Multimeter conducts like a big resistor. Since current will be very low due to the very high **resistance**, the circuit's overall current won't be impacted in the slightest. It will transmit the appropriate voltage

A passive electrical device known as a resistor adds **resistance **to the flow of electric current. They can be discovered in virtually all electrical networks and electronic circuits. One ampere of current (A) and a one volt (V) drop across a resistor's terminals produce an ohm, which is the resistance that results. The voltage at the terminal ends determines the current in a direct proportion. **Ohm's **law demonstrates how to calculate this ratio. Multiple applications exist for resistors. Among some examples are voltage division, heat generation, matching and loading circuits, current limiters for electric current, gain control, and time constant setting. With resistance values spanning a range of more than nine orders of magnitude, they are readily available on the market. Units of resister is **omhs.**In the International System of Units, the **ohms **serves as the reference unit for electrical resistance.

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imagine another solar system, with a star of the same mass as the sun. suppose a planet with a mass twice that of earth (2mearth) orbits at a distance of 1 au from the star. what is the orbital period of this planet? view available hint(s)for part a imagine another solar system, with a star of the same mass as the sun. suppose a planet with a mass twice that of earth (2mearth) orbits at a distance of 1 au from the star. what is the orbital period of this planet? 2 years it cannot be determined from the information given. 6 months 1 year

1year is the **orbital period** of this planet.

The **orbital period** is the quantity of time a given astronomical object takes to complete one orbit around every other object. In astronomy, it generally applies to planets or asteroids orbiting the solar, moons orbiting planets, exoplanets orbiting different stars, or binary stars.

**Kepler's third law** - indicates the relationship among the length of an items orbit and the common distance that it's far from the issue it orbits. this could be used for something clearly orbiting round another factor.

Entire **revolution **is known as the orbital duration. At 200 km that is approximately ninety minutes. The orbital duration will increase with altitude for two motives. First, as the altitude increases, Earth's gravity decreases, so the orbital speed had to stability it decreases.

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a gun with a muzzle velocity of 100 m/s is fired horizontally from a tower. neglecting air resistance, how far will the bullet fall 1 second later (vertical distance) ? * 1 point a) 5 m b) 50 m c) 100 m d) 490 m e) none of these

option c A gun is fired horizontally from a tower with a muzzle **velocity** of 100 m/s. The bullet will arrive **100m **away and arrive 1 second late if air resistance is ignored.

That is not to argue that there isn't a **velocity **increase. It absolutely depends on the specific firearm, cartridge, and loading in question. The reason for an increase in velocity is that the **pressures **are slightly higher, which causes the bullet to move less before engaging the rifling.

However, a significant improvement in accuracy is what many handloads will discover. A smaller distance to the rifling reduces the possibility of any bullet tipping and the variation in breech **pressures **that exists between different rounds. From round to round, slightly variable **pressures **can and will be produced even with equal powder loads, down to less than 1/10th of a grain. It's a simple reality.

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When engineers consider the forces that can act on a structure, they must think about all parts of the structure. Describe three different places on a bridge that would experience very different forces.

Any **bridge** is subject to three different types of **forces**: the **dead** **load**, the **live** **load**, and the **dynamic load**. The weight of the bridge itself is discussed in the first of these words.

Any of the four fundamental forces in physics—gravitational, **electromagnetic**, strong, and weak—that control how objects or particles interact as well as how some particles decay—is referred to as a **fundamental** **force**, also known as a fundamental interaction.

**Compression** and **tension** are the two main forces that are ever-present on a bridge. A **force** that compresses or shortens the object it is acting on is known as a **compressive** **force**. A force known as tension or tensile force works to stretch or expand the object it is acting on.

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Ask Tutor a question about your assignment

The current in each **branch** of the circuit is **9.5 A** and** 0 A**.

Point B, according to Kirchoff's** junction** law equation is

**i = i₁ + i₂ ** ......equation 1

Now, according to Kirchoff's **Loop** law,

Loop 2 is anticlockwise, calculates the current i₂ equation is

21.4 - 50i₂ - 6 - i - 100i₂ = 0

**150i₂ + i = 15.4** ......equation 2

Loop 1 is clockwise, calculates the current i₁ equation is

20.5 - 30i₁ - 6 - i - 40i₁ - i₁ = 0

**80i₁ + i = 14.5 ** ........equation 3

substitute equation 1 in equation 3 for the value of i,

81i - 80i₂ = 14.5 .....equation 3

Upon, subtracting equation 3 from equation 2, we get **i₂ = 9.5 A **

substituting the value of i₂ in equation 3, we get i = 9.5A

Hence on substituting value for i₁, in equation 1 , we get **i₁ = 0 A **

Hence, the** current **in each branch of the circuit is **9.5A, 9.5A, 0A**

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A medium-sized jet has a 3. 8-m-diameter fuselage and a loaded mass of 85,000 kg. The drag on an airplane is primarily due to the cylindrical fuselage, and aerodynamic shaping gives it a drag coefficient of 0. 37.

To travel at 230 m/s at an altitude where the** air density **is 1.0 kg/m3, the jet's engines must deliver** 111kN** of thrust.

**Air Density** is defined as the mass of an object, including air, divided by its volume.

Scientists measure density in terms of kilogrammes per cubic metre when using the metric system.

The density of the air is influenced by its **temperature**, pressure, and water vapour content. We'll discuss dry air initially, so just **temperature **and pressure will be a concern.

In addition to a fundamental explanation of air density, we will go into how humans are affected by decreased air density, such as that experienced at high altitudes, how humidity influences air density in unexpected ways, and how air density affects things like aircraft, baseballs, and even racing automobiles.

The density of the air in a free environment drops as **temperature **increases.

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Which of the following statements is most true regarding the use of testimony on hair samples in courts today?

We may not consider the use of** hair samples **today because **DNA **analysis is more modern.

The term **DNA **refers to the molecule that contains the** genetic material **of the living things. Hence, we could use the DNA sample to be able to solve very difficult cases. This is because the DNA sample can be able to tell the exact identity of the person that involved,

Before the advent of the DNA, the hair sample was one of the very reliable ways be which evidence could be gathered to solve crimes. Hence; Modern** DNA analyses** have made testimony using hair samples obsolete.

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Missing parts;

Hair samples are replacing DNA as an easily available, go-to source for identifying suspects

Modern changes in the discipline mean that any police officer can provide testimony on hair samples

Modern DNA analyses have made testimony using hair samples obsolete

There’s solid research that should lead us to be skeptical of testimony based on hair samples

With low-frequency stimulation, the muscle relaxes fully between contractions, resulting in ____________ twitches per stimulus.

With low-frequency stimulation, the muscle relaxes fully between contractions, resulting in **identical twitches** twitches per stimulus.

**Alpha motor** neurons are the** motor neurons** that innervate the fibers of the skeletal muscle. A number of branches, each innervating a different muscle fiber, are formed as the alpha motor neuron enters the muscle. A motor unit is made up of one** alpha motor** neuron and all of the muscle fibers it innervates. Small motor units with 3-5 muscle fibers per** motor neuron** are found in muscles that are involved in delicate, coordinated control. Our hand and eye muscles, as well as those that control eye movement, have very small motor units.

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A man pulls a crate with a rope. The crate slides along the floor in the horizontal direction (x direction). The man exerts a force of 50 N on the rope, and the rope is at an angle . Describe how the force components change as the angle increases from 0° to 90° and use your graph to explain your answer. Give a detailed explanation of the forces at . Show a sample calculation at one angle for both components.

The 50 N force applied at an angle to the **crate** may be broken down into horizontal and vertical force components. As the angle created by the rope, e, increases from 0° to 90°, the horizontal component, Fx, drops and the vertical force component, Fy, increases.

The **components** of a force are the force parts acting in perpendicular directions, horizontal and vertical, that combine to give the specified force.

The **direction** the crate is sliding = The horizontal, x-direction

The force exerted by the man = 50 N

The angle of the rope

The components of the force are therefore:

Horizontal component, Fx = 50 × cos(8)

Vertical component, F₁ = 50 x sin(0)

The value of cos(e) and sin(e) as the angle the rope makes with the horizontal,

e, increases from 0° to 90° are as follows:

Therefore, the horizontal component of the force exerted by the man, Fx has a maximum value at = 0, and decreases to 0, as increases from 0° to 90°.

The vertical component of the force exerted, Fy, has a minimum value of O at → = 0°, and the value of sin(e) and therefore Fy, increases to a maximum of (sin(90°) 1) 50 N as increases to 90°.

Please find attached the graph showing the components of the force, Fx, and Fy, exerted by the man as the angle formed by the rope increases from 0° to 90°

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A 750 resistor in a circuit has a current flowing through it of 2.0 A. What is

the power dissipated by the resistor? (Use P=OVI = /²R= VR)

OA. 300 W

B. 150 W

C. 38 W

D. 450 W

The **power **dissipated by the resistor is** 3000W.**

**Electrical power**, or (P), in a circuit is a unit of measurement for the rate at which energy is consumed or produced inside a circuit. The energy produced or delivered by an **energy source**, such as a **voltage**, is absorbed by the associated load.

In physics, power is referred to as the rate of **energy conversion **or transfer over time. The unit of power in the** SI system, **often known as the **International System **of **Units**, is the** Watt (W).** A single joule per second is one watt. Power was formerly referred to as activity in some research. A **scalar quantity** is **power.**

The resistor's **power **dissipation can be computed as P = I²R

here ,

I = 2 A

R = 750

Therefore P= **2² x 750 W**

**= 3000W**

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a 40.0-kg child and an 8.40-kg sled are on the surface of an icy lake 15.0 meters apart. the child exerts a 5.20 n force on the sled towards them via a rope they’ve attached.

**Acceleration** of the sled is 0.62m/s^2

Acceleration of the **child** is 0.13m/s^2

They **met** at 2.6m from the child's initial position

The question is incomplete, the complete question is given below:

a 40.0-kg child and an 8.40-kg sled are on the surface of an icy lake 15.0 meters apart. the child exerts a 5.20 n force on the sled towards them via a rope they’ve attached.(a) What is the acceleration of the sled? m/s2(b) What is the acceleration of the child? m/s2(c) How far from the child's initial position do they meet? m

Part a

Acceleration of the sled:

Mass of sled=8.40kg

**Force=**5.20N

Acceleration=F/m

=5.2/8.4

=0.62m/s^2

Part b

Acceleration of the child

Mass of the child=40kg

Force=5.20N

Acceleration=F/m

=5.2/40

=0.13m/s^2

Part c

Distance from the child's initial position they met

They accelerate towards each other at =0.62+0.13

=0.75m/s^2

The time to meet is given by:

We use **kinematic **equation to find this,

s=ut+1/2at^2

u=0m/s^2

a=0.75m/s^2

s=15m

t=?

15 =0*t+ (1/2) (0.75) t^2

15=(1/2)*0.75t^2

t=6.32 sec

The child moves:

s=ut+1/2at^2, u=0, a=0.13, t=6.32

=(1/2) (0.13) 6.32^2

=2.6m

Hence they met at 2.6m from the child's original position

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Help! A car is traveling at 60 km/h. It accelerates to 85km/h in 5 seconds. What is the acceleration of the car?

A Car is travelling at a speed of 60 km/h and then **accelerates** to the velocity 85 km/h than **acceleration** in 5 sec is given by 18000 km/h² .

**Acceleration** of body is defined as rate of change of the **velocity** with respect to the time. **Acceleration** is a vector quantity it have magnitude as well as direction.

**Acceleration** = (final **velocity** - initial **velocity** )/ time

**Acceleration **= change in velocity / change in time

Given that in the question that the **velocity** changes from 60 km/h to 85 km/h in 5 sec =( 0.00138 h ) then the **acceleration** of the car is given as,

**Acceleration **of the car = (60 - 85)/0.00138

**Acceleration **of the car = 18000 km/h²

**Acceleration** of the car travelling with the **velocity **60 km/h to final the **velocity** 85 km/h in time 5 sec is given by 18000 km/h².

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what is the speed of the book when it reaches the hands? (b) if we substituted a second book with twice the mass, what would its speed be? (c) if, instead, the book were thrown down, would the answer to (a) increase, decrease, or remain the same?

Anything thrown from a structure, you have a downward velocity if you throw it down correctly. Additionally, you have little G, thus the ball will keep **accelerating**. As a result of the acceleration, your final velocity will undoubtedly be much higher.

At the bottom of the structure, a book is currently being dropped; a man is standing nearby with his hands extended in a very linear motion. The height of these arms is also determined, de Unlike this book, which stands at a specific height Big D The weight of this book has increased to two kilograms. two kg. This small D is equivalent to one point five meters on the issue whereas this enormous D is equal to ten meters of wire. seeks to know the speed at which it will reach this person's grasp.

We have a starting **energy **and a finishing energy. We also have one more energy. We only have gravitational potential energy, after all. What is our final energy, then? The book is falling, so we have kinetic energy, and since Cromwell is not written in it, we have gravitational potential energy. really easy Therefore, we have M g Big D, followed by 1/2 em, the last square, and M g Little T. What should we do next, then? really easy As a result of our velocity solution, the final square's mg big d minus m g tiny d is equal to 1/2.

Therefore, the final square is equal to two times mg big D, minus mg small D, and you merely need to solve for V divide. I divide by an, you square root it, and the result is equal to two mg large D minus two mg little D all over.

Because if you thought about this properly, your speed would increase. You must simply consider anything. anything falls from a structure. If you throw it down correctly, it will move downward at a speed. Furthermore, since you have little G, the ball will keep **accelerating**. Because it is **accelerating**, it follows that your final velocity will be much higher.

Both your initial kinetic energy and your gravitational potential energy would be present, as would your final kinetic **energy **and gravitational potential energy. Because it is at its highest point, you would have a 1/2 M V initial square plus M g Big D and he would have a 1/2 em final square plus M g tiny. +00 It's not a huge D or small D now that it's in their palm. Therefore, the answer would alter. Your speed would actually rise, in my opinion, if you give this some careful thought. You only need to consider anything.

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two ice skaters stand facing each other at rest on a frozen pond. they push off against one another and the 61 kg skater acquires a speed of 0.75 m/s. if the other skater acquires a speed of 0.89 m/s, what is her mass in kilograms?

The **mass **of the other skater who is pushed is 51.4 kilograms.

According to the** law of conservation of momentum,**

The total linear momentum is always conserved in a system if no external force is applied.

So. we can write,

**Initial momentum **=** final momentum**

Initial momentum is zero as both the skater are at rest.

So, Final momentum should be 0,

Final momentum = 0

M₁V₁ + M₂V₂ = 0

M₁ is the mass of first skater,

V₁ is the final speed of the first skater,

M₂ is the mass of the second skater,

V₂ is the final speed of the second skater, V₂ will taken as negative because the second skater is pushed into opposite direction,

Putting all the values,

61(0.75) = -M₂(-0.89)

M₂ = 51.4 Kg.

So, the **mass **of the skater is 51.4 kg.

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One tank of goldfish is fed fish food once a day. A second tank is fed twice a day, and a third tank is fed food four times a day during a six week study. The weight of each fish is recorded daily.

The dependent variable in the experiment in which the **weight of each fish** is recorded daily is the fish' weight.

A **dependent variable** is the variable that cannot be controlled in an experiment. An independent variable is the controllable variable/factor in an experiment.

In this experiment, the amount of food fed and how often the food fed can be controlled. The **fat gained** by the fish and the weight of fish cannot be controlled.

Therefore, in this experiment the dependent variable is **weight of fish.**

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what is the power of 600 joules of work done in 4 seconds?responses 150 watts 150 watts 240 watts 240 watts 600 watts 600 watts 2,400 watts

**150 Watts **is the **power** of 600 J of** work** completed in 4 seconds.

The **rate** at which **work** is completed is referred to as **power**. It has the following **mathematical** expression:

[tex]Power = work/time[/tex]

The **power** can be obtained using the above **formula**.

From the mentioned query, the following **information** was observed:

**Work** = 600 J

**Time** = 4 s

**Power** =?

[tex]Power = Work/Time \\Power = 600/4[/tex]

**power** = 150 watts

Thus, 150 **Watts** are generated by 600 J of **work** completed in 4 seconds.

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When we see saturn going through a period of apparent retrograde motion, it means.

In its orbit, **Earth **is passing** Saturn,** with both planets on the same side of the Sun.

**What is apparent retrograde motion?**

When a planet appears to be moving backward relative to other bodies in its solar system when viewed from a certain angle, this is known as **apparent retrograde motion.** Motion in the same direction as other bodies is referred to as direct motion or prograde motion.

Mars typically looks to be traveling to the left of the stars. **Mars**, however, moves right in relation to the **stars **during** "retrograde motion"** periods. Truth be told, that is only an illusion that lasts for around two years. In reality, **Earth** is orbiting the **Sun** and is currently passing past Mars. **Mars** is only occulted by Earth once every 26 months since it orbits the Sun more closely and moves quicker than Mars. **Mars** typically moves from west to east in the sky, but when Earth passes in front of it, we see it move from east to west, creating the impression that it is going backward.

Hence, the earth is passing **Saturn** in its orbit, with both planets on the same side of the Sun.

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we will explore more this equation. we need to solve this for all masses! you should recognize now that this system of linear equations can be written in a matrix form. we will define the variable

The coefficients of the variables in each equation can be arranged in a row to create the coefficient **matrix**. A constant term should always be written on the right in standard form for each equation.

A coefficient matrix, a variable matrix, and a constant **matrix **can all be used to describe a system of linear **equations **in matrix form.

Think about the system,

2x+3y=8

5x−y=−2

X and Y are the variables that we have. As a result, the variable **matrix **can be written as [xy].

The constant terms from the equations, 8 and 2, are on the right side of the equivalence. The first and second rows of the constant matrix are occupied by the two integers in that order since they are the ones that correspond to the first and second **equations**. The matrix then takes the form [82].

The system is now represented by the equation [2531] [xy] = [82].

Now, the system is denoted as [2531] [xy]=[82].

You can see that the matrix representation is identical to the system of **equations **using matrix multiplication.

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Q2. A stone leaves a slingshot horizontally with an initial speed of 15.2 m/s from a

height 1.1 m above the ground. Determine the stone's:

a) total air time

b) maximum height

c) range

d) final velocity

Horizontal

VX =

dx = ?

t = ?

Vertical

dy = -1.1m

v1y =

v2y= ?

a =

t = ?

**Answer:**

Assume that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex]. Also assume that that the air resistance on this stone is negligible.

The total air time of this stone is approximately [tex]1.5\; {\rm s}[/tex].

The maximum height of this stone is [tex]1.1\; {\rm m}[/tex], same as the height of the slingshot.

The range of this stone is approximately [tex]23\; {\rm m}[/tex].

The final velocity of this stone is approximately [tex]21\; {\rm m \cdot s^{-1}}[/tex].

**Explanation:**

If the air resistance on this stone is negligible, this stone will accelerate towards the ground with a **vertical acceleration** [tex]a_{y}[/tex] of [tex]a_{y} = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}[/tex].

At the same time, the **horizontal velocity** [tex]v_{x}[/tex] of this stone will stay the same during the entire flight: [tex]v_{x} = 15.2\; {\rm m\cdot s^{-1}}[/tex].

The stone was launched from a height of [tex]1.1\; {\rm m}[/tex] above the ground. Therefore, the **vertical displacement** [tex]x_{y}[/tex] of the stone will be [tex]x_{y} = (-1.1)\; {\rm m}[/tex] when the stone hits the ground.

The **initial vertical velocity** [tex]u_{y}[/tex] of this stone would be [tex]u_{y} = 0\; {\rm m\cdot s^{-1}}[/tex] since the stone was launched horizontally.

Let [tex]v_{y}[/tex] denote the **final vertical velocity** of this stone right before landing. Apply the SUVAT equation [tex](v_{y})^{2} - (u_{y})^{2} = 2\, a\, x[/tex] to find [tex]v_{y}\![/tex]:

[tex](v_{y})^{2} - (u_{y})^{2} = 2\, a\, x[/tex].

[tex](v_{y})^{2} = (u_{y})^{2} + 2\, a\, x[/tex].

[tex]\begin{aligned}v_{y} &= -\sqrt{(u_{y})^{2} + 2\, a\, x} \\ &= -\sqrt{0^{2} + 2\, (-9.81) \, (-1.1)}\; {\rm m\cdot s^{-1}} \\ &\approx -14.6908 \end{aligned}[/tex].

(Final vertical velocity [tex]v_{y}[/tex] is negative since the stone is travelling downwards toward the ground.)

Let [tex]t[/tex] denote the duration of this flight. Apply the SUVAT equation [tex]t = (v_{y} - u_{y}) / (a)[/tex] to find [tex]t\![/tex]:

[tex]\begin{aligned} t &= \frac{v_{y} - u_{y}}{a} \\ &\approx \frac{(-14.6908) - 0}{(-9.81)}\; {\rm s} \\ &\approx 1.49753\; {\rm s} \end{aligned}[/tex].

In other words, this stone was in the air for approximately [tex]1.5\; {\rm s}[/tex].

Also because the stone was launched horizontally, the vertical velocity of this stone started at [tex]u_{y} = 0\; {\rm m\cdot s^{-1}}[/tex] and became negative (toward the ground) immediately after.

Hence, this stone would not have travelled upward during the entire flight. The height of this stone would be maximized immediately after the stone was launched: [tex]1.1\; {\rm m}[/tex].

Multiple the horizontal velocity [tex]v_{x} = 15.2\; {\rm m\cdot s^{-1}}[/tex] of this stone by the duration of the flight [tex]t \approx 1.49753\; {\rm s}[/tex] to find the **range** (horizontal displacement) of this stone:

[tex]\begin{aligned} (\text{range}) &= v_{x}\, t \\ &\approx (15.2\; {\rm m\cdot s^{-1}})\, (1.49753\; {\rm s}) \\ &\approx 23\; {\rm m} \end{aligned}[/tex].

Right before landing, the stone would be travelling with a vertical velocity of [tex]v_{y} \approx (-14.6908)\; {\rm m\cdot s^{-1}}[/tex] and a horizontal velocity of [tex]v_{x} = 15.2\; {\rm m\cdot s^{-1}}[/tex]. Apply the **Pythagorean Theorem** to find the overall velocity of this stone at that moment:

[tex]\begin{aligned} v &= \sqrt{{(v_{x})}^{2}\, {(v_{y})^{2}} \\ &\approx \sqrt{(15.2\; {\rm m\cdot s^{-1})^{2} + (-14.6908)^{2}}\; {\rm m\cdot s^{-1}} \\ &\approx 21\; {\rm m\cdot s^{-1}} \end{aligned}[/tex].

a system of diatomic ideal gas contracts from a volume of 4.1 m3 to a final volume of 1.3 m3. if the process proceeds at constant pressure of 148 kpa, calculate the energy in kj transferred by heat, where positive is energy transferred into the system, and negative is energy transferred out of the system.

A system of **diatomic ideal gas** contracts from a volume of 4.1 m3 to a final volume of 1.3 m3. if the process proceeds at constant pressure of 148 kpa. The energy transferred by heat, where positive is energy transferred into the system, and negative is energy transferred out of the system is(Q)= 1450.4 KJ

**Energy** is a physical term that means if a force is applied on a object and the object move some distance that means there is some energy is generate in that object. It is a vector quantity. It can be measured in Joule.

To calculate the energy we using the formula,

Q = nCp AT

Or, Q = nCp(T₂-T₁)

Or, Q = nCp[P(V₂ - V₁) /nR] ....eq(1)

Here we are given,

V₁ =Initial volume = 4.1 m³

V₂= final volume = 1.3 m³

Process is isobaric so,

p= Constant pressure= 148 kP = 148 x 10³ P

n = Number of moles = 1

Cp= specific heat at constant pressure.

For diatomic molecule Cp = 7R/2

we know, AT = T₂-T₁

From ideal gas equation

PV = nRT

T = PV/ nR

T₁= PV₁/nR

And T₂ = PV₂/nR

Now to calculate energy = Q in KJ transferred by heat at constant pressure.

Substitute all these values in eq (1)

Q = n(7R/2) [P(V₂ - V₁) /nR]

Or, Q = 7P(V₂ - V₁)/2

Or, Q = 3.5(148 × 10³ P) (4.1- 1.3) m³

Or, Q = 1450.4 x 10³ J ........(P.m3 = J)

Or, Q = 1450.4 KJ

From the calculation we can say that, The energy transferred by heat, where positive is energy transferred into the system, and negative is energy transferred out of the system is(Q)= 1450.4 KJ

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which color is bent the least by prism

The red light is the least refracted by the **prism.**

Each beam of light with a particular wavelength is slowed differently by the glass. Since violet light has a shorter** prism **wavelength, it is brake more than the longer wavelengths of red light. accordingly, violet light is bent the most while red light is bent **prism** the least.** Prism** on dispersion, the light rays with longer wavelengths bend less than ones with shorter wavelengths. Since red has the longest wavelength, it bends the least.** prism** Among the 7 constituent colors of light, violet light has the least wavelength and hence it deviates the most, and red light having the largest wavelength deviates the least. Hence, **prism **the required order is violet, indigo, blue, green, yellow, orange, and red.

So we can conclude that in a **prism**, the red light is less refracted.

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a plane is flying horizontally with speed 198 m/s at a height of 3210 m above the ground, when the package is dropped from a plane. The acceleration of gravity is 9.8 m/s^2.

a second package is thrown downward from the plane with a vertical speed v1=78m/s. what is the magnitude of the total velocity of the package at the moment it is thrown as seen by an observer on the ground? answer in units of m/s.

The magnitude of the total **velocity** of the package at the moment it is thrown as seen by an observer on the ground is D = 193m/s 15.2s = 2934 m.

What is **velocity ?**

**velocity ** is the prime indicator of the position as well as the rapidity of the object

Sol-

1. 0.5gt^2 = 2010 m.

4.9t^2 = 2010.

t = 20.3 s. = Fall time.

D = Xot. = 193m/s 20.3s = 3909 m.

2. V=sqrt(Xo^2+Yo^2)=sqrt(193^2+58^2) = 202 m/s.

3. Vot + 0.5gt^2 = 2010 m.

58t + 4.9t^2 = 2010.

4.9t^2 + 58t - 2010 = 0.

Use the **quadratic ** formula we are get

t = 15.2 s. = Fall time

D = 193m/s 15.2s = 2934 m.

D = 193m/s 15.2s = 2934 m.

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True or false Condensation occurs with the removal of thermal energy.

true. condensation is when gas converts to liquid. the molecules move slower because of a loss of thermal energy, so it forms liquid

a typical insulation resistance of equipment rated 480v is . select one: a. 10 m ohms b. 50 megohms c. 100 megohms d. 1,000 megohms

All different kinds of electrical wires and cables are routinely tested by measuring **insulation **resistance. This test is frequently used as a customer acceptance test in production settings.

This **test **is frequently used as a customer acceptance test in production settings, with the customer frequently defining the minimum **insulation **resistance per unit length.

In contrast to a real HIPOT **test**, the results of the IR **Test **are meant to provide information on the quality of the bulk insulation material rather than being helpful in identifying specific insulation flaws.

Many wire and cable manufacturers use the** insulation **resistance test to track their insulation manufacturing processes and identify emerging issues before process variables stray outside of permitted limits, even when it is not needed by the end customer.

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a plane circular coil of radius 0.77 m lies in a horizontal plane. it carries a current of 4.38 a. the coil is in a uniform horizontal 1.157-t magnetic field. what is the magnitude of the magnetic torque on the coil? calculate the torque in the units of n.m. write your answer in decimal form with three digits to the right of the decimal point (e.g. 5.374); do not write any units.

The **magnitude** of the magnetic **torque **on the coil is 9.435 Nm.

A **magnetic field **exerts a **torque **that tries to align the normal vector of a loop of current with the magnetic subject. the size of the torque on a loop

The **magnetic torque**, τ, skilled by using a unmarried particle of quantity V and domain magnetization Md whose moment is oriented at attitude θ to carried out induction B is given by means of τ=mHsinθ where m=MdV is the magnetic second of the particle.

This is the **torque **on a modern-wearing loop in a uniform **magnetic field**. This equation can be proven to be valid for a loop of any form. The loop includes a modern I, has N turns, every of area A and the perpendicular to the loop makes an angle θ with the field B.

Calculation:-

τ = μ×B

= I A B sin90°

= 4.38 × 3.14×(0.77)²× 1.157

= 9.435 N m.

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PLEASE HELP!!! WILL MARK BRAINLIEST

The environmental impact of the changes in the amount of **energy resources** is reduction in **air pollution.**

**Energy resources** are the materials that can act as sources of energy which is grouped into two namely:

From the given figures,

In 2014 renewable energy = 19%; while in 2015 it is = 25%

In 2014 non renewable energy when added = 79%; while in 2015 it is = 73%

This shows that there was reduction in the use of non renewable energy from 2014 to 2015 by 6%.

This would affect the environment positively as there would be **reduction** in **air pollution** caused by non renewable energy resources.

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18. How might the cycling of matter in Earth’s atmosphere be related to to the movement of dust from the Sahara desert to the Amazon?

This is Science

The** cycling of matter** in Earth’s atmosphere is related to the movement of dust from the Sahara desert to the Amazon because the **biosphere **is a major ecosystem that connects all **ecosystems **around the world.

The **ecosystems **are specific geographic regions in which biotic factors (life) and abiotic factors (e.g. dust) interrelate to shape the environmental condition of the area, while the term biosphere makes reference to a major ecosystem that connects all these region in the world.

Therefore, we can conclude that ecosystems are interconnected to shape the **biosphere**, thereby the phenomena that occur in Sahara desert are able to modify the conditions in a Forest like Amazon.

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5.12 ** consider a simple harmonic oscillator with period r. let ( f ) denote the average value of any variable f (t), averaged over one complete cycle: 1 f (f)

considering simple** harmonic oscillator** with period r E=1/2mw²A² , T= 1/4mw²A² V = 1/4mw²A² therefore **T=V=E/2.**

A model with numerous significant applications in both conventional and quantum mechanics is the **harmonic oscillator**. It acts as a model for the mathematical analysis of a wide range of phenomena, including elasticity, acoustics, AC circuits, molecular and crystal vibrations, electromagnetic fields, and the optical characteristics of matter. A body is referred to be a linear harmonic oscillator or a simple harmonic oscillator when it oscillates about its location along a linear straight line under the influence of a force that is directed towards the mean location and is proportionate to the **displacement **at any moment from this location. Periodic motion is best demonstrated by this type of oscillation. The period is completely independent of the initial **displacement **from equilibrium (amplitude of oscillation). The period is unaffected by how far the cart is moved from its equilibrium location. the greatest **displacement **from the mean position, is the angular speed of the body rotating around in a circle, and t is the duration.

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an electron of mass 9.11 3 10231 kg has an m initial speed of 3.00 3 105 m/s. it travels in a straight line, and its speed increases to 7.00 3 105 m/s in a dis- tance of 5.00 cm. assuming its acceleration is constant, (a) determine the magnitude of the force exerted on the electron and (b) c

a. The magnitude of the **force **exerted on the electron F = 3.64*10^-18N

b. The force F is 4.08*10^11 times the weight of the electron

a. In order to calculate the magnitude of the **force **exerted on the electron you first calculate the acceleration of the electron, by using the following formula:

v: final **speed **of the electron = 7.00*10^5 m/s

vo: initial **speed **of the electron = 3.00*10^5 m/s

a: acceleration of the electron = ?

x: distance traveled by the electron with certain **speed**= 5.0cm = 0.05m

you solve the equation (2) for a and replace the values of the parameters:

[tex]a=v^{2} - V^{2} /2x[/tex]

a=4×10^12 m/s²

to calculate the force we now use the second Newton law :

F=ma

m: mass of the electron = 9.11*10^-31kg

F=3.64*10^-18N

The magnitude of the force exerted on the electron is 3.64*10^-18N

b. given weight of electron is :

Fg=mg

Fg = 8.92*10^-30N

The Division between the force electron and the weight of the electron F is:

F/Fg=4.08*10^11

The force F is 4.08*10^11 times the weight of the electron

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use letter B below to explain what is wrong with the orbital diagram for beryllium

Electronic Configuration:

Normally, the electronic configuration will be written through the atomic number of the particular element. The electrons fill in this accruing to the energy level and orbitals like s, p, d, and f

The atomic number for the Beryllium is 4. So, the electronic configuration of beryllium is

[tex]1s^22s^2[/tex]In option B, the s block has two electrons and both are having an upward spin orientation. This is incorrect, as one must be in the upward orientation and the other will be in the downward orientation

At a gas is in a container with a constant temperature pressure change cause the volume to decrease based on the relationship between pressure and volume what must happen to the pressure

At constant** temperature pressure **is inversely proportional to volume, so pressure will increase.

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