate in the reaction and insoluble species.
Ba²⁺(aq) + SO₄²⁻(aq) ⇒ BaSO₄(s)
In the balanced equation-aPb(NO3)2(s)heatb PbO(s)+ c NO2(g)+ dO2(g); the values of a,b,c, d are respectively
Answers
Answer:
The balance reaction is
2Pb(NO3)2 ----》4NO2+2PbO+O2
hence the value of a,b,c,d are 2,4,2,1 respectively!
Plz help me I am timed!!!!!
Answers
Answer:
i think its the gibbous phase
Explanation:
What is the coefficient for hydrogen in the balanced equation for the reaction of solid tungsten(VI) oxide with gaseous hydrogen to form solid tungsten and liquid water?
Answers
Answer:
2
Explanation:
WO2(s) + 2H2(g) -> W(s) + 2H2O(l)
A flask contains 1.45 moles of N2, 0.659 moles of He. If the total pressure is 775 torr, what is the partial pressure of O2 ?
Answers
Answer:
533.2 torr.
Explanation:
The following data were obtained from the question:
Mole of N₂ = 1.45 moles
Moles the He = 0.659 mole
Total pressure = 775 torr
Partial pressure of N₂ =?
Next, we shall determine the mole fraction of N₂. This can be obtained as follow:
Mole of N₂ = 1.45 moles
Moles the He = 0.659 mole
Total mole = 1.45 + 0.659 = 2.109 moles
Mole fraction of N₂ = Mole of N₂ / total mole
Mole fraction of N₂ = 1.45 / 2.109
Mole fraction of N₂ = 0.688
Gina, we shall determine the partial pressure of N₂. This can be obtained as follow:
Total pressure = 775 torr
Mole fraction of N₂ = 0.688
Partial pressure of N₂ =?
Partial pressure of N₂ = total pressure × mole fraction of N₂
Partial pressure of N₂ = 775 × 0.688
Partial pressure of N₂ = 533.2 torr.
Therefore, the partial pressure of N₂ is 533.2 torr.
As a future educator how will you handle a pupil who could possibly be a gifted child
Answers
Answer:
Learn how gifted students think. ...
Created tiered assignments for students. ...
Include a variety of levels in your classroom library. ...
Utilize their talents and interests. ...
Explore real-word application.
Anyone know the answer
Answers
Answer:
b
Explanation:
i know
Plzzz help me plz I am timed!!
Answers
Answer:
Explanation:
pretty sure its gaillieo
Answer:
Galileo
Explanation:
he was the first one to use a telescope
The solubility of magnesium phosphate at a given temperature is 0.173 g/L. Calculate the Ksp at this temperature. After you calculate the Kspvalue, take the negative log and enter the (pKsp) value with 2 decimal places.
Answers
Answer: [tex]K_{sp}=1.25\times 10^{-14}[/tex]
[tex]pK_{sp}=13.90[/tex]
Explanation:
Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as [tex]K_{sp}[/tex]
The equation for the ionization of magnesium phosphate is given as:
[tex]Mg_3(PO_4)_2\rightarrow 3Mg^{2+}+2PO_4^{3-}[/tex]
When the solubility of [tex]Mg_3(PO_4)_2[/tex] is S moles/liter, then the solubility of [tex]Mg^{2+}[/tex] will be 3S moles\liter and solubility of [tex]PO_4^{3-}[/tex] will be 2S moles/liter.
Thus S = 0.173 g/L or [tex]\frac{0.173g/L}{262.8g/mol}=0.00065mol/L[/tex]
[tex]K_{sp}=(3S)^3\times (2S)^2[/tex]
[tex]K_{sp}=108S^5[/tex]
[tex]K_{sp}=108\times (0.00065)^5=1.25\times 10^{-14}[/tex]
[tex]pK_{sp}=-log(K_{sp})=\log (1.25\times 10^{-14})=13.90[/tex]
The value of Ksp and pKsp for the given reaction is 1.25 × 10⁻¹⁴ and 13.90 respectively.
How we calculate the Ksp?Solubility product constant (Ksp) is define as the product of the solubilities of the products, present in any chemical reaction.
Given chemical reaction will be represented as:
Mg₃(PO₄)₂ → 3Mg²⁺ + 2PO₄³⁻
Solubility of Mg₃(PO₄)₂ = 0.173 g/L or 0.173g/L / 262.8g/mole = 0.00065mol/L
Now for the given reaction let we consider that solubility of Mg₃(PO₄)₂ be x, solubility of Mg²⁺ be 3x and solubility of PO₄³⁻ will be 2x and equation for Ksp will be written as:
Ksp = [Mg²⁺]³[PO₄³⁻]²
Ksp = [3x]³[2x]²
Ksp = 108[x]⁵
Now we pot the solubility value of x as the solubility of Mg₃(PO₄)₂ & we get,
Ksp = 108(0.00065)⁵
Ksp = 1.25 × 10⁻¹⁴
Now we calculate the value of pKsp as:
pKsp = -log(Ksp)
pKsp = -log(1.25 × 10⁻¹⁴)
pKsp = -(-13.90) = 13.90
Hence value of pKsp is 13.90.
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Determine the mass of hydrogen contained in 9.06 x 1024 H2O molecules.
Answers
Answer:
15.2 g H2
Explanation:
2H2O -> 2H2 + O2
9.06 x 10^24 molecules x (1 mol/6.022 x 10^23 molecules) x (2 mol H2/2 mol H2O) x (1.008 g/1 mol) = 15.2 g H2
The tablets were crushed, and 4.9993 g of the powder was transferred to a beaker and reacted with HCl. After filtration, the filtrate was transferred to a 100-mL volumetric flask and diluted with water. 20.00 mL of this stock solution were combined with 0.2 M Na3PO4. The resulting precipitate weighed 0.3451 g after drying. Calculate the moles of BiPO4 precipitated, the moles of Bi3 in the stock solution, and the mass of BSS per tablet.
Answers
Answer:
Explanation:
From the information given:
Mass of BiPO₄ = 0.3451 g
Number of moles of BiPO₄ = [tex]0.3451 \ g \ BiPO_4 \times \dfrac{1 \ mol \ BiPO_4}{303.95 \ g \ BiPO_4}[/tex]
[tex]= 0.001135 \ mol[/tex]
The number of moles of Bi³⁺ in 20.00 mL is:[tex]= 0.001135 \ mol \ BiPO_4 \times \dfrac{1 \ mol \ of \ Bi^{3+}}{1 \ mol \ BiPO_4}[/tex]
= 0.001135 mol of Bi³⁺
The number of moles of Bi³⁺ in 100 mL stock solution
[tex]= 0.001135 \ mol \ Bi^{3+} \times \dfrac{100 \ mL}{20.0 \ mL}[/tex]
[tex]= 0.005675 \ mol[/tex]
Mass of BSS in 4.9993 g tablets
[tex]m = 0.005675 \ mol \ Bi^{3+} \times \dfrac{1 \ mol \ BSS}{1 \ mol \Bi^{3+}} \times \dfrac{362.1 \ g \ BSS}{1 \ mol \ BSS}[/tex]
m = 2.055 g BSS
Mass of BSS in 5.0103 g (5 tables)
[tex]m = 2.055 g \ BSS \times \dfrac{5.0103 \ g}{4.9993 \ g}[/tex]
= 2.06 g
∴
The mass of BSS per tablet is [tex]=\dfrac{2.06 \ g}{5 \ tablet}[/tex]
= 0.412 g BSS/ tablet
How much energy is required to vaporize 1.5 kg of aluminum? (Refer to table
of latent heat values.)
A. 733 kJ
B. 1650 kJ
C. 7095 kJ
D. 600 kJ
Answers
Answer:
B 1650
Explanation:
Scientists have developed a new way to extract natural gas, called hydraulic fracturing, or fracking. Which of these is a positive impact of this method?
A. Decreased habitat
B. Decreased earthquakes
C. Increased supply
D. Increased demand
Answers
Answer:
The answer is C if its wrong you can report my answer I'm 100% sure its C
When planning a simple experiment, what does it mean to “test one variable”?
a During the experiment, the scientist keeps the control the same but changes many other elements he or she is testing.
b During the experiment, the scientist has only one element, or variable, that is changed to test the hypothesis.
c The scientist can only use simple language and materials when planning the one variable to be tested.
d The scientist plans and performs just one science experiment a day to test one variable.
Answers
Answer:
I believe the answer is "b". "During the experiment, the scientist has only one element, or variable, that is changed to test the hypothesis."
Explanation:
I remember from last year but I'm not totally sure. Good luck!
The experimental setup has been the design that includes the experimental and the control group. during the experiment, only one variable is changed to test the hypothesis. Thus, option b is correct.
What is experimental design?The experiment design includes the testing of the hypothesis to solve the problem and reach the solution through the analysis of the observations. It has been the setup that includes the test and the control group that involves the dependent, independent, and controlled variables.
Testing one variable in the experimental designs means changing one of the elements of the experience to prove the reliability of the hypothesis. This variable is the factor that alters and affects the other factors of the experiment and leads to a cause and effect.
The result of the effect of the hypothesis proves the testability of the experiment and provides solutions to the research question. This further leads to the formulation of the law and theory.
Therefore, option A. testing one variable involves proving the hypothesis.
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