is

A) 7.5 N. B) 75 N.

C) 750 N. D) any horizontal force greater than zero.

Here, if take it that you mean "perfectly smooth" to mean that there is no friction. If that is the case, then the box begins to move whenever there is a net horizontal **force** acting on it. (D) It goes without saying that the force increases as the box** accelerates. **

F = ma

Where, F is the force on the box and m is the mass of the box and a is the acceleration.

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determine the tension developed in cable ab for equilibrium of the 440- lb crate. determine the tension developed in cables ac for equilibrium of the 440- lb crate. determine the force developed along strut ad for equilibrium of the 440- lb crate.

In physics, a system is said to be in **equilibrium **when neither its internal energy state nor its state of motion tend to vary over time. If all of the forces operating on a single particle are vector summated to zero, equilibrium occurs.

In physics, tension is the pulling **force **that is conveyed axially by a string, cable, chain, or other similar one-dimensional continuous item, or by either end of a rod, truss member, or other similar three-dimensional object.

**Equilibrium **refers to the state of a system when neither its internal energy state or state of motion tend to change over time. **Equilibrium **for a single particle occurs when the vector sum of all **force **acting on the particle is zero.

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a 0.11 kgkg steel ball is tied to the end of a string and then whirled in a vertical circle at a constant speed vv . the length of the string is 0.62 mm , and the tension in the string when the ball is at the top of the circle is 4.0 nn . what is vv ?

The **speed **of the ball during **centripetal motion **is** 4.75 m/s**.

We need to know about **centripetal force** to solve this problem. When an object moves in a circular motion, the object is experiencing centripetal force. The magnitude of **centripetal force** is

Fc = m . v²/R

where Fc is the **centripetal force**, m is mass, v is velocity and R is the radius.

From the question, we know that

m = 0.11 kg

F = 4 N

R = 0.62 m

The tension in the string is equal to **centripetal force**

T = Fc

4 = m . v²/R

4 = 0.11 . v² / 0.62

v² = 22.55

v = 4.75 m/s

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when rebuilding her car’s engine, a physics major must exert 240 n of force to insert a dry steel piston into a steel cylinder. what is the magnitude of the normal force between the piston and cylinder in newtons if the coefficient of kinetic friction between the piston and cylinder is 0.3?

If the coefficient of **kinetic friction **between two sliding surfaces is μ and the **normal force** between them is N, then the kinetic friction between them is given by μ = F/N . Therefore** N= 800**.

Given

**kinetic friction** μ = 0.3

and kinetic friction μ = F/N

N = normal force

where F =** frictional force **

F = 240 n

N = F/μ

= 240 n/0.3

N = 800 n

There are two types of friction **kinetic friction**, also known as dynamical friction, and static friction. A **force **acting in opposition to the direction of a moving body on the surface is felt. The two materials' coefficient of kinetic friction will determine how much **force **is applied. Kinetic friction occurs whenever two surfaces slide past one another. The application of brakes to tyres, the movement of an object across the ground, such as a box, or the rubbing of sandpaper all cause kinetic friction. The coefficient of friction, which measures the relationship between the frictional **force **and the normal force, provides a good description of friction. It obstructs the motion of several different items.

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A piston contain oxygen at 280k occupying a volume of 0.25m^3.the cylinder is compressed adiabtically to 0.14m^3 find the increase in tempratur of the gas

The gas's internal **energy **rises by 250 J when the value is positive. So, the increase in temperature of the gas is 250 J.

Any device addressing the relationship between heat and work must be designed with a working knowledge of thermodynamics. This method ignores actions that take place at the molecular level in favor of considering a particular amount of matter.

In macroscopic thermodynamics, the effects are based on observable, quantifiable quantities, and the attributes of the system are given to the system as a whole.

Work cannot "store" **energy **like the aforementioned forms can. It is merely a momentary **manifestation **process of energy transmission. Heat cannot transport **energy **either; it is merely a temporary **manifestation **process. Therefore, other types of energies in transition include heat and work.

by setting a limit, identifies the subject of the **manifestation **analysis. Either "a distinct collection of substance" or "a region in space" must be handled consistently.

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Alcohol abuse can lead directly to all of the following Except

Group of answer choices

lung cancer

brain damage

heart disease

stroke

Lung cancer. Brain damage, heart disease and stroke can be caused by alcohol abuse but lung cancer cannot.

**Alcohol abuse** can lead to various health risks including brain damage, heart diseases, stroke etc. But studies yet not proved any connection of alcohol use with **lung cancer**.

**Alcohols **are organic compounds with **OH groups**. They are used in beverages as sprits which causes, **neurodegeneration** and nerve injury. The use of alcohol and further adverse affects is called alcohol abuse.

**Alcohol **abuse leads to severe damages to almost all parts of the body from brain to digestive system. **Alcoholic products** interfere with the nerve functions and suppress the excitatory **nerve pathway** activity causing brain damage and strokes.

Alcohol abuse further causes high blood pressure and damage to the heart valves . However, is is not reported that alcoholic use cause lung cancer. It is mainly caused by **smoking**. Thus option **a** is correct.

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a 22-g bullet traveling 240 m/s penetrates a 1.7 kg block of wood and emerges going 125 m/s .if the block is stationary on a frictionless surface when hit, how fast does it move after the bullet emerges?

**Answer:**

m v1 = M V + m v2 conservation of momentum

V = m (v1 - v2) / M

V = .022 (240 - 125) / 1.7 = 1.49 m/s

you are an electron moving forward. you fly into a region where the magnetic field is pointing to your right. what is the direction of the magnetic force?

Therefore, the electric charge will travel in a circle around a** fixed **point. Positive charges move in a counterclockwise manner when the magnetic field is pointing into the page, whereas negative charges move in a **clockwise **direction (apply the right hand rule).

**Perpendicular** to the direction of motion is the direction of the force caused by a magnetic field.

According to the** right hand rule**, you should point your right thumb toward the direction of the velocity (v), your** index finger** toward the direction of the **magnetic field **(B), and your middle finger toward the direction of the** magnetic force** that results from that.

Right hand rule #1 governs the direction of the magnetic force on a moving charge, which is perpendicular to the plane formed by v and B. (RHR-1)

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In coming to a stop, a car has left black tire marks of length 92 m on a road. Assuming

the best rate of slowing down for this car is 7 m/s calculate the velocity of the car just

before braking

Fall

The velocity of the car just before breaking **35.9 m/s**

Braking distance, s = 92.0 m

Deacceleration = 7 m/s²

Speed of the car when stopped, =0

Let the speed of the car just before braking, =0

Using the equation of motion ²=²+2as

² = ² - 2as

² = 0² - 2(-7)(92.0)

² = 1288

≈ 35.9 m/s ← speed of the car just before breaking

What is acceleration?**Acceleration **can be defined as a vector quantity that determines the rate at which an object changes its **velocity**. An object continues to **accelerate **as it changes its speed over and over again.

Acceleration has nothing to do with changing the target's movement **speed**. If an object does not change its **speed**, then the object is not accelerating. The data on the right represents an object **moving north**. The speed of the target changes over **time**. In fact, the speed changes by a **constant amount** - ie. 10 m/s - every second. When the speed of an object changes, the object is said to be in **accelerated motion** or acceleration.

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isabella's mom bought her a microscope so she could observe a plant cell.during her observation, she rotates the objective lens from 4x to 10x so she could view the plant cell at a higher magnification. what was the total magnification when she changed the objective lens?

Add the eyepiece's power, typically 10X, to the objective's (4x) power to get the overall **magnification**. Total magnification for 4x lens is **40x **and 10x is **400x**.

Make sure the 4X scanning objective is locked into position and the stage is completely down before viewing a slide through the **microscope**.

Set the slide over the aperture that you want to see, then carefully place the stage clips on top of the slide to secure it in place.

Start with the 4X objective, keep both eyes open while looking through the eyepiece (if necessary, cover one with your palm), and gradually raise the stage using the coarse adjustment knob until the image is clear. The coarse adjustment knob will only need to be used once during the operation. You will be utilizing parfocal **microscopes**, which means that the image. Things appear 40 times bigger than they are using a 40x objective. Comparing objective **magnification **is relative. The capacity of a **microscope **to create an image of an object at a scale bigger (or even smaller) than its real size is known as magnification.

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which requires the most energy to melt it: 1kg of ice, 1kg of solid lead or 1kg of solid ethanol

The **substance **that requires the **greatest amount **of energy to melt is **ice**.

The **latent heat** of fusion refers to the energy that is required to melt 1 Kg of a substance. We must note that this heat goes into the breaking of the internal bonds of the material. Thus, the nature of the** internal bonds** in the materials are important when we are dealing with the** latent heat **of fusion.

We can see that the particles of ice are held together by the strong **hydrogen bonds**. As such, we can see that ice has the highest latent heat of fusion.

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What is the pressure when 800N is applied to an area of 0.3m2 ?

**Answer: **[tex]2666.67 \text{ (or in 2 sigfigs, }2.7\times10^{3})[/tex]

**Explanation: **[tex]1\text{ }\dfrac{\text{N}}{\text{m}^2} = 1 \text{ Pa}\\\\P=\dfrac{F}{A}\\\\P=\dfrac{800\text{ N}}{0.3\text{ m}^2} = 2666.\overline6 \text{ N/m}^2 \approx 2666.67 \text{ Pa} \approx 2.7 \text{ kPa}[/tex]

Don't know if you need to convert to other units but typically in physics it's left as N/m^2 or Pa.

A 1500 kg car travels around a circular track at a constant speed. a) If the radius of the path is 200 m and the car is traveling at 45 m/s, how long does it take the car to do a lap around the track? b) What net force is acting on the car in the horizontal direction? c). What force keeps the car in a circular path? d). What is the coefficient of static friction between the car’s tires and the road?

a) The **time taken** is 4.44 s

b) The **force **that keeps it moving is 15188 N

c) The centripetal force is responsible for the motion in the circular path.

d) The coefficient of the **friction **is 1.03

The** centripetal force** is the force that keep the object moving in a circular path. In this case, we need to find the how long does it take the car to do a lap around the track.

a) The time that is taken is the radio of the distance to the speed of the object. Thus the **time **that is taken = 200 m/45 m/s = 4.44 s

b) The net force that acts on the car as it is negotiating the circular path is given as; mv^2/r = 1500 * (45)^2/200

= 15188 N

c) The centripetal force keeps the car on the circular path

d) The coefficient of static friction is; 15188 N/1500 kg * 9.8 m/s^2

= 1.033

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a football kicker can give the ball an initial speed of 25m/s. what are the a) least and b) the greatest elevation angles at which he can kick the ball to score a field goal from a point 50m in front of goalposts whose horizontal bar is 3.44m above the ground?

tan0=1.95 and tan0=0.605 are two solutions. 0 = 63 and theta 0 = 31 are the **corresponding **(first quadrant) **angles**.

The **elevation** angle is the angle between the horizontal line of sight and the object when standing and looking at something. The **angle** of depression is the angle between the horizontal line of sight and the object if the person is standing and looking down at the object. The rise or rise of something is called elevation. Mountains have an elevation based on their height, and your mood rises the happier you are. **Elevation** is a noun that describes the height of something above a surface or **ground** line. It is also a term of measurement for things like temperatures or degrees.

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A 0.12-kg apple falls off a tree branch that is 2.3 m above the thick grass. The apple sinks 0.067 m into the grass while stopping. Determine the average contact force that the grass alone exerts on the apple while stopping it. Ignore air resistance.

**Answer:**

**F = 20 N**

**Explanation:**

Given:

m = 0.12 kg

H = 2.3 m

S = 0.067 m

g = 9.8 m/s²

____________

F - ?

1)

**Potential energy over grass:**

Wp = m*g*H = 0.12*9.8*2.3 ≈ 2.7 J

2)

**Work against the friction force of the grass:**

A = F₁*S

3)

**According to the law of conservation of energy:**

A = Wp

F₁*S = Wp

F₁ = Wp / S = 2.7 / 0.067 ≈ 40 N

4)

**Average grass resistance strength:**

F = F₁ / 2 = 40 / 2 = 20 N

If an element starts off with an activity of 100Bq, and its half life is 10 minutes, what would the activity be after 5 minutes???

I'm literally giving out 100 points and I really need the help :/

From the calculation, the **activity **of the **isotope **is ** 70.7 Bq.**

We define the term** half life **as the amount of a radioactive **isotope **that is left after a given time. It is in fact the time that it takes for only half of the amount of the radioactive isotopes that is in a sample to remain.

Recall that if a substance is radioactive, this implies that the sample is capable of spontaneous **disintegration**. The amount of the sample that is present tends to diminish in the system as time increases.

Give the fact that;

Ao = initial activity = 100Bq

A = activity after time t = ??

Time taken = 5 minutes

Half life of the isotope = 10 minutes

Now we know that;

A/Ao = (1/2)^t/t1/2

A/100 = (1/2)^5/10

A/100 = (1/2)^1/2

A = (1/2)^1/2 * 100

A =** 70.7 Bq**

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Which best describes the velocity of a rolling pen?

4 s2

4 cm/s

4 cm west

4 cm/s west

[tex]\huge\underline\mathcal{Answer \: - }[/tex]

velocity is a vector quantity that tells us about the speed as well as direction of an object.

Thus , the best description of velocity will be the one which tells us the speed as well as direction of the rolling pen.

therefore ,

the last option **4**** ****cm/****s ****west **is correct!

hope helpful ;-;

if you answer i will mark you as brainlist

reaction

Newtons third law states that for every action there is an equal but opposite reaction

and for that object (rocket, missile, jet,) as the engine is ignited the force of the burning fuel pushes backward while the rocket moves forward so the rate at which the fuel burns is equal to the rate at which the object moves forward

the force at which the burning fuel pushes backward is equal but opposite to the rate at which the object moves forward

a bird flying 3.45 m / s directly north feels a window directly east and accelerates 0.558 m / S^2. What is its velocity 5.25 s later

If a bird flying 3.45 m / s directly north feels a window directly east and **accelerates **0.558 m / s², then its **velocity **after 5.25 seconds would be

There are three equations of motion given by Newton,

v = u + at

S = ut + 1/2×a×t²

v² - u² = 2×a×s

As given in the problem If a bird flying 3.45 m / s directly north feels a window directly east and **accelerates **0.558 m / s²,

By using the first **equation **of motion,

v = u + a × t

v = 3.45 + 0.558 × 5.25

v = 6.537 m / s

Thus, its **velocity **after 5.25 seconds would be 6.537 m / s

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**Answer:**

about 4.53 m/s 40.3° east of north

**Explanation:**

You want the **velocity of a bird** flying **3.45 m/s north** after being **accelerated** by a wind at **0.558 m/s² directly east** for **5.25 seconds**.

The attached table shows the result of the acceleration. The change in "x" velocity is the product of the acceleration and time. The y-velocity is unaffected by the easterly acceleration.

Final velocityThe magnitude of the final velocity is the root of the sum of the squares of its components:

Vf = √(2.9295² +3.45²) ≈ **4.5226 . . . . m/s**

The direction of the final velocity is ...

arctan(3.45/2.9295) ≈ 49.7° . . . . . CCW from east

**The magnitude of the bird's final velocity is about 4.53 m/s. Its direction is about 40.3° east of north, or 49.7° north of east**. **The components of the velocity are about 2.93 m/s east and 3.45 m/s north**.

__

*Additional comment*

The second attachment shows the bird's direction as a "bearing" angle, conventionally measured clockwise from north. The answer above gives the complementary angle, measured CCW from east.

Problem values are given to 3 significant figures, so we have rounded results to that precision.

# 14 If you have a tire blowout when driving on the highway, you should not use your brakes until...

If you have a tire **blowout** when driving on the highway, you should not use your brakes until the vehicle has nearly **rolled **to a stop.

If you have a tire** blowout** when driving on the highway, you should not use your brakes until the vehicle has nearly **rolled **to a stop because at high speed the deviation is more.

**Rolling** is a type of motion that combines rotation and translation of that object with respect to a surface, such that, if ideal conditions exist, the two are in contact with each other without sliding. **Rolling** where there is no sliding is referred to as pure **rolling.**

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When the lever is pulled, 2 kg of carbon dioxide is ejected at a speed of 60 m/s. The remaining mass of the person, chair, and cylinder is 80 kg. After the ejection, how fast will the chair be moving?.

The **combined velocity** of the car and the chair is 1.5 m/s.

By the use of the law of the conservation of **linear momentum** we know that the total momentum before collision is equal to the sum of the final momentum after collision.

We have to first obtain the momentum of the system before and after the collision has occurred as we see below;

Then we have;

Momentum before collision = 2 Kg * 60 m/s = 120 Kgm/s

Momentum after Collison = 80v Kgm/s

Momentum = mv

m = mass of the object

v = velocity of the object

Using the principle of the conservation of momentum;

120 = 90v

v = 120/80

v = 1.5 m/s

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What is the mass of a blow dart that experiences a blowing force of 0.20 Newtons and travels the length of the 1.2 meter barrel in 0.04 seconds? (HINT: first find the acceleration)

The **mass of a blow dart** that experiences a blowing force of 0.20 Newtons and travels the length of the 1.2 meter barrel in 0.04 seconds is 0.26 g

**a = v / t**

**v = d / t**

a = Acceleration

v = Velocity

d = Distance

t = Time

d = 1.2 m

t = 0.04 s

v = 1.2 / 0.04

v = 30 m / s

a = 30 / 0.04

a = 750 m / s²

According to Newton's second law of motion,

**F = m a**

F = Force

m = Mass

F = 0.2 N

m = F / a

m = 0.2 / 750

m = 2.6 * [tex]10^{-4}[/tex] kg

m = 0.26 g

Therefore, the mass of a blow dart is **0.26 g**

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Imagine a black hole lacking any accretion disk whatsoever. Would this black hole produce any light? why?.

We wouldn't be able to observe the **black hole **if the accretion disc in it didn't create any light. Due to the **black hole's **intense gravitational pull, these particles spin at incredibly high speeds, producing an accretion disc and radiation in the process.

Therefore, there is no light when the **accretion disc **is absent.

Please refer to the solution for this step.

So, option an is the proper response. All other **possibilities **are false.

Please refer to the solution for this step.

A is the right response in this case.

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In the case of falling, the time will double how much the height will increase

In the case of** falling**, the time will double then the **height** will increase by a factor of **4 times.**

In this problem, we are dealing with **free-falling **and** distance**, where distance is The physical quantity that can be defined by how the object or body is seen far away, whereas** displacement **and Distance both are different physical meanings but have the same standard units and whereas a** free falling object** is an object that's falling beneath the sole impact of gravity. Any object that's being acted upon as it were by the **force of gravity **is said to be in a state of free fall.

Since we are given that the falling time is doubled, since the formula for the distance by the **equation of motion** is

s=1/2gt²

where g is the **acceleration due to gravity** and t is the** time**, so if the time is increased by 2 times, then the distance increase by the value of 4 times as distance is directly proportional to the square of the **falling time**.

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Equal masses are suspended from two separate wires. The wires have identical lengths. The first wire has a larger cross-sectional area than the second wire. Which wire will stretch the least?.

As the larger **cross-sectional **area results in** less stress force** therefore, for the **same force **, stress is less in **large **cross -section and it **streches less**

According to** Hooke's rule**, stress and strain are directly inversely related, meaning that as stress rises, strain rises as well. There is no need that the connection between strain and stress be linear. It is valid when the **deformation **is caused by a relatively tiny bulk stress.

**Stress=K×strain**

The **elastic modulu**s is the proportionality constant characterizing the connection between stress and strain.

Stress=Elastic modulus×Strain

The term **"bulk modulus**" refers to the elastic modulus for bulk stress. The ability of the material to endure changes in volume under pressure from all sides may be expressed numerically as the bulk modulus. It describes the elastic characteristics of **solids **and **fluids **under pressure on all surfaces.

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two forces parallel to the x axis do 11.0 j of work on a small tray while moving it 16.7 m in the x direction across a gym floor. one of the forces has a value of 3.71 n in the x direction. what is the other force?

The other **force **has **magnitude **of 2.41 N and **direction opposite **to that of force 3.71 N **parallel **to x axis

Let the other force=P

**work done=total force*displacement**

16.7=(P+3.71)*11

P+3.92=1.51

P=-2.41

**Newton **is the abbreviation for the SI **unit **of absolute **force **known as newton (N). It is described as the amount of force required to accelerate a kilogram of mass by one meter per second. In the foot-pound-second (English, or customary) system, one **newton **is equivalent to around 0.2248 pounds of force or 100,000 dynes in the centimeter-gram-second (**CGS**) system.

The **newton **was given its name in honor of Sir** Isaac Newton,** whose second rule of **motion **outlines the modifications that a **force **may cause in a body's motion.

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what is the speed of the protons? (note: the speed is high enough that, in principle, we should use a relativistic calculation--something you'll learn about further--but for this problem you should use the formulas you are already familiar with.)

The speed of the **protons** v is 1.089[tex]e^{8}[/tex] m/s.

Every atom has a proton, a subatomic particle, in its nucleus. The particle has an electrical charge that is opposite to the electrons and is positive.

Define potential difference.To establish a potential difference, a unit of positive **electric charge** must be transported from one location to another.

Here we are given a** potential difference **as 62MV= 62[tex]e^{6}[/tex]V

Now, as per classical definition, equation P.E. and the K.E.

So we have,

qV = 1/2[tex]\frac{m}{s^{2} }[/tex]

V is the potential difference and v is the velocity.

v = [tex]\sqrt\frac{2qV}{m}[/tex]

By substituting the values we get,

v = 1.089[tex]e^{8}[/tex] m/s

The speed of the protons v is 1.089[tex]e^{8}[/tex] m/s.

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A patient's tumor is being treated with proton-beam therapy. The protons are accelerated through a potential difference of 62 MV. What is the speed of the protons? (Note: The speed is high enough that, in principle, we should use a relativistic calculation something you'll learn about in Chapter 27 but for this problem, you should use the formulas you are already familiar with.)

Suppose an asteroid orbits the sun with a mean radius 11 times that of Earth. Use the simplified version of

Kepler's third law (T2= a³) to find the period of the asteroid? Round your answer to the nearest Earth year.

**Answer:**

36 years

**Explanation:**

Given the equation of **Kepler's third law** as T² = a³, you want to know the period of an **asteroid** that has an orbital **radius of 11 au**.

Solving the given equation for t, we find ...

T = a^(3/2) . . . . . . take the 1/2 power

Then for a=11, the period in years is ...

T = 11^(3/2) ≈ 36.48

**The period of the asteroid is about 36 years**.

ANSWER ASAP: Leandra is working with a machine that uses 10,000w of power in 2 hours. Find the amount of work done by the machine.

w means "Watts"

The time must also be converted into seconds.

If Leandra is working with a machine that uses 10,000 watts of **power **in 2 hours, then the amount of **work **done by the machine would be 72000000 **Joules**.

The total amount of **energy** transferred when a force is applied to move an object through some distance.

The **work **done is the multiplication of applied **force **with the displacement.

As given in the problem Leandra is working with a **machine** that uses 10,000 Watts of **power **in 2 hours,

Power = work done / time

10000 = work done /3600*2

Work done = 72000000 Joules

Thus, the **work **done by Leandra would be 72000000 **Joules**.

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an ideal spring of negligible mass is 12.00 cmcm long when nothing is attached to it. when you hang a 3.75 kgkg object from it, you measure its length to be 13.40 cmcm.

If we have an **ideal spring** and attach a mass of 3.75 kg to it such that the spring extends from 12 cm to 13.40 cm, then its **spring constant **is 2678.57 N/m

When a force applied to a spring, then according to the **Hooke's Law**:

F = - k. x

Where:

F = **applied force**

k = spring constant

x = change in spring's length

The minus sign indicates that the displacement and the **restoring force** is in the opposite direction.

The given** parameters**:

x1 = 12 cm

x2 = 13.4 cm

Hence,

x = x2 - x1 = 13.4 - 12 = 1.4 cm = 1.4 x 10⁻² m

F = 3.75 . 10 = 37.5 N

Then,

k = F/x = 37.5 / (1.4 x 10⁻² ) = 2678.57 N/m

Complete question:

An ideal spring of negligible mass is 12.00 cm long when nothing is attached to it. when you hang a 3.75 kg object from it, you measure its length to be 13.40 cm. What is the **spring constant**?

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3. Cylinder of radius 5 cm and height 20 cm, is made of iron of density 7800 kg/m³, find

a. The volume of the cylinder in m³

b. The mass of the cylinder in kg.

The volume of the cylinder is 1.57 x 10⁻³ m³.

V = πr²h

V = π(5cm)²(20cm)(1m/100cm)³

V = 1.57 x 10⁻³ m³

The mass of the cylinder is 12.25 kg.

ρ = m/v

m = ρv

m = (7800 kg/m³)(1.57 x 10⁻³ m³)

m = 12.25 kg

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