a) How fast is the ball going when it passes the equilibrium point of the spring?

b) How far will the ball go up the ramp? Specify clearly what value you are giving me!

The ball is going when it passes the** equilibrium point **of the spring with a speed of 1.26 m/s and the ball go up the ramp till a **height **of 8.1cm.

The mass of the ball is 0.1 Kg. The** force constant** is 110N/m. The **compression** in spring is 4 cm which is equal to 0.04 meters. The **coefficient of kinetic friction **is 0.2.

a) Applying** work energy theorem, **according to which the total work done on a body by all the forces us equal to the net change in kinetic energy of the body.

**Total work done = change in kinetic energy**

Work done by friction + work done by spring = ∆KE

umgx + 1/2Kx² = 1/2mv²

Where,

u is the** coefficient of kinetic friction,**

m is the **mass **of the the ball,

g is** acceleration due to gravity,**

K is **spring constant,**

v is the **velocity** of the ball,

x is the** compression** in the spring.

Putting all the values,

-0.2(0.1)(9.8)(0.04) + (0.5)(110)(0.04)(0.04)= (0.5)(0.1)v².

-0.00784 + 0.088 = 0.05v²

v²=1.6

v = 1.26 m/s.

b) Applying **energy conservation,**

Initial total energy = final total energy

Mgh = 1/2Mv²

(0.1)(9.8)h = (0.5)(0.1)(1.6)

h = 0.081m

h = 8.1 cm.

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what happens to the temperature of the car brake when a driver brake decelerate quickly

**Answer:**

This reduces the kinetic energy of the vehicle, slowing it down and causing the temperature of the brakes to increase. Decelerating from very high speeds too quickly can cause a number of problems: The brakes could overheat and the material they are made from could shatter.

An electron moves between the ends of a 9.00 volt battery. How much work is done on the electron? A)0.78 x10^-15 J B)9.00 x10^-17 J C)1.44 x10^-18 J D)25.0 x 10^-20 J E)15.3 x 10^-20 J

When an **electron** moves between the ends of a 9.00-volt battery, the **work done** on the electron is 1.44 * 10⁻¹⁸ Jouoles; option C

The** work done** in moving an **electron** between two points is defined as the product of the potential difference between the points and the charge on an electron.

Mathematically;

Work done = ΔV * qwhere;

ΔV is the potential difference between the points

q is the charge on the electron.

The potential difference between the two points is the work done in moving a unit positive charge from one point to the other in the circuit.

The charge, q on an electron is 1.609 * 10⁻¹⁹ Coulombs.

For the given **electron** that moves between the ends of a 9.00-volt battery;

ΔV = 9.000 Volts

q = 1.609 * 10⁻¹⁹ Coulombs

Work done = 9.000 * 1.609 * 10⁻¹⁹

**Work done** = 1.44 * 10⁻¹⁸ Jouoles

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A 100 kg man and 50 kg woman on ice

skates stand facing each other. If the

woman pushes the man backwards so that

his final speed is 1 m/s, at what speed

does she recoil?

**Answer:**

First you must find the kinetic energy that aman use to push her;So you can find the speed that she recoil

If a car accelerated from 55 mi/hr to 16 mi/hr. in 3.2s how far did the car go while it was accelerating?

The cargo while it was **accelerating **at a distance of 0.602 meters.

**Acceleration **is the name we give to any system wherein the speed changes. on the grounds that speed is a pace and a direction, there are only two approaches so that you can boost up.

**Velocity **is the rate of change of displacement. Acceleration is the price of alternate velocity. velocity is a vector quantity because it consists of both significance and direction. Acceleration is likewise a vector quantity as it's far simply the charge of alternate velocity.

initial **velocity **= 55 m/hr

= 55/60× 60 m/sec

= 0.0152 m/sec

final **velocity **= 16 mi/hr

= 16/3600

= 0.0044 m/sec

time = 3.2 sec

V = u - at

a = ( U - V )/t

= (0.0152 - 0.0044)/t

= 0.0108 m/sec²

S = ut + 1/2at²

= 0.0152 × 3.2 sec + 1/2 × 0.0108 m/sec² × (3.2)²

= 0.0486 + 0.553

= 0.602 meter.

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Many scientists believe the solar system formed _______________ago

**Answer:**

4.6/4.5 billion years ago

**Explanation:**

a hydraulic lift requires a minimum effort force of 14.4N to lift a patient of a mass 82kg .How much is the effort piston area if the resistance piston has an area of 1.2m²

The output force of a hydraulic lift is given by:

[tex]F_2=\frac{A_2}{A_1}F_1[/tex]In this case we need to lift a patient of mass 82 kg, that means that the lifting force has to be equal to:

[tex]F_2=82\cdot9.8=803.6[/tex]Now that we know that we plug the values given, in this case we have:

[tex]\begin{gathered} 803.6=\frac{1.2}{A_1}(14.4) \\ A_1=\frac{1.2}{803.6}(14.4) \\ A_1=0.022 \end{gathered}[/tex]**Therefore the area of the effort piston is 0.022 squared meters (rounded to three decimal).**

I need helppp

What is the force applied to the small piston,f,in Lb that is required to deliver a working force,F, of 1000 lb? The area of the small piston,a, is 0.1963 sq in. and the area of the large piston,A, is 6.28 sq in.

The area of the small piston, a, is 0.1963 sq in. and the area of the large piston, A, is 6.28 sq in. The** force applied** to the small piston **(f)= 31.21 lb** that is required to deliver a working force (F)= 1000 lb

Force is a **physical quantity** that means if some kind of external or internal affair is happen on a object and the object is move a bit that means a force is act on it. Its a **vector** quantity.

To calculate the force of the **small piston** f we are using the formula,

p=P

Or, f/a=F/A

Here we are given,

a= The area of the **small piston** = 0.1963 sq in

A= The area of the **big piston** = 6.28 sq in.

F= The force of the big piston = 1000 lb.

We have to calculate the force of the small piston = f

Now we put the values in above equation we get,

f / a = F / A

Or, f = a F/A

Or, f = [tex]\frac{0.1963 \times 1000}{6.28}[/tex]

Or, f = 31.21 lb

Now from the calculation we can say that, The force applied to the small piston (f)= 31.21 lb

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The potential energy for a mass on a spring is proportional to the square of which of these quantities?

A. mass

B. frequency

C. displacement

E. period displacement velocity

**Answer:**

C. Displacement

**Explanation:**

Jerry is riding his motorcycle at a speed of 45 m/s. He accelerates at a speed of -8 m/s² for 4seconds. How fast will he be going

**Given**

Initial speed, u=45 m/s

Acceleration

[tex]a=-\frac{8m}{s^2}[/tex]Time taken, t=4 sec

**To find**

The final speed

**Explanation**

Let the speed he be going in be v

Thus,

[tex]\begin{gathered} a=\frac{v-u}{t} \\ \Rightarrow-8=\frac{v-45}{4} \\ \Rightarrow-32+45=v \\ \Rightarrow v=13\text{ m/s} \end{gathered}[/tex]**Conclusion**

The velocity he is going in is **13 m/s.**

my opponent will say that recycling is in an issue here but that's just because they don't care about the sea turtles or other marine life affected by plastic in the ocean what is a logical fallacy

Logical fallacy: It happens when someone makes the claim that something must be true of the entire thing since it is true of some portions of the entire thing.Its basically a Bad reasoning or a bad argument against a person argument

The main three logical fallacies

AD HOMINEM

is intended at an individual rather than the argument they are making

STRAW MAN

presenting someone's point falsely or inaccurately in order to undermine it.

SLIPPERY SLOPE

supposing that a single, relatively unimportant incident will have a number of unforeseen effects and produce a noteworthy result.

The main three logical fallacies

AD HOMINEM

is intended at an individual rather than the argument they are making

STRAW MAN

presenting someone's point falsely or inaccurately in order to undermine it.

SLIPPERY SLOPE

supposing that a single, relatively unimportant incident will have a number of unforeseen effects and produce a noteworthy result.

The question is in the attached image:)

No count number what time of the 12 months it's far, the **northern and the southern hemisphere **will usually revel in a season** contrary to the other. **

Therefore, if the **northern hemisphere** has the **summer time**, then the southern hemisphere will revel in the **wintry weather season**. When we are saying contrary we additionally suggest that once it's far sp**ring season** in the northern hemisphere, then it's far **autumn season** in the southern hemisphere.

The most **important motive** for this phenomenon is the lean of the **earth on its axis**. Since the earth is tilted slightly, one of the hemispheres will usually get hold of greater and direct rays from the solar. It approach that once the **earth is tilted** in the direction of the solar, then the northern hemisphere gets direct solar rays that are skilled through us because the **summer time.**

During this time the southern hemisphere stories the **wintry weather **season. This** phenomenon maintains **alternating because the planet **revolves across the sun**. This summer time lasts for 1/2 of a 12 months, or instead 1/2 of a revolution.

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Please help!!

Question in the picture

Set of **equation** which is true for the situation is

c) 2SA = SB and 2BA=BB

**Force **applied perpendicular to the surface of an object per unit area is called pressure

SI unit of **pressure** is one newton per square meter (N/m2).

Given, length = 3 foot, width= 1 foot and height = 1 foot

1foot = 0.305m

Volume of tank A = 3*0.305*0.305*0.305

= 0.085

density of water= 1000kg/m^3

**Pressure**= 1000kg/m^3 *gravity * height

=1000kg/m^3 * 9.8 m/s^2* 0.305

=2989 N

**Force** exerted by water at bottom= P * A

= 2989*0.085

=254.065 Nm^2

similarly, for tank B

Given ,length = 6 foot, width =1 foot and height= 1foot

Volume of tank B = 6*0.305*0.305*0.305

=0.17

pressure= 1000kg/m^3 * 9.8m/s^2 * 0.305

= 2989 N

**Force **exerted by water at bottom = P*A

= 2989 * 0.17

=508.13 Nm^2

Hence proved that **pressure** exerted by tank B is twice that of tank A.

And same goes for pressure exerted on the side of the tank.

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The speed of sound traveling through a dense material is 600 m/s. If the wavelength is 15.0 m, what is the frequency of this sound?9,000 Hz80 Hz0.0025 Hz40 Hz

W0e are asked to determine the frequency of a sound given its velocity and wavelength. To do that we will use the following formula:

[tex]v=\lambda f[/tex]Where:

[tex]\begin{gathered} v=\text{ velocity} \\ \lambda=\text{ wavelength} \\ f=\text{ frequency} \end{gathered}[/tex]Now, we solve for the frequency by dividing both sides by the wavelength.

[tex]\frac{v}{\lambda}=f[/tex]Now, we substitute the values:

[tex]\frac{600\frac{m}{s}}{15m}=f[/tex]Solving the operations:

[tex]40Hz=f[/tex]Therefore, the frequency is 40 Hz.

a car accelerates from rest at 7.8 meters per second squared. how much time does it need to attain a speed of 6 meters per second?

**Answer:**

v = u + at

**Explanation:**

initial velocity = u = 0

acceleration of the car = a = 7.8 m/s^2

time taken to reach a speed of, v = 6 m/s

hence,

6 = 0 + 7.8 x t

t = 6/7.8

t = 0.77 s

A helium balloon has a volume of 8.89 liters, or 0.00889 cubic meters. Air has a density of 1.29 kilograms per cubic meter, and helium has a density of 0.177 kilograms per cubic meter.a. What is the weight of the helium inside the balloon?b. What is the buoyant force exerted on the balloon?c. What is the net force on the balloon? Neglect the weight of the rubbery material that comprises the actual balloon. . How many identical balloons would be needed to lift a child of mass 24.9 kilograms?

**Given:**

The volume of a helium balloon: 8.89 liters or 0.00889 cubic meters

The density of helium: 0.177 kilograms per cubic meters

The density of the air: 1.29 kilograms per cubic meters

**To find:**

a) weight of the helium inside the balloon.

b) the buoyant force exerted on the balloon.

c) the net force on the balloon.

d) number of identical balloons needed to lift a child of mass 24.9 kilograms.

**Explanation:**

**a)**

The expression for the density of the balloon is:

[tex]Density\text{ of helium=}\frac{Mass\text{ of helium}}{Volume\text{ of helium}}[/tex]Rearrange the above expression to find the mass of the helium.

[tex]Mass\text{ of helium=Density of helium}\times Volume\text{ of helium}[/tex]Substitute the values from the given data, we get:

[tex]\begin{gathered} Mass\text{ of helium=0.177}\frac{kg}{m^3}\times0.00889\text{ m}^3 \\ Mass\text{ of helium=0.001573 kg} \end{gathered}[/tex]Thus, the mass of the helium is 0.001573 kg.

The weight of an object is the product of its mass and gravitational acceleration. Thus, the weight of helium is

[tex]\begin{gathered} Weight\text{ of helium=mass of helium}\times g \\ \end{gathered}[/tex]here, g is the acceleration due to gravity.

Substitute the values, and we get:

[tex]\begin{gathered} Weight\text{ of helium=0.001573 kg }\times9.8\text{ }\frac{m}{s^2} \\ Weight\text{ of helium=0.01542 N} \end{gathered}[/tex]The weight of helium is 0.001542 Newtons.

**b)**

The expression for buoyant force is:

[tex]F=\rho gV[/tex]here, ρ is the density, g is the acceleration due to gravity and V is the volume.

To find the buoyant force exerted by helium on the balloon, substitute the values for helium in the above equation.

[tex]\begin{gathered} F=0.177\text{ }\frac{kg}{m^3}\times9.8\text{ }\frac{m}{s^2}\times0.00889\text{ m}^3 \\ F=0.01542\text{ }\frac{kg\cdot m}{s^2} \\ F=0.01542\text{ N} \end{gathered}[/tex]The buoyant force exerted on the baloon is 0.01542 Newtons.

**c) **

The buoyant force exerted by the balloon is 0.01542 N and it acts in an upward direction. Whereas, the other force acting on the balloon is the force due to gravity, the weight of the balloon. The weight of the balloon is 0.01542 N and is always acts in the downwards direction.

Since the magnitude of buoyant force exerted on a balloon is equal to the weight of the balloon. Both these forces are acting in opposite directions. Thus the net effect will be zero.

[tex]\begin{gathered} F_{net}=F-W \\ F_{net}=0.01542\text{ N -0.01542 N} \\ F_{net}=0\text{ N} \end{gathered}[/tex]Thus, the net force acting on the balloon is 0 Newtons.

**d)**

For a helium balloon, 1 liter of helium can lift 1 gram of mass.

The mass of the child is 24.9 kg = 24900 grams.

Thus, to lift a child of mass 24900 grams, 24900 liters of helium is required.

Now, one balloon contains 8.89 liters of helium, thus for 24900 liters of helium volume, the number of ballons required will be,

[tex]\frac{1\text{ balloon}}{n\text{ balloons}}=\frac{8.89\text{ liters}}{24900\text{ liters}}[/tex]Rearranging above equation to find n, we get

[tex]\begin{gathered} n\text{ balloons = }\frac{24900}{8.89} \\ n\text{ balloons = 2800.89} \end{gathered}[/tex]Thus, approximately 2801 helium balloons are required to lift a child of mass 24.9 kg.

**Final answer**:

**a) The weight of helium is 0.001542 Newtons.**

**b) The weight of helium is 0.001542 Newtons.**

**c) The net force acting on the balloon is 0 Newtons.**

**d) Approximately 2801 helium balloons are required to lift a child of mass 24.9 kg.**

A satellite orbiting Earth at an orbital radius r has a velocity v. Which represents the velocity if the satellite is moved to an orbital radius of 5r?(1 point)

The** equation **which represent the **velocity**, if the satellite is moved to an **orbital radius** of 5r is **V = V/**[tex]\sqrt\\5[/tex].

**Orbital velocity** or orbital speed is the minimum** velocity** a body must maintain to stay in an orbit. Due to the inertia of a moving body, the body has the tendency to move on in a** straight path**.

It is given that the** radius** is **5r**

To find out the equation which represent the velocity if the satellite is moved to an **orbital radius** of 5r.

Mathematically, the **orbital velocity** is calculated by the formula:

**V = **[tex]\sqrt{GM}[/tex]**/r**

where, V = orbital velocity,

G = gravitational constant

M = mass of a satellite

r = radius

Substituting the value of** r **in this **equation**, we have:

V = [tex]\sqrt{GM}[/tex]/r

V = 1/ [tex]\sqrt{5}[/tex] × [tex]\sqrt{GM}[/tex]/r

V = [tex]\sqrt{GM}[/tex]/r

Therefore,

V = 1/ [tex]\sqrt{5}[/tex] × V

**V = V/**[tex]\sqrt{5}[/tex]

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A 150 pound man runs up a stairway 20 feet above ground level in 15s. How much work did the man do?

Given:

h = height = 20 ft = 6.096 m

m = 150 pound = 68.0389 kg

time = 15 s

g= 9.8 m/s^2

Potential energy = mgh = (68.0389 ) (9.8 ) (6.096 ) = **4,064.7 J **

**Work done = 4,064.7 J **

The highest freefall jump on record is from a height of almost 38,000 m. At this height, the acceleration of gravity is slightly weaker than the accelera

of gravity on the surface of Earth. Although the skydiver used a parachute to slow himself down below a certain altitude, how would the increasing

acceleration impact his velocity and rate of displacement covered?

BIU

S2

X

Increasing his acceleration will impact his velocity and rate of displacement covered in that as the **speed **increases due to the increased rate of acceleration, the rate of **air resistance **also increases.

**Air resistance **is a force created by air. When an item moves through the air, the force operates in the **opposite direction**.

When a diver descends, the force of **air** **resistance **acts to counteract the force of gravity. As the skydiver falls faster and faster, the quantity of air resistance grows until it equals the magnitude of **gravity's force**.

A balance of forces is achieved when the **force of gravity** equals the **force of air resistance,** and the skydiver no longer accelerates. The skydiver reaches what is known as terminal velocity.

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a javelin is thrown at 28.5m/s from flat ground at a 43.2 degree angle. How long does it take to reach its maximum height? IN SECONDS

The **time take****n** for the javelin thrown at 28.5 m/s from flat ground at a 43.2 degree angle to reach the **maximum** height is 2.0 s

From projectile motion, we understand that the **time taken** to reach **maximum** height is given as:

t = uSineθ / g

Where

t is the time to reach maximum heightu is the initial velocity θ is the angle of projectiong is acceleration due to gravityNow, using the above formua, we can obtain the **time taken** for the javelin to reach the **maximum** height as follow:

Initial velocity (u) = 28.5 m/s

Angle of projection (θ) = 43.2 degrees

Acceleration due to gravity (g) = 9.8 m/s²

Time taken to reach the peak (t) = ?

t = uSineθ / g

t = (28.5 × Sine 43.2) / 9.8

t = 2.0 s

Thus, the **time taken** to reach **maximum** height is 2.0 s

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Please help me understand this I go to get it

**Answer:**

**Vx = 150 * cos 53 = 90.3 m/s horizontal speed**

**Vy = 150 * sin 53 = 120 m/s vertical speed**

**t1 = 120 / 9.8 = 12.2 sec time to reach vertical height (vy = 0 at apex)**

**H1 = 1/2 g t^2 = 9.8 / 2 * 12.2^2 = 729 m height risen above cliff**

**729 + 405 = 1134 m total height above striking point**

**H = 1/2 g T^2 where T is time to fall 1134 m**

**T = (2 * 1134 / 9.8)^1/2 = 15.2 sec**

**T + t1 = 15.2 + 12.2 = 27.4 sec total time in air**

**Sx = Vx * 27.4 = 90.3 * 27.4 = 2470 m total horizontal distance**

A rectangular coil of dimensions 5.40cm x 8.50cm consists of 25 turns of wire. The

coil carries a current of 15.0mA.

(a) Calculate the magnitude of its magnetic moment [5]

(b) Suppose a magnetic field of magnitude 0.35T is applied parallel to the plane of

the loop. What is the magnitude of the torque acting on the loop? [5]

(c) Calculate the magnitude of the torque on the coil when 0.35T magnetic field

makes angles of 600 and 00 with μ. [5]

(d) Show that the units A.m2.T Reduce to N.m. [

A. **Magnetic moment **will be 17.212*[tex]10^{-4} A-m^{2}[/tex].

B. **Torque** will be 6.024* [tex]10^{-4} N-m[/tex]

C. 9f B = 35 make angle 60°

then T = 25 × 15,×10³× (5.40x8.50) ×10 × 0.35 Sm 60°

5.22x[tex]10^{-4}[/tex] n-m

of ∅ = 0° t = 0 ∵ sm0 = 0

As it is a Torque NIAB

= Am². Tesla

=** N-3.**

**Rectangular coils** have four sides and slightly rounded edges and are generally cheaper to **manufacture**. Importantly they cannot handle radial forces more effectively than their circular counterparts and most lose their rectangular shape during short circuits. A rectangular coil carrying current is placed in a uniform magnetic field. The direction in which the spool is difficult to rotate.

The **motor works** on the principle that when a **rectangular coil** is placed in a magnetic field and an electric current is applied, a force acts on the coil, causing it to rotate continuously. A toroidal transformer is a type of electrical transformer that consists of a toroidal or annular core. Its primary and secondary windings are wound across the surface of the torus core and separated by insulating material. This configuration minimizes flux leakage.

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If Hubble's constant had a value of 95 km/s/Mpc, what would be the age of the Universe?

The **age** of the** Universe** is 13.8 ± 0.1 billion years.

The ‘**hubble constant**, h0’ is used to determine the size of the **universe. **It is a measurement that is used in describing the** universe's **expansion. It was a constant introduced by **Edwin Hubble**. He found out that the **farther **the distance of the** galaxies **from the** Earth,** the faster they would appear to be moving.

One of the most** important **numbers in **cosmology** **Hubble's constant ** because it is needed to estimate the** size** and **age** of the universe which is 13.8 ± 0.1 billion years.

The **age** of the universe using **Hubble's constant** which is 13.8 ± 0.1 billion years.

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Divya and Melissa go to a restaurant. They decide to try something they have not eaten before and order chicken sandwiches with sriracha sauce. Both Divya and Melissa find it difficult to eat the sandwiches as they feel the sandwiches are too spicy. Which of the following processes help them identify the spicy taste?

The processes that help Divya and Melissa **identify the spicy taste **of the chicken sandwiches with sriracha sauce is sensation.

**Sensation **is the process in which one feels something after being in physical contact with something. As Divya and Melissa eats the chicken sandwiches with sriracha sauce, their senses tells that the food is spicy.

Acculturation is the process in which one **adopts and adjusts** to a new cultural environment. Homogenization is the process in which two non-soluble liquids are mixed uniformly. Adaptation is the process of changing one's trait to a new environment.

Therefore, the processes that helps them identify the spicy taste is **sensation**.

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A shopper in a supermarket pushes a loaded cart with a horizontal force of 14 N. The cart

has a mass of 32 kg.

The acceleration of gravity is 9.8 m/s

2

.

Disregarding friction, how far will the cart

move in 4 s, starting from rest?

Answer in units of m.

**Answer:**

ΔS = 3.5 m

**Explanation:**

First, apply the 2º Newton's Law to find the resulting acceleration.

∑**F** = m × **a**

F = m × a

14 = 32 × a

a = 14 /32 = 7/16

a = 0.4375 m/s²

Then, we must apply the equation of accelerated movement:

ΔS = V₀*t + (1/2)*a*t²

Starting from the rest and using the value of acceleration:

ΔS = 0*4 + (1/2)*(0.4375)*(4)²

ΔS = (1/2)*(0.4375)*(16)

ΔS = 3.5 m

an optical instrument consist of two lenses .if the object distance for lens 1 is 12cm then the image distance is 36cm.if the height of the object for lens 2 is 5cm then the image height is 2.5cm. evaluate the combined magnification of the two lenses

The magnification of first lens can be given as,

[tex]m_1=-\frac{v_1}{u_1}[/tex]Here, m1 is the magnification of first lens, v1 is the distance of image from first lens and u1 is the distance of object from first lens.

Substitute the known values in the equation,

[tex]\begin{gathered} m_1=-\frac{36\text{ cm}}{12\text{ cm}} \\ =-3 \end{gathered}[/tex]The magnification of second lens can be given as,

[tex]m_2=-\frac{v_2}{u_2}[/tex]Here, m2 is the magnification of second lens, v2 is the distance of image from second lens and u2 is the distance of object from second lens.

Substitute the known values in the equation,

[tex]\begin{gathered} m_2=-\frac{2.5\text{ cm}}{5\text{ cm}} \\ =-0.5 \end{gathered}[/tex]The combined magnification of two lenses can be given as,

[tex]m=m_1m_2[/tex]Substitute the known values,

[tex]\begin{gathered} m=(-3)(-0.5) \\ =1.5 \end{gathered}[/tex]**Thus, the combined magnification of two lenses is 1.5.**

Given a metal loop of wire with an area of 400 square centimeters and a magnetic field of 0.0875 Tesla through it. If the magnetic field is constant everywhere through the loop then which of these is the magnetic flux through the loop in SI units? [4. Define magnetic flux] 0.00350 0.0140 286

We will have that the value will be:

[tex]\Phi=(0.04m^2)(0.0875T)\Rightarrow\Phi=0.00350m^2T[/tex]can you help me with this ap physics class from my school

We know that the components of any vector along the x and y axes are given by:

[tex]\begin{gathered} v_x=v\cos\theta \\ v_y=v\sin\theta \\ \text{ where:} \\ v\text{ is the magnitude of the vector.} \\ \theta\text{ is the angle from the }x\text{ axis to the vector. } \end{gathered}[/tex]In this case we know the tha magnitude of the vector is 6.96 m/s; we also know that the angle from the x-axis to the vector is 51.5° (the sum of angles θ and the 26.5° angle); then we have:

[tex]\begin{gathered} v_x=6.96\cos51.5=4.33 \\ v_y=6.96\sin51.5=5.45 \end{gathered}[/tex]**Therefore, the components of the vector are:**

At the beginning of a new school term, a

student moves a box of books by attaching a

rope to the box and pulling with a force of

F = 84.4 N at an angle of 64°, as shown in the

figure.

The acceleration of gravity is 9.8 m/s².

The box of books has a mass of 14 kg and

the coefficient of kinetic friction between the

bottom of the box and the floor is 0.3.

64°

14 kg

p=0.3

What is the acceleration of the box?

Answer in units of m/s².

**Answer:**

1.22 m/s² (3 s.f.)

**Explanation:**

Draw a **diagram **modelling the given situation (see attachment).

Friction always acts in the opposite direction to motion (or potential motion).R = Normal Reaction (perpendicular to the plane).Weight = mg.

Given values:

Pulling force = 84.4 NMass (m) = 14 kgAcceleration due to gravity (g) = 9.8 m/s²Coefficient of friction (μ) = 0.3As the **pulling force** is at an **angle **to the plane (ground), **resolve **the force into **components **parallel and perpendicular to the plane.

Resolving vertically (↑) to find the **Normal Reaction**, R:

[tex]\begin{aligned}\implies R+82.2 \sin 64^{\circ}&=14g\\R&=14g-82.2 \sin 64^{\circ}\end{aligned}[/tex]

The **frictional force** takes its **maximum value** when an object starts to move (or is on the point of moving):

[tex]\boxed{F_{\text{max}}= \mu R}[/tex]

where R is the Normal Reaction and μ is the coefficient of friction.

Using F = μR to find the **Frictional Force**, F:

[tex]\begin{aligned}\implies F &= 0.3\left(14g-82.2 \sin 64^{\circ}\right)\\ & =0.3\left(14(9.8)-82.2 \sin 64^{\circ}\right)\\& =0.3\left(137.2-82.2 \sin 64^{\circ}\right)\\ & = 41.16-24.66\sin 64^{\circ}\end{aligned}[/tex]

**Newton's second law **states that the overall **resultant force** acting on a body is equal to the **mass **of the body **multiplied **by the body’s **acceleration**:

[tex]\boxed{F_{\text{net}}=ma}[/tex]

Resolving horizontally (→) using **Newton's second law of motion** to find acceleration:

[tex]\begin{aligned}\textsf{Using} \quad F_{\text{net}}&=ma\\\\\implies 82.2 \cos64^{\circ}-(41.16-24.66\sin 64^{\circ})&=14a\\17.0383694...&=14a\\a&=\dfrac{17.0383694...}{14}\\a&=1.21702638...\\a&=1.22\;\sf m/s^2\;(3\;s.f.)\end{aligned}[/tex]

Therefore, the **acceleration **of the box is 1.22 m/s² (3 s.f.).

In your readings you learned that “correlation does not imply causality.” Which of the following is the best interpretation of this statement?

A. Just because there is a relationship between two behaviors does not mean that one causes the other

B. Many factors influence the relationship between two behaviors.

C. A relationship between two behaviors does not mean that one or both behaviors are testable.

D. Correlated behaviors are the result of operational conditioning.

SOMEONE PLEASE HELP!

Just because there is a **relationship **between two **behaviors **does not mean that one causes the other. Option A.

**Natural observation** is a research method that observes objects in their natural environment. This approach is commonly used by psychologists and other **social scientists**. It is a process of deep reflection, questioning, and evidence evaluation. A study in which researchers look for relationships between people's demographic neighborhood and their level of prejudice.

**Psychologists** use this because it is the most objective method known to produce reliable insights. The science of **behavior** and mental processes. It attempts to describe and explain aspects of human thinking feeling perception and behavior. Naturalistic observation is a method of observation that involves observing people's behavior in environments in which they normally occur. Laboratory Observation observing behavior in a more artificial environment focusing on a small number of carefully defined behaviors.

Learn more about **Correlated behaviors** here:-https://brainly.com/question/15295264

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A vector is 148 m long and

points in a -96.3 degree

direction.

Find the x-component of the

vector.

The **x-component** of the vector is determined as **-16.24 m.**

The **x-component** of a vector is the vector component measured along x - direction. It is the vector acting in the x-coordinate.

The magnitude of **x -component** of a vector is given by the following formula as shown below;

Vₓ = V cosθ

where;

Vₓ is the x - component of the vectorV is the magnitude of the vector = 148 mθ is the angle of the vector = -96.3 degreesVₓ = 148 m x cos(-96.3)

Vₓ = -16.24 m

Learn more about **x - component of a vector** here: https://brainly.com/question/28002904

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**Answer:**

Y= -147

X= -16.24

**Explanation:**

10. The value of the 8th term is 78.The sequence is increasing by 10 at each step.Explicit equation: y = 10x - 2Recursive: now = previous term + 10Find the 9th term.Explanation:
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