The greatest **stress** that a material can withstand before failing is referred to as its strength. Its stiffness describes how much it will flex or bend when pulled. High strength is frequently found in materials with high stiffness. The greatest stress that a **material **can withstand before failing is referred to as its strength.

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If u drop a ball from a tower 6 miles up where will it land

A- Alongside the tower

B-Fall upward into space

C-Downward into space

D- It will circle around the earth

The **ball** will land alongside the **tower** due to the **gravitational pull** of the **earth**. Therefore, option (A) is correct.

**Gravity** is a force that attracts any physical body which has mass towards the **center** of the **earth**. Everybody having **mass** exerts a force or gravitational pull on every other object with mass. Gravity is the reason the **planets** orbit the sun as well as the **moon** orbits the earth.

Every particle of **matter** in the **universe** attracts every other particle with a specific force, and that **force** is directly proportional to the product of the masses of those particles.

Mathematical expression for gravity can be written as:

[tex]F= G\frac{mM}{r^2}[/tex]

Where F is the **force** between objects, m and M are **masses** of objects interacting, the **distance** between the center of the masses is equal to 'r' and, G is the **gravitational** constant.

When you drop a ball from a tower 6 miles up it will land back on the surface of the earth **alongside the tower **due to the **gravitational pull **of the earth.

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An object starts at rest and experiences a constant acceleration of 4 m/s² for 3 seconds.

Sketch the acceleration-time graph for this object.

1. What was the initial velocity of the object?

2. What was the velocity of the object after 1 second?

3.What was the velocity of the object after 2 seconds?

4.What was the velocity of the object after 3 seconds?

5. Sketch the velocity-time graph for this object.

6. What was the average velocity of the 1st second?

7.What distance did the object travel in the 1st second?

8. What was the average velocity of the 2nd second?

9. What distance did the object travel in the 2nd second?

10.What was the average velocity of the 3rd second?

11. What distance did the object travel in the 3rd second?

12.Sketch the position-time graph for this object.

13.What was the displacement of the object?

14.What was the distance travelled by the object?

For the given **acceleration **and **time**, following are the different **velocities**.

Given:

**acceleration **a = 4 m/s²

time t = 3 sec

initial velocity u = 0 [ starts from rest ]

let final velocity be = v

Therefore according to the question,

**velocity **after 1 sec :

v = u + at

v = 0 + 4 x 1

v = 4m/s ( after 1 sec)

**Velocity **after 2 secs

v = 0 + 4 x 2

v= 8m/s (after 2 sec)

**Velocity **after 3 secs

v = 0 + 4 x 3

v = 12m/sec

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in an elastic collision, a 400-kg bumper car collides directly from behind with a second bumper car traveling in the same direction. the mass of the leading bumper car is 30.0% greater than that of the trailing bumper car. the initial speed of the leading bumper car is 5.60 m/s and that of the trailing car is 6.00 m/s.

According to momentum conservation momentum before collision is equal to momentum after **collision**. velocity of trailing care after collision** v1=5.047 m/s **velocity of leading can after collision** v2=5.947 m/s** .

In physics, a **collision**, which is also known as an impact, is the abrupt, violent coming together in close proximity of two bodies, such as two pool cues, a golf club and a ball, a hammer and a nail, two railroad cars when linked, or a falling object and a floor. The **force **and the amount of time the objects are in touch, in addition to the materials the two objects are made of, have an impact on the outcome of the impact. It is generally knowledge that a hard steel ball dropped on a steel plate would rebound almost to the original position from where it was dropped, while a ball made of putty or lead will not. In a collision, an object encounters a **force **for a predetermined period of time, which causes a change in the mass's velocity. Each object that collides with the other experiences a **force**. The two forces are at odds with one another but have equal power.

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an automobile of mass m is proceeding around a highway curve of 40-meter radius. the surface of the roadway is horizontal, and the coefficient of friction between the tires and the roadway is 0.50. the maximum speed with which the car can round the curve without slipping is...

The **maximum speed** with which the car can round the curve without slipping is 14m/s

Given the following:

The radius, r=40m

The coefficient of friction μ=0.5

Then from Newton's law:

μmg=mv^2/r

From the above equation, the speed, v of the **car **is:

v=√μrg, where μ=0.5, r=40m, and g=9.8m/s^2

v=√(0.5)(40m)(9.8m/s^2)

v=√196

v=14m/s

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,,.........................

Answer choices??? What do you have

A torpedo fired from a submerged submarine is propelled through the waterwith a speed of 20.00 m/s and explodes upon impact with a target 2000.0 maway. If the sound of the impact is heard 101.4 s after the torpedo was fired,what is the speed of sound in water? (Because the torpedo is held at a constantspeed by its propeller, the effect of water resistance can be neglected.)

**Given,**

The initial speed, u=20.00 m/s

The distance between the submerine and the target is d=2000.0m

The sound of impact is heard after T=101.4 s.

**To find**

The speed of sound in water.

**Explanation**

Here the total time taken to reach the submarine is the sum of thetime taken by the torpedo to reach the target and the time taken for it to come back.

Let the speed be v.

Thus,

[tex]\begin{gathered} T=\frac{d}{u}+\frac{d}{v} \\ \Rightarrow101.4=\frac{2000}{20}+\frac{2000}{v} \\ \Rightarrow v=1428.6\text{ m/s} \\ \end{gathered}[/tex]**Conclusion**

Speed of the sound in water is** 1428.6 m/s**

a long, thin solenoid has 700 turns per meter and radius 2.50 cm. the current in the solenoid is increasing at a uniform rate of 48.0 a/s. part a what is the magnitude of the induced electric field at a point near the center of the solenoid? express your answer with the appropriate units. e

The magnitude of the induced electric field at a point near the center of the **solenoid **is **E =0 v/m** at a point 0.500 cm from the axis of the solenoid is ** E = 1.05 × 10^-7 v/m.**

formula for **magnetic field** due to **solenoid **is ,

B=μ₀nI

E=μ₀nI/2 dI/dt

E = 4π×10^-7 × 700 ×0×48/2

E=0v/m at center of the solenoid.

at r= 0.5cm

E=4π×10^-7 × 700 ×0.5×10^-2×48/2

E=1.05×10^-4 v/m

A long, thin wire loop that is frequently wrapped around a metallic core is referred to as a solenoid in physics. When an electric current is sent through it, the solenoid creates a **magnetic field**. Solenoids play a crucial role since they can generate precise magnetic fields and function as electromagnets. Its magnetic field has a form that is highly reminiscent to a bar magnet's field when a direct electric current is conducted through it. In a solenoid, the field is powerful and constant. A greater overall **magnetic field** is created as a result of the little magnetic fields that are produced by the current in each turn of the coil.

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please answer questions 15, 16, and 17 below for a 2m long steel coil spring with a diameter of 2cm in a passenger vehicle is exposed to a force of 2,000 n. if the length of the coil extends elastically to 2.2m upon this force, please calculate

The question is incomplete, however 7.1 X 10^6 N/m^2 is** Young's Modulus** of 2m long steel coil spring with a **diameter **of 2cm in a passenger vehicle is exposed to a force of 2,000 N. If the length of the coil extends elastically to 2.2m upon this force.

[tex][Y=Fl\pir^2e],[Y=4000 \cdot2/\pi0.1884/2\pi^2\cdot0.4)][/tex]

Y = 7.1 X 10^6 N/m^2

**Young's modulus** is a metric for determining how elastic a substance is. The ability of a body to resist attempts to deform it using an external **shearing stress **is referred to as its elastic property.

The **internal force **of a material that attempts to return the body to its former shape is known as a restoration force. Young's modulus of elasticity is the proportion of **restorative stress **generated and **strain **(deformations such an increase in length per unit length).

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You place a box weighing 299.7 n on an inclined plane that makes a 43.5 angle with the horizontal. compute the component of the gravitational force acting down the inclined plane. answer in units of n.

The** gravitational force **acting **down the inclined plane** is **206.19N**

The force acting along the inclined plane is **opposite the frictional force **and the** formula** to express it is:

[tex]F_{m}[/tex]= F sinФ

It is given that

F = 299.7N

Ф = 43.5 degree

Putting the value we have:

[tex]F_{m}[/tex] = 299.7 sin 43.5°

= 299.7 (0.688)

= 206.19N

Therefore the **gravitational force** acting **down the inclined plane is 206.19N.**

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the timing device in an automobile’s intermittent wiper system is based on rc an time constant and utilizes 0.500 μf a capacitor and a variable resistor. determine the time constant if the resistance is 30 mω.

Our resistance is four mega houses at two seconds. Simply enter 15 seconds as R times 150.50 times 10 to the negative six digits for the calculation. We therefore have 30 **Mega Ohms**.

It is required to wipe the screen of an automobile on a regular basis when there is a light drizzle, when it is dirty, or when any of these conditions exist. There is a switch that uses an electrical circuit to wipe the screen. A main-wiper control circuit system and a relay control circuit are components of an intermittent wiper system. The relay control circuit uses a transistor and diode combination in an RC circuit.

According to what we've been told, our RC circuit's capacitance is 0.5 micro Farads, or 0.5 times ten to the minus six Farads. The **resistance **times the capacitance produces the time constant. And by multiplying both sides by C, we may find R's value. And when the time constant is divided by the capacitance, which is equal to 0.5 times ten to the minus six Farads, we have the minimum **resistance**, which is equal to 4.00 **Mega Ohms**.

The maximum time constant divided by capacitance occurs when the resistance is at its maximum. As a result, when we replace tau with 15 seconds, we obtain 30.0 **Mega Ohms**. To modify the frequency of the wiper blades' oscillation, the **resistance **must be able to shift between four and thirty megaohms.

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An automobile travels for 90 minutes along a highway. The graph shows the progress of the automobile, with its start point designated as distance = 0 km.

What is the automobile's instantaneous velocity at time = 60 seconds?

0.50 km/min

1.0 km/min

−0.40 km/min

0.33 km/min

Taking the gradient from point B to P, 0.33 km/min is the automobile's **instantaneous velocity**. Option **D** is the right answer.

Instantaneous velocity of a moving body is the velocity of the body at an **instant of time** or at a specific time.

Given that an automobile travels for 90 minutes along a highway. From the graph, it is shown that the velocity is constant at point B to point Point P.

The automobile's instantaneous velocity at time = 60 seconds can be calculated by using the gradient formula along the line BP since the velocity is **constant** from point B to point P

**Gradient = Δ distance / Δtime**

Velocity V = (30 - 15) / (75 - 30)

V = 15 / 45

V = 0.33 Km/min

Therefore, the automobile's **instantaneous velocity** at time = 60 seconds is 0.33 km/min

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help please i have a 17 as a grade :)

**Given **

A 50kg boy

A 100 kg father

Speed (both) 5 m/s

**Procedure **

Kinetic energy is a form of energy that an object or a particle has by reason of its motion

For the boy

[tex]\begin{gathered} K_b=\frac{1}{2}mv^2 \\ K_b=\frac{1}{2}\cdot50\operatorname{kg}\cdot(5m/s)^2 \\ K_b=625J \end{gathered}[/tex]For the father

[tex]\begin{gathered} K_f=\frac{1}{2}mv^2 \\ K_f=\frac{1}{2}\cdot100\operatorname{kg}\cdot(5m/s)^2 \\ K_f=1250J \end{gathered}[/tex]Now, let's compare the kinetic energy between father and boy

[tex]\begin{gathered} \frac{father^{\prime}s\text{ KE}}{boy^{\prime}s\text{ KE}} \\ \frac{1250J}{625J} \\ \frac{father^{\prime}s\text{ KE}}{boy^{\prime}s\text{ KE}}=2 \end{gathered}[/tex]The father's KE is twice the boy's kinetic energy

*Screenshot: *

Part 2:

Part 1:

A humming bird flies 1.m along a straight path at a height of 5.9 m above the ground. Upon spotting a flower below, the hummingbird drops directly downward 1.8 m to hover in front of a flower.

What is the magnitude of the hummingbird’s total displacement?

The hummingbird's total **displacement** is 6.168m, 16.96⁰ Southwest.

Construct a right-angled triangle from the bird's displacement

⇒From the diagram uploaded; we calculate the resultant/total displacement (R) of the bird using Pythagoras theorem,

R² = 5.9² + 1.8²

R² = 38.05

R = √38.05

R = 6.168 m

calculate the direction of the bird's displacement

From the vector diagram head-to-tail rule, we determine the cardinal direction;[tex]tan\alpha = \frac{1.8}{5.9}[/tex]

From the diagram; [tex]tan\alpha = 0.3050[/tex]

[tex]\alpha = tan^{-1} 0.3050[/tex]

[tex]\alpha = 16.96^{o}[/tex]

Therefore the hummingbird's total displacement is 6.168m, 16.96⁰ Southwest.

What is displacement?**Displacement** is defined as a change in the **location** of an **object**. It is a vector quantity and has direction and **magnitude**. It is represented as an arrow pointing from the starting position to the final position. For example - when an object moves from point A to point B, the position of the object changes.

Displacement (symbolized d or s ), also called **length** or **distance**, is a one-dimensional quantity representing the difference between two specified points. The standard **SI unit** of displacement is the **meter** (m).

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Based on this law, if a collapsing cloud is isolated in space with no external forces, what must happen to it as its size decreases?.

Based on** law of conservation of angular momentum** if a collapsing cloud is isolated in space with no external forces, the cloud will spin faster, the size will go on decreasing and the **angular momentum** will go on increasing that is reduction in radius and it will start spinning faster.

According to the **nebular theory**, a cloud of gas and dust must gravitationally collapse into a disk in order for planets to form inside. The disk must flatten out to fit observations. what causes this flattening to happen? Take the law of conservation of angular momentum, which states that an amount related to an object's size(its **moment of inertia**) times the rate at which rotates (**angular speed**) must always remain constant if no **external forces **are acting on the object.

Therefore, if a collapsing cloud is isolated in space with no external forces, the cloud will spin faster the size will go on decreasing and the angular momentum will go on increasing that is reduction in radius and it will start spinning faster.

What is law of conservation of angular momentum?Principle of conservation of angular momentum states that, if no external **torque** acts on a system, the total angular momentum of the system remains constant. If I be the momentum of inertia of a body about a given axis of rotation and w be its **angular velocity**, then I w= constant

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A hockey puck with an initial speed of 8.0 m/s coasts 45 m to a stop across the ice. If the force of friction on the

puck has a magnitude of 0.12 N, what is the puck's mass?

**Answer:**

[tex]\boxed{m = 0.16875 \;kg}[/tex]

**Explanation:**

The work done by a constant force F Newtons on a mass of m kg over a distance of d m at an acceleration of a m/s² is given by the equation:

[tex]W = F\cdot d[/tex]

This should be equal to the kinetic energy expended

[tex]KE = \dfrac{1}{2}m v^2[/tex]

By the law of conservation of energy,

W = KE

[tex]F\cdot d = \dfrac{1}{2}m v^2[/tex]

Given v = 8 m/s, F = 0.12N and d = 45m

[tex]0.12 \times 45 = \dfrac{1}{2} \times m \times 8^2[/tex]

[tex]5.4 = 32m[/tex]

[tex]m = \dfrac{5.4}{32}\\\\\boxed{m = 0.16875 \;kg}[/tex]

A hockey puck with an initial **speed** of 8.0 m/s coasts 45 m to a stop across the ice. If the** force** of friction on the puck has a magnitude of 0.12 N the puck's mass is 0.16875 Kg

**Work **in physics is the energy that is transferred to or from an item when a force is applied along a displacement. In its simplest form, it** equals** the product of the** force's** magnitude and the distance travelled for a constant** force** directed in the direction of motion.

The** work **done by a constant **force** F Newtons on a mass of m in kg over a distance of d in m at an acceleration of a m/s² is given by the equation:

This should be equal to the** kinetic energy** expended

K E = 1/2 m.v²

work, W = F.d

By the law of conservation of** energy**,

W = K E

Given v = 8 m/s, F = 0.12 N and d = 45 m

0.12* 45 = .5*m*8²

mass, m = 0.16875 Kg

A hockey puck with an initial **speed** of 8.0 m/s coasts 45 m to a stop across the ice. If the** force** of friction on the puck has a **magnitude **of 0.12 N the puck's mass is 0.16875 Kg

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A pilot drops a bottle out an airplane. If the plane was flying at an altitude of 500 m

and the bottle lands 400 m horizontally from the initial dropping point, how fast was

the plane flying when the bottle was released?

The plane was flying at **39.6 m/s** when the bottle was released .

[tex]h = ut + 1/2at^2[/tex]

distance fallen h= 500m

Initial velocity u=0

a=98 m/s2

[tex]h = 1/2at^2[/tex]

[tex]t^2 = 2h/a[/tex]

[tex]t^2 = 1000/9.8 = 10.1s[/tex]

[tex]d_h = 400, t = 10.1s[/tex]

[tex]v = d_h/t\\v = 400/10.1[/tex]

**v = 39.6 m/s**

What is Altitude ?

**Altitude **or Height (also known as depth) is a **measurement **of the **distance **between a reference point and a point or object, usually in a vertical or "**upward**" direction. The exact definition and reference value varies depending on the context (eg, aeronautics, geometry, geodesy, sports, or barometric pressure). Although the term **height** is often used to refer to the height of a place above **sea level**, in **geography **the term height is often preferred for this use.

The vertical measurement of distance in the "**down**" direction is usually called **depth**.

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Can you please help me with this question no 15 ?? Anyone please

The **weight **of the object in the newly heavenly body is 3000 N.

In science and engineering, the **weight **of an object is the pressure performed on the item due to gravity. a few widespread textbooks outline weight as a vector quantity, the gravitational pressure performed on the item. Others define weight as a scalar quantity, the significance of the **gravitational pressure.**

Given,

mass of earth = M

mass of new heavenly body = 12 M

the radius of the earth = r

the radius of the new heavenly body = 4r

mass of the object = m (mass always remains constant)

[tex]\frac{mM}{r^2}[/tex]

using the formula of gravity,

G₁ = g[tex]\frac{mM}{r^2}[/tex]

G₂ = g[tex]\frac{m12M}{4r^2}[/tex]

comparing G₁ and G₂

G₁ = 1000 N given

G₁ / G₂ = M × 4r² / 12 M r²

G₂ = 1000 × 12 / 4

= 3000 N

The measure of the pressure of **gravity **performing on a frame. The method for weight is given by using: w = mg. As weight is a force its SI unit is also the same as that of pressure, the SI unit of weight is **Newton **(N).

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galaxy fragments in the early universe formed before the first stars. in dark matter mini-halos. due to gravity from large dark matter halos. in places where the universe was slightly less dense than average.

Galaxy fragments originated in the early world due to the **gravity** of massive amounts of dark matter.

**Dark matter** is any substance that primarily interacts with visible matter through** gravity** (e.g., stars and planets). Therefore, in theory, it need not be made up of a brand-new form of fundamental particle but rather may be built up, at least in part, of typical baryonic matter, such as protons or neutrons.

The concept of** dark matter**, the invisible substance whose gravitational pull is assumed to hold galaxies together, may not be the most pleasing one in physics. According to a recent study, however, if you want to get rid of it, you'll need to switch it out for something more stranger: a gravitational force that at some distances pushes large objects apart and at others draws them together. The analysis highlights how difficult it is to rationalize away **dark matter.**

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A 10,000 N elevator is going upward and gaining speed. It is pulled upward by 4 steel cables, each exerting a 4,000 N tension force. What’s the net force?

The combined weight of the elevator box and the passenger riding inside it acts as the pulling force on the wires in an** elevator**. Therefore, in a perfect world, the **cable's tension** would match the elevator's weight when it is at rest.

How can I determine an** elevator** cable's tensile force?

**Total tension** is equal to the weight plus the force of acceleration when lift is upward. Total tension equals the difference between weight and force caused by acceleration as lift decreases.

In medium lengths, tension exerts its force, especially in flexible materials like rope or cord. The force of tension is still a** gravitational** **force**. When the body moves.

**The net force** is the total of all forces acting on an object. According to Newton's Second Law, there must be a net force exerted on an item in order for it to accelerate. If an object's net force is zero, it is said to be in equilibrium and not moving forward.

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Determine the cross-sectional area of a copper conductor if its resistance is 0.2 ohm and its mass is 0.2 kg. So:

R=0.2 Ohm, m=0.2 kg, ρ=0.017 m²/m, S=?

The **cross-sectional area** of a copper conductor if its resistance is 0.2 ohm and its mass is 0.2 kg is 61.7 m²

Considering the conductor is a wire,

Density = m / V

V = A l

**ρ = R A / l**

m = Mass

V = Volume

l = Height / Length

R = Resistance

ρ = Resistivity

R = 0.2 Ω

m = 0.2 kg

ρ = 0.017 Ω m

Density of copper = 8.96 * 10³ kg / m³

V = 8.96 * 10³ / 0.2

V = 44.8 * 10³ m³

A l = 44.8 * 10³

l = 44.8 * 10³ / A

ρ = R A / l

0.017 = 0.2 A / l

l = 0.2 A / 0.017

**Equating **both the values of l,

44.8 * 10³ / A = 0.2 A / 0.017

761.6 = 0.2 A²

A² = 3808

A = 61.7 m²

Therefore, the cross-sectional area of a copper conductor is **61.7 m² **

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What is the weight of a 179 kg football player?

394.6 pounds I hope this helps you

What do all living things constantly engage in

All **living **things are constantly engaged in **Homeostasis**.

Homeostasis is the capacity to sustain a comparatively constant internal condition that endures despite changes in the external **environment**. To consume **energy **and eventually live, all living things—from plants to puppies to people—must control their interior environments. For numerous reasons, the body sustains homeostasis. Body temperature, blood sugar levels, and varying pH levels are a few of them. Not merely at the level of the entire body as it is for temperature, homeostasis is maintained at several levels.

Homeostasis is a state that can be preserved by all living things. They have systems in place to regulate things like their internal **temperature**, water balance, and acidity. Normal cell functions that take place inside of them depend on homeostasis. Normal life processes are interfered with if an organism can't sustain **equilibrium**. Ailment or even death might follow.

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Help me as pleasessss help with 1,2 and 3

1.) Flammability

2.) Physical Properties

3.) Flammability, Reactivity, Ability to Rust

2.) Physical Properties

3.) Flammability, Reactivity, Ability to Rust

The gas pressure in an oxygen tank is 3.90 atm at a temperature of 298 K. If the pressure decreases to 3.20 atm, what is the temperature of the gas in kelvin? it need to be rounded by three significant figures to

The **temperature **of the gas rounded to three significant figures would be 244 Kelvin.

What is an ideal gas?

It is an imaginary gas for which the **volume **occupies by it is negligible, this gas does not exist in a practical situation and the concept of an ideal gas is only the theoretical one.

As given in the problem, the gas **pressure **in an oxygen tank is 3.90 atm at a **temperature **of 298 K. If the pressure decreases to 3.20 atm,

By using the constant **volume **for the ideal gas,

P₁/P₂ = T₁/T₂

3.90 /3.20 = 298 / T₂

T₂ = 244 Kelvin

Thus, the **temperature **of the gas rounded to three significant figures would be 244 Kelvin.

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4. A ball is thrown horizontally with an initial velocity of 10 m/s off a cliff and spends 5 seconds in the air before hitting the ground. What is the height of the cliff? How far does the ball travel before hitting the ground.

The** height** of the cliff is **122.5 m** and the **farthest distance **covered equals to** 50 m.**

What is projectile motion?

Projectile motion is a form of motion experienced by an **object **or** particle** that is projected near **Earth's surface** and moves along a** curved path** under the action of **gravity** only.

Given is a ball that is thrown horizontally with an initial velocity of **10 m/s **off a cliff and spends **5 seconds **in the air before hitting the ground.

Horizontal initial velocity = **u[x] = 10 m/s**

Vertical initial velocity = **u[y] = 0 m/s**

Vertical acceleration = **a[y] = 9.8 m/s²**

Using the **second equation** of motion along the **vertical direction** -

S[y] = u[y]t + 1/2a[y]t²

S[y] = 0 + 1/2 x 9.8 x 5 x 5

S[y] = 12.5 x 9.8

**S[y] = 122.5 m**

**Horizontal distance** covered = u[x] x t = 10 x 5 = **50 m**

Therefore, the** height** of the cliff is **122.5 m** and the **farthest distance **covered equals to** 50 m.**

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suppose that the stone is launched with a speed of 3 m/s and travels 40 m before coming to rest. what is the approximate magnitude of the friction force on the stone? 0 n 2 n 20 n 200 n

The approximate magnitude of the **friction force** of the stone is 2N.

Given values:

Mass(m)= 20 Kg

Velocity(v)= 3m/s

Distance(x)= 40m

Kinetic energy is given by the expression:

[tex]Ek=1/2mV^{2}\\ Ek=1/2*20Kg*(3m/s)^{2} \\Ek=90J[/tex]

If we divide the** kinetic energy** by the distance traveled we get the friction force:

[tex]Ff=Ek/x\\Ff=90J/40m\\Ff=2.25N[/tex]

Approximate magnitude of the friction force is: [tex]Ff=2N[/tex]

Result is **2N**.

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The location of magnetic north changes over time in its relation to true north. This angular difference between magnetic north and true north is called.

**Declination**. As you can see, the position has a significant impact on the compass's direction. Declination, which is measured in degrees on your map and represents the angle between magnetic north and true north.

The compass does not always point precisely toward geographic north on the surface of the Earth. An angle known as "**declination**" describes the compass's departure from true north (or "magnetic declination"). If you were to stand at the north geomagnetic pole, your compass would be held horizontally as usual and would not have a preference to point in any specific direction. The same would be true if you were to stand at the south **geomagnetic **pole. The north-pointing end of your compass would point up at the south **geomagnetic **pole if you were to hold it on its side, and it would point down at the north **geomagnetic** pole.

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a solenoid has 15 turns per centimeter of its length. the solenoid is twisted into a circle so that it becomes shaped like a toroid. what is the magnetic field at the center of each turn of the toroid? the current is 29 mama .

The **magnetic field** at the center of each turn of toroid is: 2.826×10⁻⁵ T

Magnetic field is a **vector field** in surrounding of a magnet, electric current carrying conductor or a changing electric field, in which **magnetic** **forces** can be experienced.

Magnetic field of a toroid is calculated as (B): μ₀nI

Where, μ₀= permeability

n= Number of turns in toroid

I= Current

B= Magnetic field

In the given question,

n=15 turns/cm

I=15mA

Now turns per meter length is: 15/10⁻²=1500turns per meter

The magnetic field at the center of each turn of the toroid is(B): μ₀nI

B= (4[tex]\pi[/tex]×10⁻⁷)(1500)(15×10⁻³A)

B= 2826×10⁻⁸ T

B= 2.826×10⁻⁵ T

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What are the steps for using a compass and straightedge to construct an equilateral triangle? drag the steps and drop them in order from start to finish.

The first step would be to draw your circle using the **compass**, the second step would be to add the point to the circle, the third method would be to use the circle's radius to determine the compass's width.

You were instructed to draw a hexagon inside a **circle **and to list the points as you go. So, in order to pull up that image for your query, I'm going to use my snipping tool.

So, the first step would be to draw your circle using the **compass**, which would be step number 1. Step number 2 would then be to use the center to get the radius of your **circle**.

So first you would add the point on the circle, so that would be step number 2 step. Number 3 would be to use the circle's radius to set the width of the compass and then, after you have that point on the circle, you would put the **compass **on there and you create an arc with that compass that intersects the circle.

And then you would go ahead and mark that intersection with a point connect the consecutive points with a straight edge and then repeat the stips.

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A particle that has zero momentum must also have zero kinetic energy.Select one:O TrueO False

The kinetic energy of an object is the energy possessed by the object due to its motion. That is when the velocity of the object is zero, i.e., when the object is at rest, the kinetic energy of the object will be zero.

The linear momentum is the product of the mass and the velocity of an object. When the momentum of the object is zero, the velocity of the object is also zer.

**Thus whenever a particle has a zero momentum, its velocity and hence its kinetic energy will also be equal to zero.**

**Therefore, the given statement is true.**

Where is the result of combining the terms represented by the titles below?A. x^2+x-5B. x^2+2x+1C. x+1D. x+5
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